如果你有多个参数，你可以使用

 print('some string {0:.2f} & {1:.2f}'.format(1.1234,2.345))
 >>> some string 1.12 & 2.35

是什么

print round(20.2564567 , 2)    >>>>>>>        20.25


print round(20.2564567 , 4)    >>>>>>>        20.2564

如果你用这个来表示货币，并且还想用's来分隔值，你可以使用's

$ {:, .f2} .format (currency_value)。

例如:

Currency_value = 1234.50

$ {:，.f2}.format(currency_value)——> $ 1,234.50

下面是我不久前写的一段代码:

print(">在年底" + year_string + " total paid is \t$ {:，.2f}".format(total_paid))

> At the end of year   1  total paid is         $ 43,806.36
> At the end of year   2  total paid is         $ 87,612.72
> At the end of year   3  total paid is         $ 131,419.08
> At the end of year   4  total paid is         $ 175,225.44
> At the end of year   5  total paid is         $ 219,031.80   <-- Note .80 and not .8
> At the end of year   6  total paid is         $ 262,838.16
> At the end of year   7  total paid is         $ 306,644.52
> At the end of year   8  total paid is         $ 350,450.88
> At the end of year   9  total paid is         $ 394,257.24
> At the end of year  10  total paid is         $ 438,063.60   <-- Note .60 and not .6
> At the end of year  11  total paid is         $ 481,869.96
> At the end of year  12  total paid is         $ 525,676.32
> At the end of year  13  total paid is         $ 569,482.68
> At the end of year  14  total paid is         $ 613,289.04
> At the end of year  15  total paid is         $ 657,095.40   <-- Note .40 and not .4  
> At the end of year  16  total paid is         $ 700,901.76
> At the end of year  17  total paid is         $ 744,708.12
> At the end of year  18  total paid is         $ 788,514.48
> At the end of year  19  total paid is         $ 832,320.84
> At the end of year  20  total paid is         $ 876,127.20   <-- Note .20 and not .2

这与你可能已经看到的解决方案是一样的，但是这样做会更清楚:

>>> num = 3.141592654

>>> print（f“Number： {num：.2f}”）

>>> print "{:.2f}".format(1.123456)
1.12

你可以把2f中的2改成你想显示的任何小数点。

编辑:

在Python3.6中，它转换为:

>>> print(f"{1.1234:.2f}")
1.12

你可以这样使用字符串格式化操作符:

num = 49
x = "%.2f" % num  # x is now the string "49.00"

我不确定您所说的“高效”是什么意思——这几乎肯定不是应用程序的瓶颈。如果您的程序运行缓慢，请先对其进行分析，以找到热点，然后优化这些热点。