在Kotlin中没有静态关键字。

在Kotlin中表示静态Java方法的最佳方法是什么?


当前回答

对于Android使用从单个活动到所有必要活动的字符串。 就像java中的静态

public final static String TEA_NAME = "TEA_NAME";

Kotlin中的等效方法:

class MainActivity : AppCompatActivity() {
    companion object {
        const val TEA_NAME = "TEA_NAME"
    }
    override fun onCreate(savedInstanceState: Bundle?) {
        super.onCreate(savedInstanceState)
        setContentView(R.layout.activity_main)
    }
}

另一个需要价值的活动是:

val teaName = MainActivity.TEA_NAME

其他回答

简单地使用这种方法

object Foo{
   fun foo() = println("Foo")
   val bar ="bar"  
}

Foo.INSTANCE.foo()

尽管这是2年多一点的现在,并有很多伟大的答案,我看到一些其他的方法得到“静态”Kotlin字段的缺失。下面是Kotlin-Java静态互操作的示例指南:

Scenario 1: Creating a static method in Kotlin for Java Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits class KotlinClass { companion object { //This annotation tells Java classes to treat this method as if it was a static to [KotlinClass] @JvmStatic fun foo(): Int = 1 //Without it, you would have to use [KotlinClass.Companion.bar()] to use this method. fun bar(): Int = 2 } } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinClass.foo()); //Prints "1" println(KotlinClass.Companion.bar()); //Prints "2". This is the only way to use [bar()] in Java. println(KotlinClass.Companion.foo()); //To show that [Companion] is still the holder of the function [foo()] } //Because I'm way to lazy to keep typing [System.out], but I still want this to be compilable. void println(Object o) { System.out.println(o); } }

Michael Anderson的回答提供了更多的深度,在这种情况下绝对应该参考。


下一个场景处理在Kotlin中创建静态字段,这样Java就不必在不需要静态函数的情况下一直调用KotlinClass.foo()。

Scenario 2: Creating a static variable in Kotlin for Java Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits class KotlinClass { companion object { //This annotation tells Kotlin to not generate the getter/setter functions in Java. Instead, this variable should be accessed directly //Also, this is similar to [@JvmStatic], in which it tells Java to treat this as a static variable to [KotlinClass]. @JvmField var foo: Int = 1 //If you want something akin to [final static], and the value is a primitive or a String, you can use the keyword [const] instead //No annotation is needed to make this a field of [KotlinClass]. If the declaration is a non-primitive/non-String, use @JvmField instead const val dog: Int = 1 //This will be treated as a member of the [Companion] object only. It generates the getter/setters for it. var bar: Int = 2 //We can still use [@JvmStatic] for 'var' variables, but it generates getter/setters as functions of KotlinClass //If we use 'val' instead, it only generates a getter function @JvmStatic var cat: Int = 9 } } Java package com.frybits; class JavaClass { void someFunction() { //Example using @JvmField println(KotlinClass.foo); //Prints "1" KotlinClass.foo = 3; //Example using 'const val' println(KotlinClass.dog); //Prints "1". Notice the lack of a getter function //Example of not using either @JvmField, @JvmStatic, or 'const val' println(KotlinClass.Companion.getBar()); //Prints "2" KotlinClass.Companion.setBar(3); //The setter for [bar] //Example of using @JvmStatic instead of @JvmField println(KotlinClass.getCat()); KotlinClass.setCat(0); } void println(Object o) { System.out.println(o); } }


Kotlin的一个伟大特性是您可以创建顶级函数和变量。这使得创建常量字段和函数的“无类”列表变得非常好,而这些列表又可以用作Java中的静态函数/字段。

Scenario 3: Accessing top level fields and functions in Kotlin from Java Kotlin //In this example, the file name is "KSample.kt". If this annotation wasn't provided, all functions and fields would have to accessed //using the name [KSampleKt.foo()] to utilize them in Java. Make life easier for yourself, and name this something more simple @file:JvmName("KotlinUtils") package com.frybits //This can be called from Java as [KotlinUtils.TAG]. This is a final static variable const val TAG = "You're it!" //Since this is a top level variable and not part of a companion object, there's no need to annotate this as "static" to access in Java. //However, this can only be utilized using getter/setter functions var foo = 1 //This lets us use direct access now @JvmField var bar = 2 //Since this is calculated at runtime, it can't be a constant, but it is still a final static variable. Can't use "const" here. val GENERATED_VAL:Long = "123".toLong() //Again, no need for @JvmStatic, since this is not part of a companion object fun doSomethingAwesome() { println("Everything is awesome!") } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinUtils.TAG); //Example of printing [TAG] //Example of not using @JvmField. println(KotlinUtils.getFoo()); //Prints "1" KotlinUtils.setFoo(3); //Example using @JvmField println(KotlinUtils.bar); //Prints "2". Notice the lack of a getter function KotlinUtils.bar = 3; //Since this is a top level variable, no need for annotations to use this //But it looks awkward without the @JvmField println(KotlinUtils.getGENERATED_VAL()); //This is how accessing a top level function looks like KotlinUtils.doSomethingAwesome(); } void println(Object o) { System.out.println(o); } }


另一个值得注意的可以在Java中作为“静态”字段使用的是Kotlin对象类。这些是在第一次使用时惰性实例化的零参数单例类。更多信息可以在这里找到:https://kotlinlang.org/docs/reference/object-declarations.html#object-declarations

但是,要访问单例对象,需要创建一个特殊的INSTANCE对象,处理它和处理Companion一样麻烦。下面是如何在Java中使用注释来给它一种干净的静态感觉:

Scenario 4: Using object classes Kotlin @file:JvmName("KotlinClass") //This provides a name for this file, so it's not defaulted as [KotlinClassKt] in Java package com.frybits object KotlinClass { //No need for the 'class' keyword here. //Direct access to this variable const val foo: Int = 1 //Tells Java this can be accessed directly from [KotlinClass] @JvmStatic var cat: Int = 9 //Just a function that returns the class name @JvmStatic fun getCustomClassName(): String = this::class.java.simpleName + "boo!" //Getter/Setter access to this variable, but isn't accessible directly from [KotlinClass] var bar: Int = 2 fun someOtherFunction() = "What is 'INSTANCE'?" } Java package com.frybits; class JavaClass { void someFunction() { println(KotlinClass.foo); //Direct read of [foo] in [KotlinClass] singleton println(KotlinClass.getCat()); //Getter of [cat] KotlinClass.setCat(0); //Setter of [cat] println(KotlinClass.getCustomClassName()); //Example of using a function of this 'object' class println(KotlinClass.INSTANCE.getBar()); //This is what the singleton would look like without using annotations KotlinClass.INSTANCE.setBar(23); println(KotlinClass.INSTANCE.someOtherFunction()); //Accessing a function in the object class without using annotations } void println(Object o) { System.out.println(o); } }

使用对象表示val/var/方法使静态。你也可以用object代替单例类。如果你想在类内部创建静态,你可以使用companion

object Abc{
     fun sum(a: Int, b: Int): Int = a + b
    }

如果你需要从Java调用它:

int z = Abc.INSTANCE.sum(x,y);

在Kotlin中,忽略INSTANCE。

Kotlin没有任何静态关键字。您可以在Java和Kotlin中使用下面的代码

 object AppHelper {
    @JvmStatic
    fun getAge() : Int = 30
}

Java类调用

AppHelper.getAge();

呼叫Kotlin类

AppHelper.getAge()

它非常适合我。谢谢

很多人提到伴生对象,这是正确的。但是,正如你所知道的,你也可以使用任何类型的对象(使用对象关键字,而不是类),即,

object StringUtils {
    fun toUpper(s: String) : String { ... }
}

像使用java中的静态方法一样使用它:

StringUtils.toUpper("foobar")

That sort of pattern is kind of useless in Kotlin though, one of its strengths is that it gets rid of the need for classes filled with static methods. It is more appropriate to utilize global, extension and/or local functions instead, depending on your use case. Where I work we often define global extension functions in a separate, flat file with the naming convention: [className]Extensions.kt i.e., FooExtensions.kt. But more typically we write functions where they are needed inside their operating class or object.