试着这样做:

function popupwindow(url, title, w, h) {
  var left = (screen.width/2)-(w/2);
  var top = (screen.height/2)-(h/2);
  return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
} 

(这是在2020年发布的)

这是CrazyTim回答的延伸

还可以将宽度设置为动态大小的百分比(或比率)。 绝对尺寸仍然被接受。

function popupWindow(url, title, w='75%', h='16:9', opts){
    // sort options
    let options = [];
    if(typeof opts === 'object'){
        Object.keys(opts).forEach(function(value, key){
            if(value === true){value = 'yes';}else if(value === false){value = 'no';}
            options.push(`${key}=${value}`);
        });
        if(options.length){options = ','+options.join(',');}
        else{options = '';}
    }else if(Array.isArray(opts)){
        options = ','+opts.join(',');
    }else if(typeof opts === 'string'){
        options = ','+opts;
    }else{options = '';}

    // add most vars to local object (to shorten names)
    let size = {w: w, h: h};
    let win = {w: {i: window.top.innerWidth, o: window.top.outerWidth}, h: {i: window.top.innerHeight, o: window.top.outerHeight}, x: window.top.screenX || window.top.screenLeft, y: window.top.screenY || window.top.screenTop}

    // set window size if percent
    if(typeof size.w === 'string' && size.w.endsWith('%')){size.w = Number(size.w.replace(/%$/, ''))*win.w.o/100;}
    if(typeof size.h === 'string' && size.h.endsWith('%')){size.h = Number(size.h.replace(/%$/, ''))*win.h.o/100;}

    // set window size if ratio
    if(typeof size.w === 'string' && size.w.includes(':')){
        size.w = size.w.split(':', 2);
        if(win.w.o < win.h.o){
            // if height is bigger than width, reverse ratio
            size.w = Number(size.h)*Number(size.w[1])/Number(size.w[0]);
        }else{size.w = Number(size.h)*Number(size.w[0])/Number(size.w[1]);}
    }
    if(typeof size.h === 'string' && size.h.includes(':')){
        size.h = size.h.split(':', 2);
        if(win.w.o < win.h.o){
            // if height is bigger than width, reverse ratio
            size.h = Number(size.w)*Number(size.h[0])/Number(size.h[1]);
        }else{size.h = Number(size.w)*Number(size.h[1])/Number(size.h[0]);}
    }

    // force window size to type number
    if(typeof size.w === 'string'){size.w = Number(size.w);}
    if(typeof size.h === 'string'){size.h = Number(size.h);}

    // keep popup window within padding of window size
    if(size.w > win.w.i-50){size.w = win.w.i-50;}
    if(size.h > win.h.i-50){size.h = win.h.i-50;}

    // do math
    const x = win.w.o / 2 + win.x - (size.w / 2);
    const y = win.h.o / 2 + win.y - (size.h / 2);
    return window.open(url, title, `width=${size.w},height=${size.h},left=${x},top=${y}${options}`);
}

用法:

// width and height are optional (defaults: width = '75%' height = '16:9')
popupWindow('https://www.google.com', 'Title', '75%', '16:9', {/* options (optional) */});

// options can be an object, array, or string

// example: object (only in object, true/false get replaced with 'yes'/'no')
const options = {scrollbars: false, resizable: true};

// example: array
const options = ['scrollbars=no', 'resizable=yes'];

// example: string (same as window.open() string)
const options = 'scrollbars=no,resizable=yes';

它在Firefox中运行得非常好。 只需将顶部变量更改为任何其他名称，然后再试一次

        var w = 200;
        var h = 200;
        var left = Number((screen.width/2)-(w/2));
        var tops = Number((screen.height/2)-(h/2));

window.open("templates/sales/index.php?go=new_sale", '', 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+tops+', left='+left);

这种混合解决方案对我来说很有效，无论是单屏还是双屏设置

function popupCenter (url, title, w, h) {
    // Fixes dual-screen position                              Most browsers      Firefox
    const dualScreenLeft = window.screenLeft !== undefined ? window.screenLeft : window.screenX;
    const dualScreenTop = window.screenTop !== undefined ? window.screenTop : window.screenY;
    const left = (window.screen.width/2)-(w/2) + dualScreenLeft;
    const top = (window.screen.height/2)-(h/2) + dualScreenTop;
    return window.open(url, title, 'toolbar=no, location=no, directories=no, status=no, menubar=no, scrollbars=no, resizable=no, copyhistory=no, width='+w+', height='+h+', top='+top+', left='+left);
}

我有一个问题与中心的弹出窗口在外部显示器和窗口。screenX和window。screenY分别为负值(-1920，-1200)。我已经尝试了上述所有建议的解决方案，它们在主显示器上运行良好。我想离开

左右边距为200px 顶部和底部的边缘为150像素

以下是对我有效的方法:

 function createPopupWindow(url) {
    var height = screen.height;
    var width = screen.width;
    var left, top, win;

    if (width > 1050) {
        width = width - 200;
    } else {
        width = 850;
    }

    if (height > 850) {
        height = height - 150;
    } else {
        height = 700;
    }

    if (window.screenX < 0) {
        left = (window.screenX - width) / 2;
    } else {
        left = (screen.width - width) / 2;
    }

    if (window.screenY < 0) {
        top = (window.screenY + height) / 4;
    } else {
        top = (screen.height - height) / 4;
    }

    win=window.open( url,"myTarget", "width="+width+", height="+height+",left="+left+",top="+top+"menubar=no, status=no, location=no, resizable=yes, scrollbars=yes");
    if (win.focus) {
        win.focus();
    }
}

你可以使用css来做到这一点，只要给元素下面的属性被放置在弹出窗口的中心

element{

position:fixed;
left: 50%;
top: 50%;
-ms-transform: translate(-50%,-50%);
-moz-transform:translate(-50%,-50%);
-webkit-transform: translate(-50%,-50%);
 transform: translate(-50%,-50%);

}