我认为下面两个函数是最好的方法去检查'如果一个数组是结合或数字'。由于'numeric'可能只表示数字键或顺序数字键，下面列出了两个函数来检查这两种情况:

function is_indexed_array(&$arr) {
  for (reset($arr); is_int(key($arr)); next($arr));
  return is_null(key($arr));
}

function is_sequential_array(&$arr, $base = 0) {
  for (reset($arr), $base = (int) $base; key($arr) === $base++; next($arr));
  return is_null(key($arr));
}

The first function checks if each key is an integer value. The second function checks if each key is an integer value and in addition checks if all keys are sequential starting at $base, which defaults to 0 and thus can be omitted if you do not need to specify another base value. key($my_array) returns null if the read pointer is moved past the end of the array, which is what ends the for loop and makes the statement after the for loop return true if all keys were integer. If not, the loop ends prematurely because a key is of type string, and the statement after the for loop will return false. The latter function in addition adds one to $base after each compare, to be able to check if the next key is of the correct value. The strict compare makes it also check if the key is of type integer. The $base = (int) $base part in the first section of the for loop can be left out when $base is omitted or if you make sure it is only called using an integer. But since I can't be sure for everybody, I left it in. The statement is executed only once, anyway. I think these are the most efficient solutions:

Memory wise: No copying of data or key ranges. Doing an array_values or array_keys may seem shorter (less code) but keep in mind what goes on in the background once you make that call. Yes there are more (visible) statements than in some other solutions, but that is not what counts, is it? Time wise: Besides the fact that copying/extracting data and/or keys also takes time, this solution is more efficient than doing a foreach. Again a foreach may seem more efficient to some because it is shorter in notation, but in the background foreach also calls reset, key and next to do it's looping. But in addition it also calls valid to check the end condition, which is avoided here due to the combination with the integer check.

请记住，数组键只能是整数或字符串，严格的数字字符串，如“1”(但不是“01”)将被转换为整数。如果您希望数组是顺序的，这使得检查整数键成为除了计数之外唯一需要的操作。当然，如果is_indexed_array返回false，则可以将该数组视为关联数组。我说“见过”，因为事实上它们都是。

我已经使用了array_keys($obj) !== range(0, count($obj) - 1)和array_values($arr) !== $arr(它们是彼此的对偶，尽管第二个比第一个更便宜)，但对于非常大的数组都失败了。

这是因为array_keys和array_values都是非常昂贵的操作(因为它们构建了一个大小与原始数组大致相同的全新数组)。

下面的函数比上面提供的方法更健壮:

function array_type( $obj ){
    $last_key = -1;
    $type = 'index';
    foreach( $obj as $key => $val ){
        if( !is_int( $key ) || $key < 0 ){
            return 'assoc';
        }
        if( $key !== $last_key + 1 ){
            $type = 'sparse';
        }
        $last_key = $key;
    }
    return $type;
}

还要注意，如果你不关心区分稀疏数组和关联数组，你可以简单地从两个if块中返回'assoc'。

最后，虽然这可能看起来没有本页上的许多“解决方案”那么“优雅”，但实际上它的效率要高得多。几乎任何关联数组都会立即被检测到。只有索引数组才会被彻底检查，上面列出的方法不仅会彻底检查索引数组，还会复制它们。

除非PHP有这样的内置功能，否则您无法在小于O(n)的时间内完成—枚举所有键并检查整数类型。事实上，你还想确保没有漏洞，所以你的算法可能是这样的:

for i in 0 to len(your_array):
    if not defined(your-array[i]):
        # this is not an array array, it's an associative array :)

但为什么要麻烦呢?只需假设数组是您所期望的类型。如果不是，它就会在你面前爆炸——这就是动态编程!测试你的代码，一切都会很好……

我注意到这个问题有两种常用的方法:一种使用array_values()，另一种使用key()。为了找出哪个更快，我写了一个小程序:

$arrays = Array(
  'Array #1' => Array(1, 2, 3, 54, 23, 212, 123, 1, 1),
  'Array #2' => Array("Stack", 1.5, 20, Array(3.4)),
  'Array #3' => Array(1 => 4, 2 => 2),
  'Array #4' => Array(3.0, "2", 3000, "Stack", 5 => "4"),
  'Array #5' => Array("3" => 4, "2" => 2),
  'Array #6' => Array("0" => "One", 1.0 => "Two", 2 => "Three"),
  'Array #7' => Array(3 => "asdf", 4 => "asdf"),
  'Array #8' => Array("apple" => 1, "orange" => 2),
);

function is_indexed_array_1(Array &$arr) {
  return $arr === array_values($arr);
}

function is_indexed_array_2(Array &$arr) {
  for (reset($arr), $i = 0; key($arr) === $i++; next($arr))
    ;
  return is_null(key($arr));
}

// Method #1
$start = microtime(true);
for ($i = 0; $i < 1000; $i++) {
  foreach ($arrays as $array) {
    $dummy = is_indexed_array_1($array);
  }
}
$end = microtime(true);
echo "Time taken with method #1 = ".round(($end-$start)*1000.0,3)."ms\n";

// Method #2
$start = microtime(true);
for ($i = 0; $i < 1000; $i++) {
  foreach ($arrays as $array) {
    $dummy = is_indexed_array_2($array);
  }
}
$end = microtime(true);
echo "Time taken with method #1 = ".round(($end-$start)*1000.0,3)."ms\n";

该程序在CentOS上的PHP 5.2上的输出如下:

方法#1所花费的时间= 10.745ms 方法#2所花费的时间= 18.239ms

PHP 5.3上的输出产生了类似的结果。显然，使用array_values()要快得多。

function checkAssoc($array){
    return  ctype_digit( implode('', array_keys($array) ) );
}

我的解决方案是获得如下数组的键，并检查是否键不是整数:

private function is_hash($array) {
    foreach($array as $key => $value) {
        return ! is_int($key);
    }
    return false;
}

像下面这样获取哈希数组的array_keys是错误的:

array_keys(array(
       "abc" => "gfb",
       "bdc" => "dbc"
       )
);

将输出:

array(
       0 => "abc",
       1 => "bdc"
)

因此，将它与评分最高的答案中提到的一系列数字进行比较并不是一个好主意。它总是说它是一个哈希数组如果你试着比较键和范围。