我有一个逗号分隔的字符串,我想把它转换成一个数组,这样我就可以遍历它。

有什么内置的功能吗?

例如,我有这个字符串

var str = "January,February,March,April,May,June,July,August,September,October,November,December";

现在我想用逗号将其拆分,然后将其存储在数组中。


当前回答

let str = "January,February,March,April,May,June,July,August,September,October,November,December"

let arr = str.split(',');

这将导致:

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

如果要将以下内容转换为:

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

这:

"January,February,March,April,May,June,July,August,September,October,November,December";

use:

str = arr.join(',')

其他回答

let myString = "January,February,March,April,May,June,July,August,September,October,November,December";
      const temp=myString .split(",");
      console.log(temp);

输出:-[“一月”、“二月”、“三月”、“四月”、“五月”、“六月”、“七月”、“八月”、“九月”、“十月”、“十一月”、“十二月”]

非常简单,您可以使用拆分默认javascript函数。

正如@oportocala所提到的,空字符串不会产生预期的空数组。

因此,要反击,请执行以下操作:

str
.split(',')
.map(entry => entry.trim())
.filter(entry => entry)

对于预期整数数组,请执行以下操作:

str
.split(',')
.map(entry => parseInt(entry))
.filter(entry => typeof entry ==='number')

一个很好的解决方案:

let obj = ['A','B','C']

obj.map((c) => { return c. }).join(', ')

最简单的方法:

let myStr = '1, 2, 3, 4, 5, 7, 8';

const stringToArr = (myStr) => {
    return myStr.split(',').map(x => x.trim());
};
let str = "January,February,March,April,May,June,July,August,September,October,November,December"

let arr = str.split(',');

这将导致:

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

如果要将以下内容转换为:

["January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"]

这:

"January,February,March,April,May,June,July,August,September,October,November,December";

use:

str = arr.join(',')