下面的代码只删除它在web目录中的第一个文件。我想删除web目录中的所有文件和文件夹，并保留web目录。我该怎么做呢?
- name: remove web dir contents
file: path='/home/mydata/web/{{ item }}' state=absent
with_fileglob:
- /home/mydata/web/*
注意:我已经尝试了rm -rf使用命令和shell，但他们不工作。也许我用错了。
任何正确方向上的帮助都将不胜感激。
我使用ansible 2.1.0.0
当前回答
- name: Files to delete search
find:
paths: /home/mydata/web/
file_type: any
register: files_to_delete
- name: Deleting files to delete
file:
path: '{{ item.path }}'
state: absent
with_items: "{{ files_to_delete.files }}"
其他回答
下面对我很有用，
- name: Ansible delete html directory
file:
path: /var/www/html
state: directory
- name: delete old data and clean cache
file:
path: "{{ item[0] }}"
state: "{{ item[1] }}"
with_nested:
- [ "/data/server/{{ app_name }}/webapps/", "/data/server/{{ app_name }}/work/" ]
- [ "absent", "directory" ]
ignore_errors: yes
我喜欢下面的解决方案:
- name: remove web dir contents
command:
cmd: "find . -path '*/*' -delete -print"
chdir: "/home/mydata/web/"
register: web_files_list
changed_when: web_files_list.stdout | length > 0
因为它是:
简单的 幂等 快
如果你使用Ansible >= 2.3(文件和dirs之间的区别不再需要了)，只是一个简单的复制和粘贴ThorSummoners的模板。
- name: Collect all fs items inside dir
find:
path: "{{ target_directory_path }}"
hidden: true
file_type: any
changed_when: false
register: collected_fsitems
- name: Remove all fs items inside dir
file:
path: "{{ item.path }}"
state: absent
with_items: "{{ collected_fsitems.files }}"
when: collected_fsitems.matched|int != 0
- name: Files to delete search
find:
paths: /home/mydata/web/
file_type: any
register: files_to_delete
- name: Deleting files to delete
file:
path: '{{ item.path }}'
state: absent
with_items: "{{ files_to_delete.files }}"
