假设我有一个带有数字列的表(让我们称之为“score”)。
我想生成一个计数表,显示分数在每个范围内出现的次数。
例如:
score range | number of occurrences ------------------------------------- 0-9 | 11 10-19 | 14 20-29 | 3 ... | ...
在这个示例中,有11行分数在0到9之间,14行分数在10到19之间,3行分数在20到29之间。
有什么简单的方法吗?你有什么建议吗?
假设我有一个带有数字列的表(让我们称之为“score”)。
我想生成一个计数表,显示分数在每个范围内出现的次数。
例如:
score range | number of occurrences ------------------------------------- 0-9 | 11 10-19 | 14 20-29 | 3 ... | ...
在这个示例中,有11行分数在0到9之间,14行分数在10到19之间,3行分数在20到29之间。
有什么简单的方法吗?你有什么建议吗?
当前回答
在SQL Server 2000上,投票最多的答案都不正确。也许他们用的是另一个版本。
下面是在SQL Server 2000上这两个软件的正确版本。
select t.range as [score range], count(*) as [number of occurences]
from (
select case
when score between 0 and 9 then ' 0- 9'
when score between 10 and 19 then '10-19'
else '20-99' end as range
from scores) t
group by t.range
or
select t.range as [score range], count(*) as [number of occurrences]
from (
select user_id,
case when score >= 0 and score< 10 then '0-9'
when score >= 10 and score< 20 then '10-19'
else '20-99' end as range
from scores) t
group by t.range
其他回答
select t.range as score, count(*) as Count
from (
select UserId,
case when isnull(score ,0) >= 0 and isnull(score ,0)< 5 then '0-5'
when isnull(score ,0) >= 5 and isnull(score ,0)< 10 then '5-10'
when isnull(score ,0) >= 10 and isnull(score ,0)< 15 then '10-15'
when isnull(score ,0) >= 15 and isnull(score ,0)< 20 then '15-20'
else ' 20+' end as range
,case when isnull(score ,0) >= 0 and isnull(score ,0)< 5 then 1
when isnull(score ,0) >= 5 and isnull(score ,0)< 10 then 2
when isnull(score ,0) >= 10 and isnull(score ,0)< 15 then 3
when isnull(score ,0) >= 15 and isnull(score ,0)< 20 then 4
else 5 end as pd
from score table
) t
group by t.range,pd order by pd
在SQL Server 2000上,投票最多的答案都不正确。也许他们用的是另一个版本。
下面是在SQL Server 2000上这两个软件的正确版本。
select t.range as [score range], count(*) as [number of occurences]
from (
select case
when score between 0 and 9 then ' 0- 9'
when score between 10 and 19 then '10-19'
else '20-99' end as range
from scores) t
group by t.range
or
select t.range as [score range], count(*) as [number of occurrences]
from (
select user_id,
case when score >= 0 and score< 10 then '0-9'
when score >= 10 and score< 20 then '10-19'
else '20-99' end as range
from scores) t
group by t.range
我在这里看到的答案在SQL Server的语法中行不通。我会用:
select t.range as [score range], count(*) as [number of occurences]
from (
select case
when score between 0 and 9 then ' 0-9 '
when score between 10 and 19 then '10-19'
when score between 20 and 29 then '20-29'
...
else '90-99' end as range
from scores) t
group by t.range
编辑:见评论
我会用一种稍微不同的方式来做,这样它就不必定义每种情况:
select t.range as [score range], count(*) as [number of occurences]
from (
select FLOOR(score/10) as range
from scores) t
group by t.range
没有测试过,但你懂的…
declare @RangeWidth int
set @RangeWidth = 10
select
Floor(Score/@RangeWidth) as LowerBound,
Floor(Score/@RangeWidth)+@RangeWidth as UpperBound,
Count(*)
From
ScoreTable
group by
Floor(Score/@RangeWidth)