如果您在psql shell中，使用\gexec允许您执行syed的答案和Aur的答案中描述的语法，而无需在外部文本编辑器中手动编辑。

with x (y) as (
    select
        'select count(*), '''||
        tablename||
        ''' as "tablename" from '||
        tablename||' '
    from pg_tables
    where schemaname='public'
)
select
    string_agg(y,' union all '||chr(10)) || ' order by tablename'
from x \gexec

注意，string_agg()既用于分隔所有语句之间的联合，也用于将分隔的数据箭头粉碎为一个单元，以便传递到缓冲区。

\ gexec 将当前查询缓冲区发送到服务器，然后将查询输出的每一行的每一列(如果有的话)视为要执行的SQL语句。

如果您不介意可能过时的数据，您可以访问查询优化器使用的相同统计信息。

喜欢的东西:

SELECT relname, n_tup_ins - n_tup_del as rowcount FROM pg_stat_all_tables;

不确定bash中的答案对您来说是否可以接受，但FWIW…

PGCOMMAND=" psql -h localhost -U fred -d mydb -At -c \"
            SELECT   table_name
            FROM     information_schema.tables
            WHERE    table_type='BASE TABLE'
            AND      table_schema='public'
            \""
TABLENAMES=$(export PGPASSWORD=test; eval "$PGCOMMAND")

for TABLENAME in $TABLENAMES; do
    PGCOMMAND=" psql -h localhost -U fred -d mydb -At -c \"
                SELECT   '$TABLENAME',
                         count(*) 
                FROM     $TABLENAME
                \""
    eval "$PGCOMMAND"
done

摘自我在GregSmith的回答中的评论，使其更具可读性:

with tbl as (
  SELECT table_schema,table_name 
  FROM information_schema.tables
  WHERE table_name not like 'pg_%' AND table_schema IN ('public')
)
SELECT 
  table_schema, 
  table_name, 
  (xpath('/row/c/text()', 
    query_to_xml(format('select count(*) AS c from %I.%I', table_schema, table_name), 
    false, 
    true, 
    '')))[1]::text::int AS rows_n 
FROM tbl ORDER BY 3 DESC;

感谢@ a_horis_with_no_name

如果您在psql shell中，使用\gexec允许您执行syed的答案和Aur的答案中描述的语法，而无需在外部文本编辑器中手动编辑。

with x (y) as (
    select
        'select count(*), '''||
        tablename||
        ''' as "tablename" from '||
        tablename||' '
    from pg_tables
    where schemaname='public'
)
select
    string_agg(y,' union all '||chr(10)) || ' order by tablename'
from x \gexec

注意，string_agg()既用于分隔所有语句之间的联合，也用于将分隔的数据箭头粉碎为一个单元，以便传递到缓冲区。

\ gexec 将当前查询缓冲区发送到服务器，然后将查询输出的每一行的每一列(如果有的话)视为要执行的SQL语句。

简单的两步:(注意:不需要改变任何东西-只是复制粘贴) 1. 创建函数

create function 
cnt_rows(schema text, tablename text) returns integer
as
$body$
declare
  result integer;
  query varchar;
begin
  query := 'SELECT count(1) FROM ' || schema || '.' || tablename;
  execute query into result;
  return result;
end;
$body$
language plpgsql;

2. 运行此查询获取所有表的行数

select sum(cnt_rows) as total_no_of_rows from (select 
  cnt_rows(table_schema, table_name)
from information_schema.tables
where 
  table_schema not in ('pg_catalog', 'information_schema') 
  and table_type='BASE TABLE') as subq;

或 按表获取行数

select
  table_schema,
  table_name, 
  cnt_rows(table_schema, table_name)
from information_schema.tables
where 
  table_schema not in ('pg_catalog', 'information_schema') 
  and table_type='BASE TABLE'
order by 3 desc;