是否有可能使用标准属性语法将块作为属性?

ARC有什么变化吗?


下面是一个如何完成这样一个任务的例子:

#import <Foundation/Foundation.h>
typedef int (^IntBlock)();

@interface myobj : NSObject
{
    IntBlock compare;
}

@property(readwrite, copy) IntBlock compare;

@end

@implementation myobj

@synthesize compare;

- (void)dealloc 
{
   // need to release the block since the property was declared copy. (for heap
   // allocated blocks this prevents a potential leak, for compiler-optimized 
   // stack blocks it is a no-op)
   // Note that for ARC, this is unnecessary, as with all properties, the memory management is handled for you.
   [compare release];
   [super dealloc];
}
@end

int main () {
    @autoreleasepool {
        myobj *ob = [[myobj alloc] init];
        ob.compare = ^
        {
            return rand();
        };
        NSLog(@"%i", ob.compare());
        // if not ARC
        [ob release];
    }

    return 0;
}

现在,如果你需要改变比较的类型,唯一需要改变的是typedef int (^IntBlock)()。如果你需要传递两个对象给它,将其更改为:typedef int (^IntBlock)(id, id),并将你的块更改为:

^ (id obj1, id obj2)
{
    return rand();
};

2012年3月12日编辑:

对于ARC,不需要进行特定的更改,因为ARC将为您管理这些块,只要它们被定义为副本。你也不需要在析构函数中将属性设置为nil。

如需更多阅读,请查看以下文件: http://clang.llvm.org/docs/AutomaticReferenceCounting.html


@property (nonatomic, copy) void (^simpleBlock)(void);
@property (nonatomic, copy) BOOL (^blockWithParamter)(NSString *input);

如果你要在几个地方重复同一个块,请使用类型def

typedef void(^MyCompletionBlock)(BOOL success, NSError *error);
@property (nonatomic) MyCompletionBlock completion;

为了子孙后代/完整性的缘故,这里有两个完整的例子,如何实现这种荒谬的多功能“做事方式”。@Robert的回答非常简洁和正确,但在这里我还想展示实际“定义”块的方法。

@interface       ReusableClass : NSObject
@property (nonatomic,copy) CALayer*(^layerFromArray)(NSArray*);
@end

@implementation  ResusableClass
static  NSString const * privateScope = @"Touch my monkey.";

- (CALayer*(^)(NSArray*)) layerFromArray { 
     return ^CALayer*(NSArray* array){
        CALayer *returnLayer = CALayer.layer
        for (id thing in array) {
            [returnLayer doSomethingCrazy];
            [returnLayer setValue:privateScope
                         forKey:@"anticsAndShenanigans"];
        }
        return list;
    };
}
@end

傻吗?是的。有用吗?地狱啊。这里有一个不同的,“更原子”的方式来设置属性。还有一个非常有用的类……

@interface      CALayoutDelegator : NSObject
@property (nonatomic,strong) void(^layoutBlock)(CALayer*);
@end

@implementation CALayoutDelegator
- (id) init { 
   return self = super.init ? 
         [self setLayoutBlock: ^(CALayer*layer){
          for (CALayer* sub in layer.sublayers)
            [sub someDefaultLayoutRoutine];
         }], self : nil;
}
- (void) layoutSublayersOfLayer:(CALayer*)layer {
   self.layoutBlock ? self.layoutBlock(layer) : nil;
}   
@end

这说明了通过访问器(尽管在init中,这是一个有争议的冒险实践..)设置block属性与第一个例子的“非原子”“getter”机制。在任何一种情况下,“硬编码”实现总是可以被覆盖,每个实例。一个拉. .

CALayoutDelegator *littleHelper = CALayoutDelegator.new;
littleHelper.layoutBlock = ^(CALayer*layer){
  [layer.sublayers do:^(id sub){ [sub somethingElseEntirely]; }];
};
someLayer.layoutManager = littleHelper;

也. .如果你想在一个类别中添加一个block属性…比如你想要使用Block而不是一些老式的目标/动作“action”…你可以使用相关的值。关联这些块。

typedef    void(^NSControlActionBlock)(NSControl*); 
@interface       NSControl            (ActionBlocks)
@property (copy) NSControlActionBlock  actionBlock;    @end
@implementation  NSControl            (ActionBlocks)

- (NSControlActionBlock) actionBlock { 
    // use the "getter" method's selector to store/retrieve the block!
    return  objc_getAssociatedObject(self, _cmd); 
} 
- (void) setActionBlock:(NSControlActionBlock)ab {

    objc_setAssociatedObject( // save (copy) the block associatively, as categories can't synthesize Ivars.
    self, @selector(actionBlock),ab ,OBJC_ASSOCIATION_COPY);
    self.target = self;                  // set self as target (where you call the block)
    self.action = @selector(doItYourself); // this is where it's called.
}
- (void) doItYourself {

    if (self.actionBlock && self.target == self) self.actionBlock(self);
}
@end

现在,当你做一个按钮,你不需要设置一些IBAction戏剧..只需要在创建时将工作关联起来……

_button.actionBlock = ^(NSControl*thisButton){ 

     [doc open]; [thisButton setEnabled:NO]; 
};

这种模式可以反复应用到Cocoa API中。使用属性将代码的相关部分更紧密地结合在一起,消除令人费解的委托范例,并利用对象的强大功能,而不仅仅是充当愚蠢的“容器”。


@ property(副本)无效

@property (copy)void (^doStuff)(void);

实际的苹果文档,它精确地说明了使用什么:

苹果doco。

你的。h文件:

// Here is a block as a property:
//
// Someone passes you a block. You "hold on to it",
// while you do other stuff. Later, you use the block.
//
// The property 'doStuff' will hold the incoming block.

@property (copy)void (^doStuff)(void);

// Here's a method in your class.
// When someone CALLS this method, they PASS IN a block of code,
// which they want to be performed after the method is finished.

-(void)doSomethingAndThenDoThis:(void(^)(void))pleaseDoMeLater;

// We will hold on to that block of code in "doStuff".

你的。m文件:

 -(void)doSomethingAndThenDoThis:(void(^)(void))pleaseDoMeLater
    {
    // Regarding the incoming block of code, save it for later:
    self.doStuff = pleaseDoMeLater;
  
    // Now do other processing, which could follow various paths,
    // involve delays, and so on. Then after everything:
    [self _alldone];
    }

-(void)_alldone
    {
    NSLog(@"Processing finished, running the completion block.");
    // Here's how to run the block:
    if ( self.doStuff != nil )
       self.doStuff();
    }

注意过时的示例代码。

对于现代(2014+)系统,这是正确的和文档化的方法。


您可以遵循下面的格式,并在类中使用testingObjectiveCBlock属性。

typedef void (^testingObjectiveCBlock)(NSString *errorMsg);

@interface MyClass : NSObject
@property (nonatomic, strong) testingObjectiveCBlock testingObjectiveCBlock;
@end

更多信息请看这里


Disclamer

这并不是“好的答案”,因为这个问题明确地要求objective - c。苹果在WWDC14上介绍了Swift,我想分享一下在Swift中使用block(或闭包)的不同方式。

你好,迅速

在Swift中,你有很多方法来传递一个相当于函数的块。

我找到了三个。

为了理解这一点,我建议你在操场上测试这一小段代码。

func test(function:String -> String) -> String
{
    return function("test")
}

func funcStyle(s:String) -> String
{
    return "FUNC__" + s + "__FUNC"
}
let resultFunc = test(funcStyle)

let blockStyle:(String) -> String = {s in return "BLOCK__" + s + "__BLOCK"}
let resultBlock = test(blockStyle)

let resultAnon = test({(s:String) -> String in return "ANON_" + s + "__ANON" })


println(resultFunc)
println(resultBlock)
println(resultAnon)

Swift,针对闭包进行了优化

由于Swift针对异步开发进行了优化,苹果在闭包方面投入了更多精力。 首先,函数签名可以被推断出来,所以你不必重写它。

通过数字访问参数

let resultShortAnon = test({return "ANON_" + $0 + "__ANON" })

带有命名的参数推断

let resultShortAnon2 = test({myParam in return "ANON_" + myParam + "__ANON" })

后关闭

只有当block是最后一个参数时,这种特殊情况才有效,它被称为尾随闭包

下面是一个例子(与推断签名合并以显示Swift的能力)

let resultTrailingClosure = test { return "TRAILCLOS_" + $0 + "__TRAILCLOS" }

最后:

使用所有这些功能,我要做的是混合尾随闭包和类型推断(为可读性而命名)

PFFacebookUtils.logInWithPermissions(permissions) {
    user, error in
    if (!user) {
        println("Uh oh. The user cancelled the Facebook login.")
    } else if (user.isNew) {
        println("User signed up and logged in through Facebook!")
    } else {
        println("User logged in through Facebook!")
    }
}

你好,迅速

补充@Francescu的回答。

添加额外参数:

func test(function:String -> String, param1:String, param2:String) -> String
{
    return function("test"+param1 + param2)
}

func funcStyle(s:String) -> String
{
    return "FUNC__" + s + "__FUNC"
}
let resultFunc = test(funcStyle, "parameter 1", "parameter 2")

let blockStyle:(String) -> String = {s in return "BLOCK__" + s + "__BLOCK"}
let resultBlock = test(blockStyle, "parameter 1", "parameter 2")

let resultAnon = test({(s:String) -> String in return "ANON_" + s + "__ANON" }, "parameter 1", "parameter 2")


println(resultFunc)
println(resultBlock)
println(resultAnon)

当然,您可以使用块作为属性。但是要确保它们被声明为@property(copy)。例如:

typedef void(^TestBlock)(void);

@interface SecondViewController : UIViewController
@property (nonatomic, copy) TestBlock block;
@end

在MRC中,捕获上下文变量的块分配在堆栈中;当堆栈帧被销毁时,它们将被释放。如果复制了它们,将在堆中分配一个新的块,该块可以在堆栈帧弹出后执行。