我应该如何选择一个标签在TabLayout编程?
TabLayout tabLayout = (TabLayout) findViewById(R.id.tabs);
tabLayout.setupWithViewPager(viewPager);
我应该如何选择一个标签在TabLayout编程?
TabLayout tabLayout = (TabLayout) findViewById(R.id.tabs);
tabLayout.setupWithViewPager(viewPager);
当前回答
您可以使用以下函数设置TabLayout位置
public void setTab(){
tabLayout.setScrollPosition(YOUR_SCROLL_INDEX,0,true);
tabLayout.setSelected(true);
}
其他回答
试试这个方法。
tabLayout.setTabTextColors(getResources().getColor(R.color.colorHintTextLight),
getResources().getColor(R.color.colorPrimaryTextLight));
如果你不能使用tab.select(),也不想使用ViewPager,你仍然可以通过编程方式选择一个选项卡。如果你通过TabLayout使用自定义视图。选项卡setCustomView (android.view。View View)它更简单。以下是如何做到这两种方式。
// if you've set a custom view
void updateTabSelection(int position) {
// get the position of the currently selected tab and set selected to false
mTabLayout.getTabAt(mTabLayout.getSelectedTabPosition()).getCustomView().setSelected(false);
// set selected to true on the desired tab
mTabLayout.getTabAt(position).getCustomView().setSelected(true);
// move the selection indicator
mTabLayout.setScrollPosition(position, 0, true);
// ... your logic to swap out your fragments
}
如果你不使用自定义视图,那么你可以这样做
// if you are not using a custom view
void updateTabSelection(int position) {
// get a reference to the tabs container view
LinearLayout ll = (LinearLayout) mTabLayout.getChildAt(0);
// get the child view at the position of the currently selected tab and set selected to false
ll.getChildAt(mTabLayout.getSelectedTabPosition()).setSelected(false);
// get the child view at the new selected position and set selected to true
ll.getChildAt(position).setSelected(true);
// move the selection indicator
mTabLayout.setScrollPosition(position, 0, true);
// ... your logic to swap out your fragments
}
使用StateListDrawable在选中和未选中的可绘制对象之间切换,或者类似地处理颜色和/或可绘制对象。
为你的viewpager添加:
viewPager.addOnPageChangeListener(new ViewPager.OnPageChangeListener() {
@Override
public void onPageSelected(int position) {
array.clear();
switch (position) {
case 1:
//like a example
setViewPagerByIndex(0);
break;
}
}
@Override
public void onPageScrolled(int position, float positionOffset, int positionOffsetPixels) {
}
@Override
public void onPageScrollStateChanged(int state) {
}
});
//on处理程序,以防止crash outofmemory
private void setViewPagerByIndex(final int index){
Application.getInstance().getHandler().post(new Runnable() {
@Override
public void run() {
viewPager.setCurrentItem(index);
}
});
}
我使用TabLayout切换片段。它在大多数情况下都是有效的,除了当我试图以编程方式使用tab.select(),我的TabLayout选择一个选项卡时。OnTabSelectedListener将触发onTabSelected(TabLayout。Tab Tab),这会让我很伤心。我正在寻找一种不触发侦听器的方法来做程序化选择。
So I adapted @kenodoggy 's answer to my use. I was further facing a problem where some of the internal objects would return null (because they weren't created yet, because I was answering onActivityResult() from my fragment, which occurs before onCreate() in the case the activity is singleTask or singleInstance) so I wrote up a detailed if/else sequence which would report the error and fall through without the NullPointerException that would otherwise trigger. I use Timber for logging, if you're not using that substitute with Log.e().
void updateSelectedTabTo(int position) {
if (tabLayout != null){
int selected = tabLayout.getSelectedTabPosition();
if (selected != -1){
TabLayout.Tab oldTab = tabLayout.getTabAt(0);
if (oldTab != null){
View view = oldTab.getCustomView();
if (view != null){
view.setSelected(false);
}
else {
Timber.e("oldTab customView is null");
}
}
else {
Timber.e("oldTab is null");
}
}
else {
Timber.e("selected is -1");
}
TabLayout.Tab newTab = tabLayout.getTabAt(position);
if (newTab != null){
View view = newTab.getCustomView();
if (view != null){
view.setSelected(false);
}
else {
Timber.e("newTab customView is null");
}
}
else {
Timber.e("newTab is null");
}
}
else {
Timber.e("tablayout is null");
}
}
这里,tabLayout是绑定到XML中的tabLayout对象的内存变量。我不使用滚动标签功能,所以我把它也删除了。
试试这个
new Handler().postDelayed(
new Runnable(){
@Override
public void run() {
if (i == 1){
tabLayout.getTabAt(0).select();
} else if (i == 2){
tabLayout.getTabAt(1).select();
}
}
}, 100);