如何获得您的Makefile的当前相对目录?

我有几个makefile在应用程序特定的目录，像这样:

/project1/apps/app_typeA/Makefile
/project1/apps/app_typeB/Makefile
/project1/apps/app_typeC/Makefile

每个Makefile都在这个路径中包含一个.inc文件:

/project1/apps/app_rules.inc

app_rules内部。inc .我正在设置我想要在构建时放置二进制文件的目的地。我希望所有二进制文件都在它们各自的app_type路径中:

/project1/bin/app_typeA/

我尝试使用$(CURDIR)，像这样:

OUTPUT_PATH = /project1/bin/$(CURDIR)

但相反，我得到了二进制文件埋在整个路径名，像这样:(注意冗余)

/project1/bin/projects/users/bob/project1/apps/app_typeA

我能做些什么来获得执行的“当前目录”，以便我可以知道app_typeX，以便将二进制文件放在各自的类型文件夹中?

当前回答

我喜欢选定的答案，但我认为实际展示它比解释它更有帮助。

/ tmp / makefile_path_test.sh

#!/bin/bash -eu

# Create a testing dir
temp_dir=/tmp/makefile_path_test
proj_dir=$temp_dir/dir1/dir2/dir3
mkdir -p $proj_dir

# Create the Makefile in $proj_dir
# (Because of this, $proj_dir is what $(path) should evaluate to.)
cat > $proj_dir/Makefile <<'EOF'
path := $(patsubst %/,%,$(dir $(abspath $(lastword $(MAKEFILE_LIST)))))
cwd  := $(shell pwd)

all:
    @echo "MAKEFILE_LIST: $(MAKEFILE_LIST)"
    @echo "         path: $(path)"
    @echo "          cwd: $(cwd)"
    @echo ""
EOF

# See/debug each command
set -x

# Test using the Makefile in the current directory
cd $proj_dir
make

# Test passing a Makefile
cd $temp_dir
make -f $proj_dir/Makefile

# Cleanup
rm -rf $temp_dir

输出:

+ cd /tmp/makefile_path_test/dir1/dir2/dir3
+ make
MAKEFILE_LIST:  Makefile
         path: /private/tmp/makefile_path_test/dir1/dir2/dir3
          cwd: /tmp/makefile_path_test/dir1/dir2/dir3

+ cd /tmp/makefile_path_test
+ make -f /tmp/makefile_path_test/dir1/dir2/dir3/Makefile
MAKEFILE_LIST:  /tmp/makefile_path_test/dir1/dir2/dir3/Makefile
         path: /tmp/makefile_path_test/dir1/dir2/dir3
          cwd: /tmp/makefile_path_test

+ rm -rf /tmp/makefile_path_test

注意:函数$(patsubst %/，%，[path/goes/here/])用于去除后面的斜杠。

2018-04-09 19:27:07

其他回答

简单、正确、现代的方式:

对于GNU make >= 3.81，它是在2006年引入的

ROOT_DIR := $(dir $(realpath $(lastword $(MAKEFILE_LIST))))

MAKEFILE_LIST在包含文件进入和退出作用域时发生变化。最后一项是当前文件。 lastword提取最后一项(Makefile名称，相对于pwd) Realpath是内置的，并从文件系统根解析为规范路径 Dir删除文件名，只留下目录。

2022-08-27 09:54:25

更新2018/03/05 最后我用这个:

shellPath=`echo $PWD/``echo ${0%/*}`

# process absolute path
shellPath1=`echo $PWD/`
shellPath2=`echo ${0%/*}`
if [ ${shellPath2:0:1} == '/' ] ; then
    shellPath=${shellPath2}
fi

它可以在相对路径或绝对路径上正确执行。由crontab调用的已执行正确。在其他shell中执行正确。

显示示例，a.sh打印自路径。

[root@izbp1a7wyzv7b5hitowq2yz /]# more /root/test/a.sh
shellPath=`echo $PWD/``echo ${0%/*}`

# process absolute path
shellPath1=`echo $PWD/`
shellPath2=`echo ${0%/*}`
if [ ${shellPath2:0:1} == '/' ] ; then
    shellPath=${shellPath2}
fi

echo $shellPath
[root@izbp1a7wyzv7b5hitowq2yz /]# more /root/b.sh
shellPath=`echo $PWD/``echo ${0%/*}`

# process absolute path
shellPath1=`echo $PWD/`
shellPath2=`echo ${0%/*}`
if [ ${shellPath2:0:1} == '/' ] ; then
    shellPath=${shellPath2}
fi

$shellPath/test/a.sh
[root@izbp1a7wyzv7b5hitowq2yz /]# ~/b.sh
/root/test
[root@izbp1a7wyzv7b5hitowq2yz /]# /root/b.sh
/root/test
[root@izbp1a7wyzv7b5hitowq2yz /]# cd ~
[root@izbp1a7wyzv7b5hitowq2yz ~]# ./b.sh
/root/./test
[root@izbp1a7wyzv7b5hitowq2yz ~]# test/a.sh
/root/test
[root@izbp1a7wyzv7b5hitowq2yz ~]# cd test
[root@izbp1a7wyzv7b5hitowq2yz test]# ./a.sh
/root/test/.
[root@izbp1a7wyzv7b5hitowq2yz test]# cd /
[root@izbp1a7wyzv7b5hitowq2yz /]# /root/test/a.sh
/root/test
[root@izbp1a7wyzv7b5hitowq2yz /]#

旧: 我用这个:

MAKEFILE_PATH := $(PWD)/$({0%/*})

如果在其他shell和其他目录下执行，可以显示正确。

2017-02-17 12:03:00

从这里带走;

ROOT_DIR:=$(shell dirname $(realpath $(firstword $(MAKEFILE_LIST))))

显示为;

$ cd /home/user/

$ make -f test/Makefile 
/home/user/test

$ cd test; make Makefile 
/home/user/test

2014-04-27 14:37:03

我喜欢选定的答案，但我认为实际展示它比解释它更有帮助。

/ tmp / makefile_path_test.sh

#!/bin/bash -eu

# Create a testing dir
temp_dir=/tmp/makefile_path_test
proj_dir=$temp_dir/dir1/dir2/dir3
mkdir -p $proj_dir

# Create the Makefile in $proj_dir
# (Because of this, $proj_dir is what $(path) should evaluate to.)
cat > $proj_dir/Makefile <<'EOF'
path := $(patsubst %/,%,$(dir $(abspath $(lastword $(MAKEFILE_LIST)))))
cwd  := $(shell pwd)

all:
    @echo "MAKEFILE_LIST: $(MAKEFILE_LIST)"
    @echo "         path: $(path)"
    @echo "          cwd: $(cwd)"
    @echo ""
EOF

# See/debug each command
set -x

# Test using the Makefile in the current directory
cd $proj_dir
make

# Test passing a Makefile
cd $temp_dir
make -f $proj_dir/Makefile

# Cleanup
rm -rf $temp_dir

输出:

+ cd /tmp/makefile_path_test/dir1/dir2/dir3
+ make
MAKEFILE_LIST:  Makefile
         path: /private/tmp/makefile_path_test/dir1/dir2/dir3
          cwd: /tmp/makefile_path_test/dir1/dir2/dir3

+ cd /tmp/makefile_path_test
+ make -f /tmp/makefile_path_test/dir1/dir2/dir3/Makefile
MAKEFILE_LIST:  /tmp/makefile_path_test/dir1/dir2/dir3/Makefile
         path: /tmp/makefile_path_test/dir1/dir2/dir3
          cwd: /tmp/makefile_path_test

+ rm -rf /tmp/makefile_path_test

注意:函数$(patsubst %/，%，[path/goes/here/])用于去除后面的斜杠。

2018-04-09 19:27:07

用{}代替()

cur_dir=${shell pwd}
parent_dir=${shell dirname ${shell pwd}}}

2022-12-02 07:26:22

如何获得您的Makefile的当前相对目录?

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