假设我这里有一个字符串:

var fullName: String = "First Last"

我想在空白处拆分字符串,并将值分配给它们各自的变量

var fullNameArr = // something like: fullName.explode(" ") 

var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]

此外,有时用户可能没有姓氏。


当前回答

您可以使用此公共函数并添加任何要分隔的字符串

func separateByString(String wholeString: String, byChar char:String) -> [String] {

    let resultArray = wholeString.components(separatedBy: char)
    return resultArray
}

var fullName: String = "First Last"
let array = separateByString(String: fullName, byChar: " ")
var firstName: String = array[0]
var lastName: String = array[1]
print(firstName)
print(lastName)

其他回答

斯威夫特4

let words = "these words will be elements in an array".components(separatedBy: " ")

Xcode 8.0/Swift 3

let fullName = "First Last"
var fullNameArr = fullName.components(separatedBy: " ")

var firstname = fullNameArr[0] // First
var lastname = fullNameArr[1] // Last

漫长的道路:

var fullName: String = "First Last"
fullName += " " // this will help to see the last word

var newElement = "" //Empty String
var fullNameArr = [String]() //Empty Array

for Character in fullName.characters {
    if Character == " " {
        fullNameArr.append(newElement)
        newElement = ""
    } else {
        newElement += "\(Character)"
    }
}


var firsName = fullNameArr[0] // First
var lastName = fullNameArr[1] // Last

在Swift 4中将字符串拆分为数组的步骤。

赋值字符串基于@spling。

注意:variableName.components(separatedBy:“split关键字”)

let fullName: String = "First Last @ triggerd event of the session by session storage @ it can be divided by the event of the trigger."
let fullNameArr = fullName.components(separatedBy: "@")
print("split", fullNameArr)

雨燕3

let line = "AAA    BBB\t CCC"
let fields = line.components(separatedBy: .whitespaces).filter {!$0.isEmpty}

返回三个字符串AAA、BBB和CCC筛选出空字段处理多个空格和制表字符如果要处理新行,请将.whittespaces替换为.whittespace和新行

字符串处理在Swift中仍然是一个挑战,而且它一直在显著变化,从其他答案中可以看到。希望事情稳定下来,事情会变得更简单。这是在当前3.0版本的Swift中使用多个分隔符的方法。

斯威夫特3:

let chars = CharacterSet(charactersIn: ".,; -")
let split = phrase.components(separatedBy: chars)

// Or if the enums do what you want, these are preferred. 
let chars2 = CharacterSet.alphaNumerics // .whitespaces, .punctuation, .capitalizedLetters etc
let split2 = phrase.components(separatedBy: chars2)