我的解决方案!

import java.util.HashMap;
import java.util.Map;

public enum MapEnumSample {
    Mustang("One of the fastest cars in the world!"), 
    Mercedes("One of the most beautiful cars in the world!"), 
    Ferrari("Ferrari or Mercedes, which one is the best?");

    private final String description;
    private static Map<String, String> enumMap;

    private MapEnumSample(String description) {
        this.description = description;
    }

    public String getEnumValue() {
        return description;
    }

    public static String getEnumKey(String name) {
        if (enumMap == null) {
            initializeMap();
        }
        return enumMap.get(name);
    }

    private static Map<String, String> initializeMap() {
        enumMap = new HashMap<String, String>();
        for (MapEnumSample access : MapEnumSample.values()) {
            enumMap.put(access.getEnumValue(), access.toString());
        }
        return enumMap;
    }

    public static void main(String[] args) {

        // getting value from Description
        System.out.println(MapEnumSample.getEnumKey("One of the fastest cars in the world!"));

        // getting value from Constant
        System.out.println(MapEnumSample.Mustang.getEnumValue());

        System.out.println(MapEnumSample.getEnumKey("One of the most beautiful cars in the world!"));
        System.out.println(MapEnumSample.Mercedes.getEnumValue());

        // doesnt exist in Enum
        System.out.println("Mustang or Mercedes, which one is the best?");
        System.out.println(MapEnumSample.getEnumKey("Mustang or Mercedes, which one is the best?") == null ? "I don't know!" : "I believe that "
                + MapEnumSample.getEnumKey("Ferrari or Mustang, which one is the best?") + " is the best!.");

        // exists in Enum
        System.out.println("Ferrari or Mercedes, wich one is the best?");
        System.out.println(MapEnumSample.getEnumKey("Ferrari or Mercedes, which one is the best?") == null ? "I don't know!" : "I believe that "
                + MapEnumSample.getEnumKey("Ferrari or Mercedes, which one is the best?") + " is the best!");

    }
}

你可以使用Mode.mode1.name()，但是你通常不需要这样做。

Mode mode =
System.out.println("The mode is "+mode);

您可以为每个枚举值重写toString()方法。

例子:

public enum Country {

  DE {
    @Override
    public String toString() {
      return "Germany";
    }
  },
  IT {
    @Override
    public String toString() {
      return "Italy";
    }
  },
  US {
    @Override
    public String toString() {
      return "United States";
    }
  }

}

用法:

public static void main(String[] args) {
  System.out.println(Country.DE); // Germany
  System.out.println(Country.IT); // Italy
  System.out.println(Country.US); // United States
}

我发现这个更容易防止输入错误:

public enum Modes {
    some-really-long-string,
    mode1,
    mode2,
    mode3;

    String str;

    Modes(){
        this.str = super.name();
    }

    @Override
    @NonNull
    public String toString() {
        return str;
    }

然而，当你需要在log/println上使用String时，或者当java自动编译toString()方法时，这可能会起作用，但在这样的代码行中->

// sample method that require (string,value)
intent.putExtra(Modes.mode1 ,shareElement.getMode()); // java error
// first argument enum does not return value

相反，如上所述，你仍然需要扩展枚举，并在这些情况下使用.name():

intent.putExtra(Modes.mode1.name() ,shareElement.getMode()); 

据我所知，唯一的办法就是

Mode.mode1.name();

然而，如果你真的需要这样做，你可以这样做:

public enum Modes {
    mode1 ("Mode1"),
    mode2 ("Mode2"),
    mode3 ("Mode3");

    private String name;       

    private Modes(String s) {
        name = s;
    }
}

你不能。我认为你有四个选择。这四家公司都提供了解决方案，但方法略有不同。

选项一:在枚举上使用内置name()。如果您不需要任何特殊的命名格式，这是非常好的。

    String name = Modes.mode1.name(); // Returns the name of this enum constant, exactly as declared in its enum declaration.

选项二:如果你想要更多的控制，给你的枚举添加覆盖属性

public enum Modes {
    mode1 ("Fancy Mode 1"),
    mode2 ("Fancy Mode 2"),
    mode3 ("Fancy Mode 3");

    private final String name;       

    private Modes(String s) {
        name = s;
    }

    public boolean equalsName(String otherName) {
        // (otherName == null) check is not needed because name.equals(null) returns false 
        return name.equals(otherName);
    }

    public String toString() {
       return this.name;
    }
}

选项三:使用静态韵母代替枚举:

public final class Modes {

    public static final String MODE_1 = "Fancy Mode 1";
    public static final String MODE_2 = "Fancy Mode 2";
    public static final String MODE_3 = "Fancy Mode 3";

    private Modes() { }
}

选项四:接口的每个字段都是public、static和final:

public interface Modes {

    String MODE_1 = "Fancy Mode 1";
    String MODE_2 = "Fancy Mode 2";
    String MODE_3 = "Fancy Mode 3";  
}