我有一个逗号分隔的字符串,我想把它转换成一个数组,这样我就可以遍历它。
有什么内置的功能吗?
例如,我有这个字符串
var str = "January,February,March,April,May,June,July,August,September,October,November,December";
现在我想用逗号将其拆分,然后将其存储在数组中。
我有一个逗号分隔的字符串,我想把它转换成一个数组,这样我就可以遍历它。
有什么内置的功能吗?
例如,我有这个字符串
var str = "January,February,March,April,May,June,July,August,September,October,November,December";
现在我想用逗号将其拆分,然后将其存储在数组中。
当前回答
对于逗号分隔字符串的字符串数组:
let months = ["January","Feb"];
let monthsString = months.join(", ");
其他回答
嗯,拆分是危险的,因为字符串总是可以包含逗号。注意以下事项:
var myArr = "a,b,c,d,e,f,g,','";
result = myArr.split(',');
那么你会怎么解释呢?你希望结果是什么?具有以下内容的数组:
['a', 'b', 'c', 'd', 'e', 'f', 'g', '\'', '\''] or
['a', 'b', 'c', 'd', 'e', 'f', 'g', ',']
即使你逃避逗号,你也会有问题。
我很快就把这件事弄混了:
(function($) {
$.extend({
splitAttrString: function(theStr) {
var attrs = [];
var RefString = function(s) {
this.value = s;
};
RefString.prototype.toString = function() {
return this.value;
};
RefString.prototype.charAt = String.prototype.charAt;
var data = new RefString(theStr);
var getBlock = function(endChr, restString) {
var block = '';
var currChr = '';
while ((currChr != endChr) && (restString.value !== '')) {
if (/'|"/.test(currChr)) {
block = $.trim(block) + getBlock(currChr, restString);
}
else if (/\{/.test(currChr)) {
block = $.trim(block) + getBlock('}', restString);
}
else if (/\[/.test(currChr)) {
block = $.trim(block) + getBlock(']', restString);
}
else {
block += currChr;
}
currChr = restString.charAt(0);
restString.value = restString.value.slice(1);
}
return $.trim(block);
};
do {
var attr = getBlock(',', data);
attrs.push(attr);
}
while (data.value !== '')
;
return attrs;
}
});
})(jQuery);
最短的
str.split`,`
var str=“一月、二月、三月、四月、五月、六月、七月、八月、九月、十月、十一月、十二月”;让arr=str.split`,`;控制台日志(arr);
对于逗号分隔字符串的字符串数组:
let months = ["January","Feb"];
let monthsString = months.join(", ");
var array = string.split(',');
MDN引用,对于极限参数的可能意外行为非常有用。(提示:“a,b,c”.split(“,”,2)指向[“a”,“b”],而不是[“a,”b,c“]。)
let str = "January,February,March,April,May,June,July,August,September,October,November,December"
let arr = str.split(',');
这将导致:
["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
如果要将以下内容转换为:
["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]
这:
"January,February,March,April,May,June,July,August,September,October,November,December";
use:
str = arr.join(',')