在postgres中(其中||是字符串连接操作符):

select (score/10)*10 || '-' || (score/10)*10+9 as scorerange, count(*)
from scores
group by score/10
order by 1

给:

 scorerange | count 
------------+-------
 0-9        |    11
 10-19      |    14
 20-29      |     3
 30-39      |     2

下面是如何在T-SQL中做到这一点:

DECLARE @traunch INT = 1000;

SELECT 
    CONCAT
    ( 
      FORMAT((score / @traunch) * @traunch, '###,000,000') 
      , ' - ' , 
      FORMAT((score / @traunch) * @traunch + @traunch - 1, '###,000,000') 
    ) as [Range]
  , FORMAT(MIN(score), 'N0') as [Min]
  , FORMAT(AVG(score), 'N0') as [Avg]
  , FORMAT(MAX(score), 'N0') as [Max]
  , FORMAT(COUNT(score), 'N0') as [Count]
  , FORMAT(SUM(score), 'N0') as [Sum]
FROM scores
GROUP BY score / @traunch
ORDER BY score / @traunch

create table scores (
   user_id int,
   score int
)

select t.range as [score range], count(*) as [number of occurences]
from (
      select user_id,
         case when score >= 0 and score < 10 then '0-9'
         case when score >= 10 and score < 20 then '10-19'
         ...
         else '90-99' as range
     from scores) t
group by t.range

select cast(score/10 as varchar) + '-' + cast(score/10+9 as varchar), 
       count(*)
from scores
group by score/10

在SQL Server 2000上，投票最多的答案都不正确。也许他们用的是另一个版本。

下面是在SQL Server 2000上这两个软件的正确版本。

select t.range as [score range], count(*) as [number of occurences]
from (
  select case  
    when score between 0 and 9 then ' 0- 9'
    when score between 10 and 19 then '10-19'
    else '20-99' end as range
  from scores) t
group by t.range

or

select t.range as [score range], count(*) as [number of occurrences]
from (
      select user_id,
         case when score >= 0 and score< 10 then '0-9'
         when score >= 10 and score< 20 then '10-19'
         else '20-99' end as range
     from scores) t
group by t.range

这将允许您不必指定范围，并且应该与SQL server无关。数学增值!

SELECT CONCAT(range,'-',range+9), COUNT(range)
FROM (
  SELECT 
    score - (score % 10) as range
  FROM scores
)

在postgres中(其中||是字符串连接操作符):

select (score/10)*10 || '-' || (score/10)*10+9 as scorerange, count(*)
from scores
group by score/10
order by 1

给:

 scorerange | count 
------------+-------
 0-9        |    11
 10-19      |    14
 20-29      |     3
 30-39      |     2

下面是如何在T-SQL中做到这一点:

DECLARE @traunch INT = 1000;

SELECT 
    CONCAT
    ( 
      FORMAT((score / @traunch) * @traunch, '###,000,000') 
      , ' - ' , 
      FORMAT((score / @traunch) * @traunch + @traunch - 1, '###,000,000') 
    ) as [Range]
  , FORMAT(MIN(score), 'N0') as [Min]
  , FORMAT(AVG(score), 'N0') as [Avg]
  , FORMAT(MAX(score), 'N0') as [Max]
  , FORMAT(COUNT(score), 'N0') as [Count]
  , FORMAT(SUM(score), 'N0') as [Sum]
FROM scores
GROUP BY score / @traunch
ORDER BY score / @traunch