Angular文件上传

我是Angular的初学者，我想知道如何创建Angular 5文件上传部分，我试图找到任何教程或文档，但我在任何地方都看不到任何东西。对此有什么想法吗?我尝试了ng4-files，但它不适用于Angular 5

当前回答

下面是我上传excel文件的方法: 目录结构:

app
|-----uploadcomponent
           |-----uploadcomponent.module.ts
           |-----uploadcomponent.html
|-----app.module.ts
|-----app.component.ts
|-----app.service.ts

uploadcomponent.html

<div>
   <form [formGroup]="form" (ngSubmit)="onSubmit()">
     <input type="file" name="profile"  enctype="multipart/form-data" accept=".xlsm,application/msexcel" (change)="onChange($event)" />
     <button type="submit">Upload Template</button>
     <button id="delete_button" class="delete_button" type="reset"><i class="fa fa-trash"></i></button> 
   </form>           
</div>

uploadcomponent.ts

    import { FormBuilder, FormGroup, ReactiveFormsModule } from '@angular/forms';
    import { Component, OnInit } from '@angular/core';
    ....
    export class UploadComponent implements OnInit {
        form: FormGroup;
        constructor(private formBuilder: FormBuilder, private uploadService: AppService) {}
        ngOnInit() {  
            this.form = this.formBuilder.group({
               profile: ['']
            });
        }

        onChange(event) {
            if (event.target.files.length > 0) {
              const file = event.target.files[0];

              this.form.get('profile').setValue(file);
              console.log(this.form.get('profile').value)
            }
        }

        onSubmit() {
           const formData = new FormData();
           formData.append('file', this.form.get('profile').value);

           this.uploadService.upload(formData).subscribe(
             (res) => {
               this.response = res;

               console.log(res);

             },
             (err) => {  
               console.log(err);
             });
         }
    }

app.service.ts

    upload(formData) {
        const endpoint = this.service_url+'upload/';
        const httpOptions = headers: new HttpHeaders({    <<<< Changes are here
            'Authorization': 'token xxxxxxx'})
        };
        return this.http.post(endpoint, formData, httpOptions);
    }

在后台，我使用DJango REST框架。 models.py

from __future__ import unicode_literals
from django.db import models
from django.db import connection
from django_mysql.models import JSONField, Model
import uuid
import os


def change_filename(instance, filename):
    extension = filename.split('.')[-1]
    file_name = os.path.splitext(filename)[0]
    uuid_name = uuid.uuid4()
    return file_name+"_"+str(uuid_name)+"."+extension

class UploadTemplate (Model):
    id = models.AutoField(primary_key=True)
    file = models.FileField(blank=False, null=False, upload_to=change_filename)

    def __str__(self):
        return str(self.file.name)

views.py。

class UploadView(APIView):
    serializer_class = UploadSerializer
    parser_classes = [MultiPartParser]       

    def get_queryset(self):
        queryset = UploadTemplate.objects.all()
        return queryset

    def post(self, request, *args, **kwargs):
        file_serializer = UploadSerializer(data=request.data)
        status = None
        message = None
        if file_serializer.is_valid():
            file_serializer.save()
            status = "Success"
            message = "Success"
        else:
            status = "Failure"
            message = "Failure!"
        content = {'status': status, 'message': message}
        return Response(content)

serializers.py。

from uploadtemplate.models import UploadTemplate
from rest_framework import serializers

class UploadSerializer(serializers.ModelSerializer):
    class Meta:
        model = UploadTemplate
        fields = '__all__'

urls . py。

router.register(r'uploadtemplate', uploadtemplateviews.UploadTemplateView, 
    base_name='UploadTemplate')
urlpatterns = [
    ....
    url(r'upload/', uploadtemplateviews.UploadTemplateView.as_view()),
] + static(settings.STATIC_URL, document_root=settings.STATIC_ROOT)

if settings.DEBUG:
    urlpatterns += static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)

MEDIA_URL和MEDIA_ROOT在项目的settings.py中定义。

谢谢!

2020-09-07 14:43:54

其他回答

非常简单和最快的方法是使用ng2-file-upload。

通过npm安装ng2-file-upload。NPM I ng2-file-upload——保存

首先在模块中导入模块。

import { FileUploadModule } from 'ng2-file-upload';

Add it to [imports] under @NgModule:
imports: [ ... FileUploadModule, ... ]

标记:

<input ng2FileSelect type="file" accept=".xml" [uploader]="uploader"/>

在你的组件中:

import { FileUploader } from 'ng2-file-upload';
...
uploader: FileUploader = new FileUploader({ url: "api/your_upload", removeAfterUpload: false, autoUpload: true });

这是最简单的用法。要知道所有的权力，这看到演示

2018-07-13 15:43:55

好的，因为这个线程出现在谷歌的第一个结果中，对于其他有同样问题的用户，你不需要像trueboroda指出的那样重新开始，有ng2-file-upload库，它简化了使用angular 6和7上传文件的过程，你所需要做的是:

安装最新的Angular CLI

yarn add global @angular/cli

出于兼容性考虑，请安装rx-compat

npm install rxjs-compat --save

安装ng2-file-upload

npm install ng2-file-upload --save

在你的模块中导入FileSelectDirective指令。

import { FileSelectDirective } from 'ng2-file-upload';

Add it to [declarations] under @NgModule:
declarations: [ ... FileSelectDirective , ... ]

在你的组件中

import { FileUploader } from 'ng2-file-upload/ng2-file-upload';
...

export class AppComponent implements OnInit {

   public uploader: FileUploader = new FileUploader({url: URL, itemAlias: 'photo'});
}

模板

<input type="file" name="photo" ng2FileSelect [uploader]="uploader" />

为了更好地理解，你可以查看这个链接: 如何使用Angular 6/7上传文件

2019-03-09 01:42:50

使用Angular和nodejs上传文件的完整示例(express)

HTML代码

            <div class="form-group">
                <label for="file">Choose File</label><br/>
                <input type="file" id="file" (change)="uploadFile($event.target.files)" multiple>
            </div>

TS组件代码

uploadFile(files) {
    console.log('files', files)
        var formData = new FormData();

    for(let i =0; i < files.length; i++){
      formData.append("files", files[i], files[i]['name']);
        }

    this.httpService.httpPost('/fileUpload', formData)
      .subscribe((response) => {
        console.log('response', response)
      },
        (error) => {
      console.log('error in fileupload', error)
       })
  }

Node Js代码

上传火灾控制器

function start(req, res) {
fileUploadService.fileUpload(req, res)
    .then(fileUploadServiceResponse => {
        res.status(200).send(fileUploadServiceResponse)
    })
    .catch(error => {
        res.status(400).send(error)
    })
}

module.exports.start = start

使用multer上传服务

const multer = require('multer') // import library
const moment = require('moment')
const q = require('q')
const _ = require('underscore')
const fs = require('fs')
const dir = './public'

/** Store file on local folder */
let storage = multer.diskStorage({
destination: function (req, file, cb) {
    cb(null, 'public')
},
filename: function (req, file, cb) {
    let date = moment(moment.now()).format('YYYYMMDDHHMMSS')
    cb(null, date + '_' + file.originalname.replace(/-/g, '_').replace(/ /g,     '_'))
}
})

/** Upload files  */
let upload = multer({ storage: storage }).array('files')

/** Exports fileUpload function */
module.exports = {
fileUpload: function (req, res) {
    let deferred = q.defer()

    /** Create dir if not exist */
    if (!fs.existsSync(dir)) {
        fs.mkdirSync(dir)
        console.log(`\n\n ${dir} dose not exist, hence created \n\n`)
    }

    upload(req, res, function (err) {
        if (req && (_.isEmpty(req.files))) {
            deferred.resolve({ status: 200, message: 'File not attached', data: [] })
        } else {
            if (err) {
                deferred.reject({ status: 400, message: 'error', data: err })
            } else {
                deferred.resolve({
                    status: 200,
                    message: 'File attached',
                    filename: _.pluck(req.files,
                        'filename'),
                    data: req.files
                })
            }
        }
    })
    return deferred.promise
}
}

2019-04-26 13:58:06

我使用的是Angular 5.2.11，我喜欢Gregor Doroschenko提供的解决方案，但是我注意到上传的文件是零字节的，我必须做一个小小的改变才能让它为我工作。

postFile(fileToUpload: File): Observable<boolean> {
  const endpoint = 'your-destination-url';
  return this.httpClient
    .post(endpoint, fileToUpload, { headers: yourHeadersConfig })
    .map(() => { return true; })
    .catch((e) => this.handleError(e));
}

下面几行(formData)对我不起作用。

const formData: FormData = new FormData();
formData.append('fileKey', fileToUpload, fileToUpload.name);

https://github.com/amitrke/ngrke/blob/master/src/app/services/fileupload.service.ts

2018-10-08 20:16:30