我正在寻找一种方法,为我在Postgres中所有的表找到行数。我知道我可以一次做一张表:
SELECT count(*) FROM table_name;
但我想看看所有表的行数,然后按它排序,以了解所有表的大小。
我正在寻找一种方法,为我在Postgres中所有的表找到行数。我知道我可以一次做一张表:
SELECT count(*) FROM table_name;
但我想看看所有表的行数,然后按它排序,以了解所有表的大小。
当前回答
如果您在psql shell中,使用\gexec允许您执行syed的答案和Aur的答案中描述的语法,而无需在外部文本编辑器中手动编辑。
with x (y) as (
select
'select count(*), '''||
tablename||
''' as "tablename" from '||
tablename||' '
from pg_tables
where schemaname='public'
)
select
string_agg(y,' union all '||chr(10)) || ' order by tablename'
from x \gexec
注意,string_agg()既用于分隔所有语句之间的联合,也用于将分隔的数据箭头粉碎为一个单元,以便传递到缓冲区。
\ gexec 将当前查询缓冲区发送到服务器,然后将查询输出的每一行的每一列(如果有的话)视为要执行的SQL语句。
其他回答
如果您不介意可能过时的数据,您可以访问查询优化器使用的相同统计信息。
喜欢的东西:
SELECT relname, n_tup_ins - n_tup_del as rowcount FROM pg_stat_all_tables;
有三种方法可以得到这种计数,每种方法都有各自的权衡。
If you want a true count, you have to execute the SELECT statement like the one you used against each table. This is because PostgreSQL keeps row visibility information in the row itself, not anywhere else, so any accurate count can only be relative to some transaction. You're getting a count of what that transaction sees at the point in time when it executes. You could automate this to run against every table in the database, but you probably don't need that level of accuracy or want to wait that long.
WITH tbl AS
(SELECT table_schema,
TABLE_NAME
FROM information_schema.tables
WHERE TABLE_NAME not like 'pg_%'
AND table_schema in ('public'))
SELECT table_schema,
TABLE_NAME,
(xpath('/row/c/text()', query_to_xml(format('select count(*) as c from %I.%I', table_schema, TABLE_NAME), FALSE, TRUE, '')))[1]::text::int AS rows_n
FROM tbl
ORDER BY rows_n DESC;
第二种方法指出,统计信息收集器在任何时候大致跟踪有多少行是“活动的”(没有被后来的更新删除或废弃)。这个值在剧烈活动时可能会偏离一点,但通常是一个很好的估计:
SELECT schemaname,relname,n_live_tup
FROM pg_stat_user_tables
ORDER BY n_live_tup DESC;
这还可以显示有多少行已死,这本身就是一个值得监视的有趣数字。
第三种方法是注意到系统ANALYZE命令,从PostgreSQL 8.3开始由autovacuum进程定期执行以更新表统计信息,它也计算行估计。你可以像这样抓取它:
SELECT
nspname AS schemaname,relname,reltuples
FROM pg_class C
LEFT JOIN pg_namespace N ON (N.oid = C.relnamespace)
WHERE
nspname NOT IN ('pg_catalog', 'information_schema') AND
relkind='r'
ORDER BY reltuples DESC;
很难说使用这些查询中哪一个更好。通常,我根据是否有更多有用的信息也想在pg_class中使用,还是在pg_stat_user_tables中使用来做出决定。出于基本的计数目的,只是为了了解事物的总体大小,这两种方法都应该足够准确。
我不记得我收集这个的URL了。但希望这能帮助到你:
CREATE TYPE table_count AS (table_name TEXT, num_rows INTEGER);
CREATE OR REPLACE FUNCTION count_em_all () RETURNS SETOF table_count AS '
DECLARE
the_count RECORD;
t_name RECORD;
r table_count%ROWTYPE;
BEGIN
FOR t_name IN
SELECT
c.relname
FROM
pg_catalog.pg_class c LEFT JOIN pg_namespace n ON n.oid = c.relnamespace
WHERE
c.relkind = ''r''
AND n.nspname = ''public''
ORDER BY 1
LOOP
FOR the_count IN EXECUTE ''SELECT COUNT(*) AS "count" FROM '' || t_name.relname
LOOP
END LOOP;
r.table_name := t_name.relname;
r.num_rows := the_count.count;
RETURN NEXT r;
END LOOP;
RETURN;
END;
' LANGUAGE plpgsql;
执行select count_em_all();应该得到所有表的行数。
下面的查询将给出每个表的行数和大小
选择table_schema, table_name, pg_relation_size('“' | | table_schema | |”“。”“| | table_name | |”“”)/ 1024/1024 size_MB, (xpath('/row/c/text()', query_to_xml(format('select count(*) AS c from %I.)%I', table_schema, table_name), false, true, ")))[1]::text::int AS rows_n 从information_schema.tables order by size_MB
如果您在psql shell中,使用\gexec允许您执行syed的答案和Aur的答案中描述的语法,而无需在外部文本编辑器中手动编辑。
with x (y) as (
select
'select count(*), '''||
tablename||
''' as "tablename" from '||
tablename||' '
from pg_tables
where schemaname='public'
)
select
string_agg(y,' union all '||chr(10)) || ' order by tablename'
from x \gexec
注意,string_agg()既用于分隔所有语句之间的联合,也用于将分隔的数据箭头粉碎为一个单元,以便传递到缓冲区。
\ gexec 将当前查询缓冲区发送到服务器,然后将查询输出的每一行的每一列(如果有的话)视为要执行的SQL语句。