没有使用Django，尝试使用Python 3.9。它也可以在处理程序中使用下面的代码片段来检索:

考虑URL为-

http://localhost:8081/api/v1/users?query_key=abcdef12345

和handler方法为:

@routes.get('/api/v1/users')
async def handler_users(request):
    query_key = request.url.query['query_key']

3.4 . for Python >

from urllib import parse
url = 'http://foo.appspot.com/abc?def=ghi'
query_def=parse.parse_qs(parse.urlparse(url).query)['def'][0]

在原始python中解析它:

path = '/some_path?k1=v1&k2=v2&k3=v3'
_, query_string = path.split('?')
params  = dict(param.split('=') for param in query_string.split('&'))
print(params)

输出:

{'k1': 'v1', 'k2': 'v2', 'k3': 'v3'}

import cgitb
cgitb.enable()

import cgi
print "Content-Type: text/plain;charset=utf-8"
print
form = cgi.FieldStorage()
i = int(form.getvalue('a'))+int(form.getvalue('b'))
print i

这不是Django特有的，而是一般的Python。关于Django的具体答案，请看来自@jball037的这个

Python 2:

import urlparse

url = 'https://www.example.com/some_path?some_key=some_value'
parsed = urlparse.urlparse(url)
captured_value = urlparse.parse_qs(parsed.query)['some_key'][0]

print captured_value

Python 3:

from urllib.parse import urlparse
from urllib.parse import parse_qs

url = 'https://www.example.com/some_path?some_key=some_value'
parsed_url = urlparse(url)
captured_value = parse_qs(parsed_url.query)['some_key'][0]

print(captured_value)

Parse_qs返回一个列表。[0]获取列表的第一项，因此每个脚本的输出是some_value

下面是Python 3的'parse_qs'文档

urlparse模块提供了你需要的一切:

urlparse.parse_qs ()