这里有一个解决方案，你谁不能访问“数字格式”或“字符串。Format”(在框架中使用有限版本的Java)。希望对大家有用。

number= 123456789;
thousandsSeparator=",";
myNumberString=number.toString();   
numberLength=myNumberString.length;
howManySeparators=Math.floor((numberLength-1)/3)
formattedString=myNumberString.substring(0,numberLength-(howManySeparators*3))
while (howManySeparators>0)    {
formattedString=formattedString+thousandsSeparator+myNumberString.substring(numberLength-(howManySeparators*3),numberLength-((howManySeparators-1)*3));
howManySeparators=howManySeparators-1;    }

formattedString

int bigNumber = 1234567;
String formattedNumber = String.format("%,d", bigNumber);

 int value = 35634646;
 DecimalFormat myFormatter = new DecimalFormat("#,###");
 String output = myFormatter.format(value);
 System.out.println(output);

输出:35634646

这里有一个解决方案，你谁不能访问“数字格式”或“字符串。Format”(在框架中使用有限版本的Java)。希望对大家有用。

number= 123456789;
thousandsSeparator=",";
myNumberString=number.toString();   
numberLength=myNumberString.length;
howManySeparators=Math.floor((numberLength-1)/3)
formattedString=myNumberString.substring(0,numberLength-(howManySeparators*3))
while (howManySeparators>0)    {
formattedString=formattedString+thousandsSeparator+myNumberString.substring(numberLength-(howManySeparators*3),numberLength-((howManySeparators-1)*3));
howManySeparators=howManySeparators-1;    }

formattedString

System.out.println(NumberFormat.getNumberInstance(Locale.US).format(35634646));

Output: 35,634,646

这是一种方法，也可以替换默认分隔符与任何字符:

val myNumber = NumberFormat.getNumberInstance(Locale.US)
   .format(123456789)
   .replace(",", "،")