64位double可以精确地表示整数+/- 253。

鉴于这一事实,我选择使用双类型作为我所有类型的单一类型,因为我的最大整数是一个无符号的32位数字。

但现在我必须打印这些伪整数,但问题是它们也和实际的双精度数混合在一起。

那么如何在Java中很好地打印这些double呢?

我试过String。format("%f", value),这很接近,除了我得到了很多小值的末尾零。

下面是%f的输出示例

232.00000000
0.18000000000
1237875192.0
4.5800000000
0.00000000
1.23450000

我想要的是:

232
0.18
1237875192
4.58
0
1.2345

当然,我可以写一个函数来修剪这些零,但由于字符串操作,这是大量的性能损失。我能用其他格式的代码做得更好吗?


Tom E.和Jeremy S.的答案是不可接受的,因为他们都任意舍入到小数点后两位。请先理解问题再回答。


请注意字符串。Format (Format, args…)依赖于语言环境(见下面的答案)。


当前回答

下面这个可以很好地完成工作:

    public static String removeZero(double number) {
        DecimalFormat format = new DecimalFormat("#.###########");
        return format.format(number);
    }

其他回答

简而言之:

如果你想摆脱尾随零和区域问题,那么你应该使用:

double myValue = 0.00000021d;

DecimalFormat df = new DecimalFormat("0", DecimalFormatSymbols.getInstance(Locale.ENGLISH));
df.setMaximumFractionDigits(340); //340 = DecimalFormat.DOUBLE_FRACTION_DIGITS

System.out.println(df.format(myValue)); //output: 0.00000021

解释:

为什么其他答案不适合我:

Double.toString() or System.out.println or FloatingDecimal.toJavaFormatString uses scientific notations if double is less than 10^-3 or greater than or equal to 10^7 double myValue = 0.00000021d; String.format("%s", myvalue); //output: 2.1E-7 by using %f, the default decimal precision is 6, otherwise you can hardcode it, but it results in extra zeros added if you have fewer decimals. Example: double myValue = 0.00000021d; String.format("%.12f", myvalue); // Output: 0.000000210000 by using setMaximumFractionDigits(0); or %.0f you remove any decimal precision, which is fine for integers/longs but not for double double myValue = 0.00000021d; System.out.println(String.format("%.0f", myvalue)); // Output: 0 DecimalFormat df = new DecimalFormat("0"); System.out.println(df.format(myValue)); // Output: 0 by using DecimalFormat, you are local dependent. In the French locale, the decimal separator is a comma, not a point: double myValue = 0.00000021d; DecimalFormat df = new DecimalFormat("0"); df.setMaximumFractionDigits(340); System.out.println(df.format(myvalue)); // Output: 0,00000021 Using the ENGLISH locale makes sure you get a point for decimal separator, wherever your program will run.

为什么使用340然后setMaximumFractionDigits?

两个原因:

setMaximumFractionDigits接受一个整数,但是它的实现有DecimalFormat允许的最大数字。DOUBLE_FRACTION_DIGITS等于340 翻倍。MIN_VALUE = 4.9E-324,因此使用340位数字,您肯定不会四舍五入的双精度和损失精度

我做了一个DoubleFormatter来有效地将大量的double值转换为一个漂亮/像样的字符串:

double horribleNumber = 3598945.141658554548844;
DoubleFormatter df = new DoubleFormatter(4, 6); // 4 = MaxInteger, 6 = MaxDecimal
String beautyDisplay = df.format(horribleNumber);

如果V的整数部分大于MaxInteger =>,则以科学格式(1.2345E+30)显示V。否则,以正常格式(124.45678)显示。 MaxDecimal决定十进制数字的数量(与银行家的四舍五入修剪)

代码如下:

import java.math.RoundingMode;
import java.text.DecimalFormat;
import java.text.DecimalFormatSymbols;
import java.text.NumberFormat;
import java.util.Locale;

import com.google.common.base.Preconditions;
import com.google.common.base.Strings;

/**
 * Convert a double to a beautiful String (US-local):
 *
 * double horribleNumber = 3598945.141658554548844;
 * DoubleFormatter df = new DoubleFormatter(4,6);
 * String beautyDisplay = df.format(horribleNumber);
 * String beautyLabel = df.formatHtml(horribleNumber);
 *
 * Manipulate 3 instances of NumberFormat to efficiently format a great number of double values.
 * (avoid to create an object NumberFormat each call of format()).
 *
 * 3 instances of NumberFormat will be reused to format a value v:
 *
 * if v < EXP_DOWN, uses nfBelow
 * if EXP_DOWN <= v <= EXP_UP, uses nfNormal
 * if EXP_UP < v, uses nfAbove
 *
 * nfBelow, nfNormal and nfAbove will be generated base on the precision_ parameter.
 *
 * @author: DUONG Phu-Hiep
 */
public class DoubleFormatter
{
    private static final double EXP_DOWN = 1.e-3;
    private double EXP_UP; // always = 10^maxInteger
    private int maxInteger_;
    private int maxFraction_;
    private NumberFormat nfBelow_;
    private NumberFormat nfNormal_;
    private NumberFormat nfAbove_;

    private enum NumberFormatKind {Below, Normal, Above}

    public DoubleFormatter(int maxInteger, int maxFraction){
        setPrecision(maxInteger, maxFraction);
    }

    public void setPrecision(int maxInteger, int maxFraction){
        Preconditions.checkArgument(maxFraction>=0);
        Preconditions.checkArgument(maxInteger>0 && maxInteger<17);

        if (maxFraction == maxFraction_ && maxInteger_ == maxInteger) {
            return;
        }

        maxFraction_ = maxFraction;
        maxInteger_ = maxInteger;
        EXP_UP =  Math.pow(10, maxInteger);
        nfBelow_ = createNumberFormat(NumberFormatKind.Below);
        nfNormal_ = createNumberFormat(NumberFormatKind.Normal);
        nfAbove_ = createNumberFormat(NumberFormatKind.Above);
    }

    private NumberFormat createNumberFormat(NumberFormatKind kind) {

        // If you do not use the Guava library, replace it with createSharp(precision);
        final String sharpByPrecision = Strings.repeat("#", maxFraction_);

        NumberFormat f = NumberFormat.getInstance(Locale.US);

        // Apply bankers' rounding:  this is the rounding mode that
        // statistically minimizes cumulative error when applied
        // repeatedly over a sequence of calculations
        f.setRoundingMode(RoundingMode.HALF_EVEN);

        if (f instanceof DecimalFormat) {
            DecimalFormat df = (DecimalFormat) f;
            DecimalFormatSymbols dfs = df.getDecimalFormatSymbols();

            // Set group separator to space instead of comma

            //dfs.setGroupingSeparator(' ');

            // Set Exponent symbol to minus 'e' instead of 'E'
            if (kind == NumberFormatKind.Above) {
                dfs.setExponentSeparator("e+"); //force to display the positive sign in the exponent part
            } else {
                dfs.setExponentSeparator("e");
            }

            df.setDecimalFormatSymbols(dfs);

            // Use exponent format if v is outside of [EXP_DOWN,EXP_UP]

            if (kind == NumberFormatKind.Normal) {
                if (maxFraction_ == 0) {
                    df.applyPattern("#,##0");
                } else {
                    df.applyPattern("#,##0."+sharpByPrecision);
                }
            } else {
                if (maxFraction_ == 0) {
                    df.applyPattern("0E0");
                } else {
                    df.applyPattern("0."+sharpByPrecision+"E0");
                }
            }
        }
        return f;
    }

    public String format(double v) {
        if (Double.isNaN(v)) {
            return "-";
        }
        if (v==0) {
            return "0";
        }
        final double absv = Math.abs(v);

        if (absv<EXP_DOWN) {
            return nfBelow_.format(v);
        }

        if (absv>EXP_UP) {
            return nfAbove_.format(v);
        }

        return nfNormal_.format(v);
    }

    /**
     * Format and higlight the important part (integer part & exponent part)
     */
    public String formatHtml(double v) {
        if (Double.isNaN(v)) {
            return "-";
        }
        return htmlize(format(v));
    }

    /**
     * This is the base alogrithm: create a instance of NumberFormat for the value, then format it. It should
     * not be used to format a great numbers of value
     *
     * We will never use this methode, it is here only to understanding the Algo principal:
     *
     * format v to string. precision_ is numbers of digits after decimal.
     * if EXP_DOWN <= abs(v) <= EXP_UP, display the normal format: 124.45678
     * otherwise display scientist format with: 1.2345e+30
     *
     * pre-condition: precision >= 1
     */
    @Deprecated
    public String formatInefficient(double v) {

        // If you do not use Guava library, replace with createSharp(precision);
        final String sharpByPrecision = Strings.repeat("#", maxFraction_);

        final double absv = Math.abs(v);

        NumberFormat f = NumberFormat.getInstance(Locale.US);

        // Apply bankers' rounding:  this is the rounding mode that
        // statistically minimizes cumulative error when applied
        // repeatedly over a sequence of calculations
        f.setRoundingMode(RoundingMode.HALF_EVEN);

        if (f instanceof DecimalFormat) {
            DecimalFormat df = (DecimalFormat) f;
            DecimalFormatSymbols dfs = df.getDecimalFormatSymbols();

            // Set group separator to space instead of comma

            dfs.setGroupingSeparator(' ');

            // Set Exponent symbol to minus 'e' instead of 'E'

            if (absv>EXP_UP) {
                dfs.setExponentSeparator("e+"); //force to display the positive sign in the exponent part
            } else {
                dfs.setExponentSeparator("e");
            }
            df.setDecimalFormatSymbols(dfs);

            //use exponent format if v is out side of [EXP_DOWN,EXP_UP]

            if (absv<EXP_DOWN || absv>EXP_UP) {
                df.applyPattern("0."+sharpByPrecision+"E0");
            } else {
                df.applyPattern("#,##0."+sharpByPrecision);
            }
        }
        return f.format(v);
    }

    /**
     * Convert "3.1416e+12" to "<b>3</b>.1416e<b>+12</b>"
     * It is a html format of a number which highlight the integer and exponent part
     */
    private static String htmlize(String s) {
        StringBuilder resu = new StringBuilder("<b>");
        int p1 = s.indexOf('.');

        if (p1>0) {
            resu.append(s.substring(0, p1));
            resu.append("</b>");
        } else {
            p1 = 0;
        }

        int p2 = s.lastIndexOf('e');
        if (p2>0) {
            resu.append(s.substring(p1, p2));
            resu.append("<b>");
            resu.append(s.substring(p2, s.length()));
            resu.append("</b>");
        } else {
            resu.append(s.substring(p1, s.length()));
            if (p1==0){
                resu.append("</b>");
            }
        }
        return resu.toString();
    }
}

注意:我使用了Guava库中的两个函数。如果你不使用Guava,你可以自己编码:

/**
 * Equivalent to Strings.repeat("#", n) of the Guava library:
 */
private static String createSharp(int n) {
    StringBuilder sb = new StringBuilder();
    for (int i=0; i<n; i++) {
        sb.append('#');
    }
    return sb.toString();
}
String.format("%.2f", value);

使用给定的十进制长度…

public static String getLocaleFloatValueDecimalWithLength(Locale loc, float value, int length) {
        //make string from float value
        return String.format(loc, (value % 1 == 0 ? "%.0f" : "%."+length+"f"), value);
    }

这是另一个答案,它有一个选项,只有当小数不为零时才附加小数。

   /**
     * Example: (isDecimalRequired = true)
     * d = 12345
     * returns 12,345.00
     *
     * d = 12345.12345
     * returns 12,345.12
     *
     * ==================================================
     * Example: (isDecimalRequired = false)
     * d = 12345
     * returns 12,345 (notice that there's no decimal since it's zero)
     *
     * d = 12345.12345
     * returns 12,345.12
     *
     * @param d float to format
     * @param zeroCount number decimal places
     * @param isDecimalRequired true if it will put decimal even zero,
     * false will remove the last decimal(s) if zero.
     */
    fun formatDecimal(d: Float? = 0f, zeroCount: Int, isDecimalRequired: Boolean = true): String {
        val zeros = StringBuilder()

        for (i in 0 until zeroCount) {
            zeros.append("0")
        }

        var pattern = "#,##0"

        if (zeros.isNotEmpty()) {
            pattern += ".$zeros"
        }

        val numberFormat = DecimalFormat(pattern)

        var formattedNumber = if (d != null) numberFormat.format(d) else "0"

        if (!isDecimalRequired) {
            for (i in formattedNumber.length downTo formattedNumber.length - zeroCount) {
                val number = formattedNumber[i - 1]

                if (number == '0' || number == '.') {
                    formattedNumber = formattedNumber.substring(0, formattedNumber.length - 1)
                } else {
                    break
                }
            }
        }

        return formattedNumber
    }