目前投票的答案是正确的,但它不会在资本化第一个字符之前切断或检查链条的长度。

String.prototype.ucfirst = function(notrim) {
    s = notrim ? this : this.replace(/(?:(?:^|\n)\s+|\s+(?:$|\n))/g,'').replace(/\s+/g,' ');
    return s.length > 0 ? s.charAt(0).toUpperCase() + s.slice(1) : s;
}

设置 notrim 论点,以防止第一条线被推翻:

'pizza'.ucfirst()         => 'Pizza'
'   pizza'.ucfirst()      => 'Pizza'
'   pizza'.ucfirst(true)  => '   pizza'

每个链条的第一个字符都被资本化了。

函数资本化(词){返回词[0].toUpperCase() + word.slice(1).toLowerCase(); } console.log(capitalize(“john”)); //John console.log(capitalize(“BRAVO”)); //Bravo console.log(capitalize(“BLAne”)); //Blane

有一个非常简单的方式来实现它通过替代。

'foo'.replace(/^./, str => str.toUpperCase())

结果:

'Foo'

关于TypeScript

  capitalizeFirstLetter(string) {
    return string.charAt(0).toUpperCase() + string.slice(1);
  }

/*
 * As terse as possible, assuming you're using ES version 6+
 */
var upLetter1=s=>s.replace(/./,m=>m.toUpperCase());

console.log(upLetter1("the quick brown fox jumped over the lazy dog."));
//\\ The quick brown fox jumped over the lazy dog. //\\

string = string.replace(string.charAt(0), string.charAt(0).toUpperCase());