以下操作应该可以工作

soup.find('span', attrs={'class':'totalcount'})

用你的类名替换'totalcount'，用你正在寻找的标签替换'span'。此外，如果类包含多个带空格的名称，只需选择一个并使用即可。

附注:这个函数用给定的条件找到第一个元素。如果你想找到所有的元素，那么将'find'替换为'find_all'。

单

soup.find("form",{"class":"c-login__form"})

多个

res=soup.find_all("input")
for each in res:
    print(each)

CSS选择器

单班第一场比赛

soup.select_one('.stylelistrow')

匹配列表

soup.select('.stylelistrow')

复合类(即与另一个类)

soup.select_one('.stylelistrow.otherclassname')
soup.select('.stylelistrow.otherclassname')

复合类名中的空格，例如class = stylelistrow otherclassname被替换为"."。您可以继续添加类。

类列表(OR -匹配当前的任何一个)

soup.select_one('.stylelistrow, .otherclassname')
soup.select('.stylelistrow, .otherclassname')

类属性，其值包含一个字符串，例如"stylelistrow":

以“style”开头:

[class^=style]

以row结尾

[class$=row]

包含“列表”:

[class*=list]

^， $和*是操作符。更多信息请点击:https://developer.mozilla.org/en-US/docs/Web/CSS/Attribute_selectors

如果你想排除这个类，那么，以anchor tag为例，选择没有这个类的anchor tags:

a:not(.stylelistrow)

你可以在:not()伪类中传递简单、复合和复杂的css选择器列表。见https://facelessuser.github.io/soupsieve/selectors/pseudo-classes/:不是

---

Bs4 4.7.1 +

innerText包含字符串的特定类

soup.select_one('.stylelistrow:contains("some string")')
soup.select('.stylelistrow:contains("some string")')

N.B.

汤式饮料2.1.0 + 2020年12月

NEW: In order to avoid conflicts with future CSS specification changes, non-standard pseudo classes will now start with the :-soup- prefix. As a consequence, :contains() will now be known as :-soup-contains(), though for a time the deprecated form of :contains() will still be allowed with a warning that users should migrate over to :-soup-contains(). NEW: Added new non-standard pseudo class :-soup-contains-own() which operates similar to :-soup-contains() except that it only looks at text nodes directly associated with the currently scoped element and not its descendants.

具有特定子元素的特定类，例如标签

soup.select_one('.stylelistrow:has(a)')
soup.select('.stylelistrow:has(a)')

试着先检查div是否有class属性，就像这样:

soup = BeautifulSoup(sdata)
mydivs = soup.findAll('div')
for div in mydivs:
    if "class" in div:
        if (div["class"]=="stylelistrow"):
            print div

这可以让我访问class属性(在beautifulsoup 4上，与文档所说的相反)。KeyError返回的是一个列表，而不是字典。

for hit in soup.findAll(name='span'):
    print hit.contents[1]['class']

这招对我很管用:

for div in mydivs:
    try:
        clazz = div["class"]
    except KeyError:
        clazz = ""
    if (clazz == "stylelistrow"):
        print div