以下内容会让你更接近目标

class Clazz
{
   public static <U extends Clazz> void doIt(U thing)
   {
   }
}

编辑:更新的例子与更多的细节

public abstract class Thingo 
{

    public static <U extends Thingo> void doIt(U p_thingo)
    {
        p_thingo.thing();
    }

    protected abstract void thing();

}

class SubThingoOne extends Thingo
{
    @Override
    protected void thing() 
    {
        System.out.println("SubThingoOne");
    }
}

class SubThingoTwo extends Thingo
{

    @Override
    protected void thing() 
    {
        System.out.println("SuThingoTwo");
    }

}

public class ThingoTest 
{

    @Test
    public void test() 
    {
        Thingo t1 = new SubThingoOne();
        Thingo t2 = new SubThingoTwo();

        Thingo.doIt(t1);
        Thingo.doIt(t2);

        // compile error -->  Thingo.doIt(new Object());
    }
}

在声明doIt()方法时，可以使用泛型方法的语法来做你想做的事情(注意doIt()方法签名中的static和void之间添加了<T>):

class Clazz<T> {
  static <T> void doIt(T object) {
    // shake that booty
  }
}

我让Eclipse编辑器接受上面的代码，没有Cannot make a static reference to the non-static type T错误，然后将其扩展到以下工作程序(完成一些适合年龄的文化引用):

public class Clazz<T> {
  static <T> void doIt(T object) {
    System.out.println("shake that booty '" + object.getClass().toString()
                       + "' !!!");
  }

  private static class KC {
  }

  private static class SunshineBand {
  }

  public static void main(String args[]) {
    KC kc = new KC();
    SunshineBand sunshineBand = new SunshineBand();
    Clazz.doIt(kc);
    Clazz.doIt(sunshineBand);
  }
}

当我运行它时，它将这些行打印到控制台:

抖抖那个“战利品”类com.eclipseoptions.datamanager。Clazz KC美元”! ! 抖抖那个“战利品”类com.eclipseoptions.datamanager。Clazz SunshineBand美元”! !

错误中正确地提到:您不能对非静态类型T进行静态引用。原因是类型参数T可以被任何类型参数替换，例如Clazz<String>或Clazz<integer>等。但是静态字段/方法由类的所有非静态对象共享。

以下内容摘自纪录片:

A class's static field is a class-level variable shared by all non-static objects of the class. Hence, static fields of type parameters are not allowed. Consider the following class: public class MobileDevice<T> { private static T os; // ... } If static fields of type parameters were allowed, then the following code would be confused: MobileDevice<Smartphone> phone = new MobileDevice<>(); MobileDevice<Pager> pager = new MobileDevice<>(); MobileDevice<TabletPC> pc = new MobileDevice<>(); Because the static field os is shared by phone, pager, and pc, what is the actual type of os? It cannot be Smartphone, Pager, and TabletPC at the same time. You cannot, therefore, create static fields of type parameters.

正如chris在他的回答中正确指出的那样，在这种情况下，你需要与方法一起使用类型参数，而不是与类一起使用。你可以这样写:

static <E> void doIt(E object) 

T不在静态方法的范围内，因此不能在静态方法中使用T。您需要为静态方法定义一个不同的类型参数。我会这样写:

class Clazz<T> {

  static <U> void doIt(U object) {
    // ...
  }

}

例如:

public class Tuple<T> {

    private T[] elements;

    public static <E> Tuple<E> of(E ...args){
        if (args.length == 0) 
             return new Tuple<E>();
        return new Tuple<E>(args);
    }

    //other methods
}

当您为类指定泛型类型时，JVM只知道它是类的实例，而不是定义。每个定义只有参数化类型。

泛型的工作方式类似于c++中的模板，因此您应该首先实例化类，然后使用指定类型的函数。

Also to put it in simple terms, it happens because of the "Erasure" property of the generics.Which means that although we define ArrayList<Integer> and ArrayList<String> , at the compile time it stays as two different concrete types but at the runtime the JVM erases generic types and creates only one ArrayList class instead of two classes. So when we define a static type method or anything for a generic, it is shared by all instances of that generic, in my example it is shared by both ArrayList<Integer> and ArrayList<String> .That's why you get the error.A Generic Type Parameter of a Class Is Not Allowed in a Static Context!