其他人已经回答了我之前的问题，但一个有用的程序打印出所有可用的属性是:

for (Map.Entry<?,?> e : System.getProperties().entrySet()) {
    System.out.println(String.format("%s = %s", e.getKey(), e.getValue())); 
}

System.getProperty("user.home");

参见JavaDoc。

其他人已经回答了我之前的问题，但一个有用的程序打印出所有可用的属性是:

for (Map.Entry<?,?> e : System.getProperties().entrySet()) {
    System.out.println(String.format("%s = %s", e.getKey(), e.getValue())); 
}

The bug you reference (bug 4787391) has been fixed in Java 8. Even if you are using an older version of Java, the System.getProperty("user.home") approach is probably still the best. The user.home approach seems to work in a very large number of cases. A 100% bulletproof solution on Windows is hard, because Windows has a shifting concept of what the home directory means. If user.home isn't good enough for you I would suggest choosing a definition of home directory for windows and using it, getting the appropriate environment variable with System.getenv(String).

替代方案是使用Apache CommonsIO FileUtils.getUserDirectory()而不是System.getProperty("user.home")。它将得到相同的结果，并且在指定系统属性时不会出现输入错误。

您的项目中很有可能已经有Apache CommonsIO库。如果你计划只用它来获取用户主目录，就不要引入它。

如果你想在windows上工作得很好，有一个叫做WinFoldersJava的包，它包装了本机调用来获得windows上的“特殊”目录。我们经常使用它，而且效果很好。