let str = "January,February,March,April,May,June,July,August,September,October,November,December"

let arr = str.split(',');

这将导致：

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

如果要将以下内容转换为：

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

这：

"January,February,March,April,May,June,July,August,September,October,November,December";

use:

str = arr.join(',')

下面是一个函数，它将字符串转换为数组，即使列表中只有一项（没有分隔符）：

function listToAray(fullString, separator) {
  var fullArray = [];

  if (fullString !== undefined) {
    if (fullString.indexOf(separator) == -1) {
      fullArray.push(fullString);
    } else {
      fullArray = fullString.split(separator);
    }
  }

  return fullArray;
}

这样使用：

var myString = 'alpha,bravo,charlie,delta';
var myArray = listToArray(myString, ',');
myArray[2]; // charlie

var yourString = 'echo';
var yourArray = listToArray(yourString, ',');
yourArray[0]; // echo

我创建这个函数是因为如果字符串中没有分隔符（只有一个项目），split会抛出一个错误。

正如@oportocala所提到的，空字符串不会产生预期的空数组。

因此，要反击，请执行以下操作：

str
.split(',')
.map(entry => entry.trim())
.filter(entry => entry)

对于预期整数数组，请执行以下操作：

str
.split(',')
.map(entry => parseInt(entry))
.filter(entry => typeof entry ==='number')

嗯，拆分是危险的，因为字符串总是可以包含逗号。注意以下事项：

var myArr = "a,b,c,d,e,f,g,','";
result = myArr.split(',');

那么你会怎么解释呢？你希望结果是什么？具有以下内容的数组：

['a', 'b', 'c', 'd', 'e', 'f', 'g', '\'', '\''] or
['a', 'b', 'c', 'd', 'e', 'f', 'g', ',']

即使你逃避逗号，你也会有问题。

我很快就把这件事弄混了：

(function($) {
    $.extend({
        splitAttrString: function(theStr) {
            var attrs = [];

            var RefString = function(s) {
                this.value = s;
            };
            RefString.prototype.toString = function() {
                return this.value;
            };
            RefString.prototype.charAt = String.prototype.charAt;
            var data = new RefString(theStr);

            var getBlock = function(endChr, restString) {
                var block = '';
                var currChr = '';
                while ((currChr != endChr) && (restString.value !== '')) {
                    if (/'|"/.test(currChr)) {
                        block = $.trim(block) + getBlock(currChr, restString);
                    }
                    else if (/\{/.test(currChr)) {
                        block = $.trim(block) + getBlock('}', restString);
                    }
                    else if (/\[/.test(currChr)) {
                        block = $.trim(block) + getBlock(']', restString);
                    }
                    else {
                        block += currChr;
                    }
                    currChr = restString.charAt(0);
                    restString.value = restString.value.slice(1);
                }
                return $.trim(block);
            };

            do {
                var attr = getBlock(',', data);
                attrs.push(attr);
            }
            while (data.value !== '')
                ;
            return attrs;
        }
    });
})(jQuery);

如果你的目标是整数，比如1,2,3,4,5，请注意。如果要在拆分字符串后将数组元素用作整数而不是字符串，请考虑将它们转换为整数。

var str = "1,2,3,4,5,6";
var temp = new Array();
// This will return an array with strings "1", "2", etc.
temp = str.split(",");

添加这样的循环，

for (a in temp ) {
    temp[a] = parseInt(temp[a], 10); // Explicitly include base as per Álvaro's comment
}

将返回一个包含整数而非字符串的数组。

let str = "January,February,March,April,May,June,July,August,September,October,November,December"

let arr = str.split(',');

这将导致：

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

如果要将以下内容转换为：

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

这：

"January,February,March,April,May,June,July,August,September,October,November,December";

use:

str = arr.join(',')