我目前正在使用下面的代码在一个表中插入数据:

<?php

public function saveDetailsCompany()
{
    $post = Input::All();

    $data = new Company;
    $data->nombre = $post['name'];
    $data->direccion = $post['address'];
    $data->telefono = $post['phone'];
    $data->email = $post['email'];
    $data->giro = $post['type'];
    $data->fecha_registro = date("Y-m-d H:i:s");
    $data->fecha_modificacion = date("Y-m-d H:i:s");

    if ($data->save()) {
        return Response::json(array('success' => true), 200);
    }
}

我想返回插入的最后一个ID,但我不知道如何获取它。

亲切的问候!


当前回答

你可以这样做:

$result=app('db')->insert("INSERT INTO table...");

$lastInsertId=app('db')->getPdo()->lastInsertId();

其他回答

在Laravel 5.2中,我会让它尽可能的干净:

public function saveContact(Request $request, Contact $contact)
{
   $create = $contact->create($request->all());
   return response()->json($create->id,  201);
}

保存模型后,初始化实例的id为:

$report = new Report();
$report->user_id = $request->user_id;
$report->patient_id = $request->patient_id;
$report->diseases_id = $request->modality;
$isReportCreated = $report->save();
return $report->id;  // this will return the saved report id

为劳拉***

首先创建一个对象,然后为该对象设置属性值,然后保存对象记录,然后获取最后插入的id。如

$user = new User();        

$user->name = 'John';  

$user->save();

//现在获取最后插入的id

$insertedId = $user->id;

echo $insertedId ;

这在laravel 4.2中是可行的

$id = User::insertGetId([
    'username' => Input::get('username'),
    'password' => Hash::make('password'),
    'active'   => 0
]);

你也可以这样尝试:

public function storeAndLastInrestedId() {
    $data = new ModelName();
    $data->title = $request->title;
    $data->save();

    $last_insert_id = $data->id;
    return $last_insert_id;
}