declare @RangeWidth int

set @RangeWidth = 10

select
   Floor(Score/@RangeWidth) as LowerBound,
   Floor(Score/@RangeWidth)+@RangeWidth as UpperBound,
   Count(*)
From
   ScoreTable
group by
   Floor(Score/@RangeWidth)

select cast(score/10 as varchar) + '-' + cast(score/10+9 as varchar), 
       count(*)
from scores
group by score/10

select t.blah as [score range], count(*) as [number of occurences]
from (
  select case 
    when score between  0 and  9 then ' 0-9 '
    when score between 10 and 19 then '10-19'
    when score between 20 and 29 then '20-29'
    ...
    else '90-99' end as blah
  from scores) t
group by t.blah

如果在MySQL中，请确保使用'range'以外的单词，否则在运行上述示例时会出现错误。

因为要排序的列(Range)是一个字符串，所以使用字符串/单词排序而不是数值排序。

只要字符串有0来填充数字长度，排序在语义上仍然是正确的:

SELECT t.range AS ScoreRange,
       COUNT(*) AS NumberOfOccurrences
  FROM (SELECT CASE
                    WHEN score BETWEEN 0 AND 9 THEN '00-09'
                    WHEN score BETWEEN 10 AND 19 THEN '10-19'
                    ELSE '20-99'
               END AS Range
          FROM Scores) t
 GROUP BY t.Range

如果范围是混合的，简单地填充一个额外的0:

SELECT t.range AS ScoreRange,
       COUNT(*) AS NumberOfOccurrences
  FROM (SELECT CASE
                    WHEN score BETWEEN 0 AND 9 THEN '000-009'
                    WHEN score BETWEEN 10 AND 19 THEN '010-019'
                    WHEN score BETWEEN 20 AND 99 THEN '020-099'
                    ELSE '100-999'
               END AS Range
          FROM Scores) t
 GROUP BY t.Range

select t.range as score, count(*) as Count 
from (
      select UserId,
         case when isnull(score ,0) >= 0 and isnull(score ,0)< 5 then '0-5'
                when isnull(score ,0) >= 5 and isnull(score ,0)< 10 then '5-10'
                when isnull(score ,0) >= 10 and isnull(score ,0)< 15 then '10-15'
                when isnull(score ,0) >= 15 and isnull(score ,0)< 20 then '15-20'               
         else ' 20+' end as range
         ,case when isnull(score ,0) >= 0 and isnull(score ,0)< 5 then 1
                when isnull(score ,0) >= 5 and isnull(score ,0)< 10 then 2
                when isnull(score ,0) >= 10 and isnull(score ,0)< 15 then 3
                when isnull(score ,0) >= 15 and isnull(score ,0)< 20 then 4             
         else 5  end as pd
     from score table
     ) t

group by t.range,pd order by pd

declare @RangeWidth int

set @RangeWidth = 10

select
   Floor(Score/@RangeWidth) as LowerBound,
   Floor(Score/@RangeWidth)+@RangeWidth as UpperBound,
   Count(*)
From
   ScoreTable
group by
   Floor(Score/@RangeWidth)