我试图得到当前日期之间的差异作为NSDate()和日期从一个PHP时间();调用例如:NSDate(timeintervalsincerely eferencedate: 1417147270)。我怎样才能得到这两个日期之间的时间差呢?我想有一个函数，比较两个日期，如果(秒> 60)，那么它返回分钟，如果(分钟> 60)返回小时，如果(小时> 24)返回天，等等。
我该怎么做呢?
编辑:目前接受的答案完全符合我的想法。为了便于使用，我推荐使用它，以便以PHP time()函数使用的形式获取两个日期之间的时间。如果你不是特别熟悉PHP，这是1970年1月1日的时间，单位是秒。这对于PHP的后端是有益的。如果你正在使用像NodeJS这样的后端，你可能会考虑下面的其他选项。
当前回答
在jose920405中添加了一些答案，使其与Swift 3.0及以上版本兼容
func getDateTimeDiff(dateStr:String) -> String {
let formatter : DateFormatter = DateFormatter()
formatter.timeZone = NSTimeZone.local
formatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let now = formatter.string(from: NSDate() as Date)
let startDate = formatter.date(from: dateStr)
let endDate = formatter.date(from: now)
// *** create calendar object ***
var calendar = NSCalendar.current
// *** Get components using current Local & Timezone ***
print(calendar.dateComponents([.year, .month, .day, .hour, .minute, .second], from: startDate!))
// *** define calendar components to use as well Timezone to UTC ***
let unitFlags = Set<Calendar.Component>([.year, .month, .day, .hour, .minute, .second])
calendar.timeZone = TimeZone(identifier: "UTC")!
let dateComponents = calendar.dateComponents(unitFlags, from: startDate!, to: endDate!)
// *** Get Individual components from date ***
let years = dateComponents.year!
let months = dateComponents.month!
let days = dateComponents.day!
let hours = dateComponents.hour!
let minutes = dateComponents.minute!
let seconds = dateComponents.second!
var timeAgo = ""
if (seconds > 0){
if seconds < 2 {
timeAgo = "Second Ago"
}
else{
timeAgo = "\(seconds) Second Ago"
}
}
if (minutes > 0){
if minutes < 2 {
timeAgo = "Minute Ago"
}
else{
timeAgo = "\(minutes) Minutes Ago"
}
}
if(hours > 0){
if hours < 2 {
timeAgo = "Hour Ago"
}
else{
timeAgo = "\(hours) Hours Ago"
}
}
if (days > 0) {
if days < 2 {
timeAgo = "Day Ago"
}
else{
timeAgo = "\(days) Days Ago"
}
}
if(months > 0){
if months < 2 {
timeAgo = "Month Ago"
}
else{
timeAgo = "\(months) Months Ago"
}
}
if(years > 0){
if years < 2 {
timeAgo = "Year Ago"
}
else{
timeAgo = "\(years) Years Ago"
}
}
DLog("timeAgo is ===> \(timeAgo)")
return timeAgo;
}
其他回答
在jose920405中添加了一些答案，使其与Swift 3.0及以上版本兼容
func getDateTimeDiff(dateStr:String) -> String {
let formatter : DateFormatter = DateFormatter()
formatter.timeZone = NSTimeZone.local
formatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let now = formatter.string(from: NSDate() as Date)
let startDate = formatter.date(from: dateStr)
let endDate = formatter.date(from: now)
// *** create calendar object ***
var calendar = NSCalendar.current
// *** Get components using current Local & Timezone ***
print(calendar.dateComponents([.year, .month, .day, .hour, .minute, .second], from: startDate!))
// *** define calendar components to use as well Timezone to UTC ***
let unitFlags = Set<Calendar.Component>([.year, .month, .day, .hour, .minute, .second])
calendar.timeZone = TimeZone(identifier: "UTC")!
let dateComponents = calendar.dateComponents(unitFlags, from: startDate!, to: endDate!)
// *** Get Individual components from date ***
let years = dateComponents.year!
let months = dateComponents.month!
let days = dateComponents.day!
let hours = dateComponents.hour!
let minutes = dateComponents.minute!
let seconds = dateComponents.second!
var timeAgo = ""
if (seconds > 0){
if seconds < 2 {
timeAgo = "Second Ago"
}
else{
timeAgo = "\(seconds) Second Ago"
}
}
if (minutes > 0){
if minutes < 2 {
timeAgo = "Minute Ago"
}
else{
timeAgo = "\(minutes) Minutes Ago"
}
}
if(hours > 0){
if hours < 2 {
timeAgo = "Hour Ago"
}
else{
timeAgo = "\(hours) Hours Ago"
}
}
if (days > 0) {
if days < 2 {
timeAgo = "Day Ago"
}
else{
timeAgo = "\(days) Days Ago"
}
}
if(months > 0){
if months < 2 {
timeAgo = "Month Ago"
}
else{
timeAgo = "\(months) Months Ago"
}
}
if(years > 0){
if years < 2 {
timeAgo = "Year Ago"
}
else{
timeAgo = "\(years) Years Ago"
}
}
DLog("timeAgo is ===> \(timeAgo)")
return timeAgo;
}
——>使用这个找到时间差距在两个日期在Swift(与两个字符串)。
func timeGapBetweenDates(previousDate : String,currentDate : String)
{
let dateString1 = previousDate
let dateString2 = currentDate
let Dateformatter = DateFormatter()
Dateformatter.dateFormat = "yyyy-MM-dd HH:mm:ss"
let date1 = Dateformatter.date(from: dateString1)
let date2 = Dateformatter.date(from: dateString2)
let distanceBetweenDates: TimeInterval? = date2?.timeIntervalSince(date1!)
let secondsInAnHour: Double = 3600
let minsInAnHour: Double = 60
let secondsInDays: Double = 86400
let secondsInWeek: Double = 604800
let secondsInMonths : Double = 2592000
let secondsInYears : Double = 31104000
let minBetweenDates = Int((distanceBetweenDates! / minsInAnHour))
let hoursBetweenDates = Int((distanceBetweenDates! / secondsInAnHour))
let daysBetweenDates = Int((distanceBetweenDates! / secondsInDays))
let weekBetweenDates = Int((distanceBetweenDates! / secondsInWeek))
let monthsbetweenDates = Int((distanceBetweenDates! / secondsInMonths))
let yearbetweenDates = Int((distanceBetweenDates! / secondsInYears))
let secbetweenDates = Int(distanceBetweenDates!)
if yearbetweenDates > 0
{
print(yearbetweenDates,"years")//0 years
}
else if monthsbetweenDates > 0
{
print(monthsbetweenDates,"months")//0 months
}
else if weekBetweenDates > 0
{
print(weekBetweenDates,"weeks")//0 weeks
}
else if daysBetweenDates > 0
{
print(daysBetweenDates,"days")//5 days
}
else if hoursBetweenDates > 0
{
print(hoursBetweenDates,"hours")//120 hours
}
else if minBetweenDates > 0
{
print(minBetweenDates,"minutes")//7200 minutes
}
else if secbetweenDates > 0
{
print(secbetweenDates,"seconds")//seconds
}
}
我在Leo Dabus的asnwer中添加了一个“长”版本，以防你想要一个字符串，说“2周前”而不是“2w”……
extension Date {
func offsetLong(from date: Date) -> String {
if years(from: date) > 0 {
return years(from: date) > 1 ? "\(years(from: date)) years ago" : "\(years(from: date)) year ago"
}
if months(from: date) > 0 {
return months(from: date) > 1 ? "\(months(from: date)) months ago" : "\(months(from: date)) month ago"
}
if weeks(from: date) > 0 {
return weeks(from: date) > 1 ? "\(weeks(from: date)) weeks ago" : "\(weeks(from: date)) week ago"
}
if days(from: date) > 0 {
return days(from: date) > 1 ? "\(days(from: date)) days ago" : "\(days(from: date)) day ago"
}
if hours(from: date) > 0 {
return hours(from: date) > 1 ? "\(hours(from: date)) hours ago" : "\(hours(from: date)) hour ago"
}
if minutes(from: date) > 0 {
return minutes(from: date) > 1 ? "\(minutes(from: date)) minutes ago" : "\(minutes(from: date)) minute ago"
}
if seconds(from: date) > 0 {
return seconds(from: date) > 1 ? "\(seconds(from: date)) seconds ago" : "\(seconds(from: date)) second ago"
}
return ""
}
}
以下是我对上述Swift 3的回答。这是截至2016年11月，Xcode发布版本为8.2 Beta (8C23)。使用上述Sagar和Emin的一些建议，有时不得不让Xcode自动完成来建议语法。在这个测试版中，语法似乎真的发生了变化。我从一个DatePicker:
let calendar = NSCalendar.current as NSCalendar
let currentDate = Date()
let date1 = calendar.startOfDay(for: buyDate!)
let date2 = calendar.startOfDay(for: currentDate)
let flags = NSCalendar.Unit.day
let components = calendar.components(flags, from: date1, to: date2)
NSLog(" day= \(components.day)")
斯威夫特5
func dateDiff(dateStr:String) -> String {
let f:DateFormatter = DateFormatter()
f.timeZone = NSTimeZone.local
f.dateFormat = "yyyy-M-dd'T'HH:mm:ss.SSSZZZ"
let now = f.string(from: NSDate() as Date)
let startDate = f.date(from: dateStr)
let endDate = f.date(from: now)
var _: NSCalendar = NSCalendar.current as NSCalendar
let dateComponents = Calendar.current.dateComponents([ .weekOfMonth, .day , .hour , .minute , .second], from: startDate!, to: endDate!)
let weeks = abs(dateComponents.weekOfMonth!)
let days = abs(dateComponents.day!)
let hours = abs(dateComponents.hour!)
let min = abs(dateComponents.minute!)
let sec = abs(dateComponents.second!)
var timeAgo = ""
if (sec > 0){
if (sec > 1) {
timeAgo = "\(sec) Seconds Ago"
} else {
timeAgo = "\(sec) Second Ago"
}
}
if (min > 0){
if (min > 1) {
timeAgo = "\(min) Minutes Ago"
} else {
timeAgo = "\(min) Minute Ago"
}
}
if(hours > 0){
if (hours > 1) {
timeAgo = "\(hours) Hours Ago"
} else {
timeAgo = "\(hours) Hour Ago"
}
}
if (days > 0) {
if (days > 1) {
timeAgo = "\(days) Days Ago"
} else {
timeAgo = "\(days) Day Ago"
}
}
if(weeks > 0){
if (weeks > 1) {
timeAgo = "\(weeks) Weeks Ago"
} else {
timeAgo = "\(weeks) Week Ago"
}
}
print("timeAgo is===> \(timeAgo)")
return timeAgo;
}
