我们如何通过javascript窗口打开一个弹出窗口的中心。打开功能上的屏幕中心变量,以当前选择的屏幕分辨率?


当前回答

我的ES6 JavaScript版本。 工作良好的铬和铬双屏幕设置。

function openCenteredWindow({url, width, height}) {
    const pos = {
        x: (screen.width / 2) - (width / 2),
        y: (screen.height/2) - (height / 2)
    };

    const features = `width=${width} height=${height} left=${pos.x} top=${pos.y}`;

    return window.open(url, '_blank', features);
}

例子

openCenteredWindow({
    url: 'https://stackoverflow.com/', 
    width: 500, 
    height: 600
}).focus();

其他回答

来源:http://www.nigraphic.com/blog/java-script/how-open-new-window-popup-center-screen

function PopupCenter(pageURL, title,w,h) {
  var left = (screen.width/2)-(w/2);
  var top = (screen.height/2)-(h/2);
  var targetWin = window.open (pageURL, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
  return targetWin;
} 

基于Facebook的,但使用媒体查询而不是用户代理正则表达式来计算是否有足够的空间(有一些空间)弹出窗口,否则将全屏。不管怎样,Tbh在移动设备上弹出的窗口会作为新标签打开。

function popupCenter(url, title, w, h) {
  const hasSpace = window.matchMedia(`(min-width: ${w + 20}px) and (min-height: ${h + 20}px)`).matches;
  const isDef = v => typeof v !== 'undefined';
  const screenX = isDef(window.screenX) ? window.screenX : window.screenLeft;
  const screenY = isDef(window.screenY) ? window.screenY : window.screenTop;
  const outerWidth = isDef(window.outerWidth) ? window.outerWidth : document.documentElement.clientWidth;
  const outerHeight = isDef(window.outerHeight) ? window.outerHeight : document.documentElement.clientHeight - 22;
  const targetWidth = hasSpace ? w : null;
  const targetHeight = hasSpace ? h : null;
  const V = screenX < 0 ? window.screen.width + screenX : screenX;
  const left = parseInt(V + (outerWidth - targetWidth) / 2, 10);
  const right = parseInt(screenY + (outerHeight - targetHeight) / 2.5, 10);
  const features = [];

  if (targetWidth !== null) {
    features.push(`width=${targetWidth}`);
  }

  if (targetHeight !== null) {
    features.push(`height=${targetHeight}`);
  }

  features.push(`left=${left}`);
  features.push(`top=${right}`);
  features.push('scrollbars=1');

  const newWindow = window.open(url, title, features.join(','));

  if (window.focus) {
    newWindow.focus();
  }

  return newWindow;
}

我有一个问题与中心的弹出窗口在外部显示器和窗口。screenX和window。screenY分别为负值(-1920,-1200)。我已经尝试了上述所有建议的解决方案,它们在主显示器上运行良好。我想离开

左右边距为200px 顶部和底部的边缘为150像素

以下是对我有效的方法:

 function createPopupWindow(url) {
    var height = screen.height;
    var width = screen.width;
    var left, top, win;

    if (width > 1050) {
        width = width - 200;
    } else {
        width = 850;
    }

    if (height > 850) {
        height = height - 150;
    } else {
        height = 700;
    }

    if (window.screenX < 0) {
        left = (window.screenX - width) / 2;
    } else {
        left = (screen.width - width) / 2;
    }

    if (window.screenY < 0) {
        top = (window.screenY + height) / 4;
    } else {
        top = (screen.height - height) / 4;
    }

    win=window.open( url,"myTarget", "width="+width+", height="+height+",left="+left+",top="+top+"menubar=no, status=no, location=no, resizable=yes, scrollbars=yes");
    if (win.focus) {
        win.focus();
    }
}

.center { 左:50%; max-width: 350 px; 填充:15 px; text-align:中心; 位置:相对; 变换:translateX (-50%); -moz-transform: translateX (-50%); -webkit-transform: translateX (-50%); -ms-transform: translateX (-50%); -o-transform: translateX (-50%); }

你可以使用css来做到这一点,只要给元素下面的属性被放置在弹出窗口的中心

element{

position:fixed;
left: 50%;
top: 50%;
-ms-transform: translate(-50%,-50%);
-moz-transform:translate(-50%,-50%);
-webkit-transform: translate(-50%,-50%);
 transform: translate(-50%,-50%);

}