假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
假设我这里有一个字符串:
var fullName: String = "First Last"
我想在空白处拆分字符串,并将值分配给它们各自的变量
var fullNameArr = // something like: fullName.explode(" ")
var firstName: String = fullNameArr[0]
var lastName: String? = fullnameArr[1]
此外,有时用户可能没有姓氏。
当前回答
您可以使用此公共函数并添加任何要分隔的字符串
func separateByString(String wholeString: String, byChar char:String) -> [String] {
let resultArray = wholeString.components(separatedBy: char)
return resultArray
}
var fullName: String = "First Last"
let array = separateByString(String: fullName, byChar: " ")
var firstName: String = array[0]
var lastName: String = array[1]
print(firstName)
print(lastName)
其他回答
在Swift 4中将字符串拆分为数组的步骤。
赋值字符串基于@spling。
注意:variableName.components(separatedBy:“split关键字”)
let fullName: String = "First Last @ triggerd event of the session by session storage @ it can be divided by the event of the trigger."
let fullNameArr = fullName.components(separatedBy: "@")
print("split", fullNameArr)
非顶部:
对于搜索如何使用子字符串(而不是字符)拆分字符串的人来说,下面是一个有效的解决方案:
// TESTING
let str1 = "Hello user! What user's details? Here user rounded with space."
let a = str1.split(withSubstring: "user") // <-------------- HERE IS A SPLIT
print(a) // ["Hello ", "! What ", "\'s details? Here ", " rounded with space."]
// testing the result
var result = ""
for item in a {
if !result.isEmpty {
result += "user"
}
result += item
}
print(str1) // "Hello user! What user's details? Here user rounded with space."
print(result) // "Hello user! What user's details? Here user rounded with space."
print(result == str1) // true
/// Extension providing `split` and `substring` methods.
extension String {
/// Split given string with substring into array
/// - Parameters:
/// - string: the string
/// - substring: the substring to search
/// - Returns: array of components
func split(withSubstring substring: String) -> [String] {
var a = [String]()
var str = self
while let range = str.range(of: substring) {
let i = str.distance(from: str.startIndex, to: range.lowerBound)
let j = str.distance(from: str.startIndex, to: range.upperBound)
let left = str.substring(index: 0, length: i)
let right = str.substring(index: j, length: str.length - j)
a.append(left)
str = right
}
if !str.isEmpty {
a.append(str)
}
return a
}
/// the length of the string
public var length: Int {
return self.count
}
/// Get substring, e.g. "ABCDE".substring(index: 2, length: 3) -> "CDE"
///
/// - parameter index: the start index
/// - parameter length: the length of the substring
///
/// - returns: the substring
public func substring(index: Int, length: Int) -> String {
if self.length <= index {
return ""
}
let leftIndex = self.index(self.startIndex, offsetBy: index)
if self.length <= index + length {
return String(self[leftIndex..<self.endIndex])
}
let rightIndex = self.index(self.endIndex, offsetBy: -(self.length - index - length))
return String(self[leftIndex..<rightIndex])
}
}
Swift的方法是使用全局拆分函数,如下所示:
var fullName = "First Last"
var fullNameArr = split(fullName) {$0 == " "}
var firstName: String = fullNameArr[0]
var lastName: String? = fullNameArr.count > 1 ? fullNameArr[1] : nil
使用Swift 2
在Swift 2中,由于引入了内部CharacterView类型,拆分的使用变得有点复杂。这意味着String不再采用SequenceType或CollectionType协议,您必须改为使用.characts属性来访问String实例的CharacterView类型表示。(注意:CharacterView确实采用SequenceType和CollectionType协议)。
let fullName = "First Last"
let fullNameArr = fullName.characters.split{$0 == " "}.map(String.init)
// or simply:
// let fullNameArr = fullName.characters.split{" "}.map(String.init)
fullNameArr[0] // First
fullNameArr[1] // Last
Swift 4或更高版本
如果您只需要正确设置人名格式,可以使用PersonNameComponentsFormater。
PersonNameComponentsFormater类提供本地化人名组成部分的表示通过PersonNameComponents对象。使用此类创建本地化当向用户显示人名信息时。
// iOS (9.0 and later), macOS (10.11 and later), tvOS (9.0 and later), watchOS (2.0 and later)
let nameFormatter = PersonNameComponentsFormatter()
let name = "Mr. Steven Paul Jobs Jr."
// personNameComponents requires iOS (10.0 and later)
if let nameComps = nameFormatter.personNameComponents(from: name) {
nameComps.namePrefix // Mr.
nameComps.givenName // Steven
nameComps.middleName // Paul
nameComps.familyName // Jobs
nameComps.nameSuffix // Jr.
// It can also be configured to format your names
// Default (same as medium), short, long or abbreviated
nameFormatter.style = .default
nameFormatter.string(from: nameComps) // "Steven Jobs"
nameFormatter.style = .short
nameFormatter.string(from: nameComps) // "Steven"
nameFormatter.style = .long
nameFormatter.string(from: nameComps) // "Mr. Steven Paul Jobs jr."
nameFormatter.style = .abbreviated
nameFormatter.string(from: nameComps) // SJ
// It can also be use to return an attributed string using annotatedString method
nameFormatter.style = .long
nameFormatter.annotatedString(from: nameComps) // "Mr. Steven Paul Jobs jr."
}
编辑/更新:
Swift 5或更高版本
对于按非字母字符拆分字符串,我们可以使用新的Character属性isLetter:
let fullName = "First Last"
let components = fullName.split{ !$0.isLetter }
print(components) // "["First", "Last"]\n"
let fullName : String = "Steve.Jobs"
let fullNameArr : [String] = fullName.components(separatedBy: ".")
var firstName : String = fullNameArr[0]
var lastName : String = fullNameArr[1]