我有一个JavaScript对象数组:

var objs = [ 
    { first_nom: 'Lazslo', last_nom: 'Jamf'     },
    { first_nom: 'Pig',    last_nom: 'Bodine'   },
    { first_nom: 'Pirate', last_nom: 'Prentice' }
];

如何在JavaScript中按last_nom的值对它们进行排序?

我知道排序(a,b),但这似乎只适用于字符串和数字。是否需要向对象添加toString()方法?


当前回答

此排序功能可用于所有对象排序:

对象deepObject(深度对象)数字数组

您还可以通过传递1,-1作为参数进行升序或降序排序。

Object.defineProperty(Object.prototype,'deepVal'{可枚举:false,可写:true,值:函数(propertyChain){var level=propertyChain.split('.');父项=此项;对于(var i=0;i<levels.length;i++){if(!parent[levels[i]])返回未定义;parent=父[级别[i]];}返回父项;}});函数dynamicSortAll(属性,sortOrders=1){/**默认排序为升序。如果你需要按降序排序传递-1作为参数**/var sortOrder=sortOrders;返回函数(a,b){var result=(属性?((a.deepVal(属性)>b.deepVal(属性))?1:(a.deepVal(属性)<b.deepVal(属性))-1:0):((a>b)?1:(a<b)-1 : 0))返回结果*sortOrder;}}深度对象=[{a: {a:1,b:2,c:3},b: {a:4,b:5,c:6}},{a: {a:3,b:2,c:1},b: {a:6,b:5,c:4}}];let deepobjResult=deepObj.sort(dynamicSortAll('a.a',1))console.log('deepobjResult:'+JSON.stringify(deepojResult))变量obj=[{first_nom:'Lazslo',last_nom:'Jamf'},{first_nom:'猪',last_nom:'Bodine'},{first_nom:'海盗',last_nom:'Prentice'}];let objResult=obj.sort(dynamicSortAll('last_nom',1))console.log('objResult:'+JSON.stringify(objResult))var numericObj=[1,2,3,4,5,6]let numResult=numericObj.sort(dynamicSortAll(null,-1))console.log('numResult:'+JSON.stringify(numResult))let stringSortResult='helloworld'.split('').sort(dynamicSortAll(null,1))console.log('stringSortResult:'+JSON.stringify(stringSortResult))let uniqueStringOrger=[…new Set(stringSortResult)];console.log('uniqueStringOrger:'+JSON.stringify(uniqueStringOrger))

其他回答

编写自己的比较函数非常简单:

function compare( a, b ) {
  if ( a.last_nom < b.last_nom ){
    return -1;
  }
  if ( a.last_nom > b.last_nom ){
    return 1;
  }
  return 0;
}

objs.sort( compare );

或内联(由Marco Demaio转交):

objs.sort((a,b) => (a.last_nom > b.last_nom) ? 1 : ((b.last_nom > a.last_nom) ? -1 : 0))

或简化为数字(由Andre Figueiredo转交):

objs.sort((a,b) => a.last_nom - b.last_nom); // b - a for reverse sort

使用Lodash或Undercore.js,这是小菜一碟:

const sortedList = _.orderBy(objs, [last_nom], [asc]); // Ascending or descending

您还可以创建一个动态排序函数,根据传递的值对对象进行排序:

function dynamicSort(property) {
    var sortOrder = 1;
    if(property[0] === "-") {
        sortOrder = -1;
        property = property.substr(1);
    }
    return function (a,b) {
        /* next line works with strings and numbers, 
         * and you may want to customize it to your needs
         */
        var result = (a[property] < b[property]) ? -1 : (a[property] > b[property]) ? 1 : 0;
        return result * sortOrder;
    }
}

所以你可以有一个这样的对象数组:

var People = [
    {Name: "Name", Surname: "Surname"},
    {Name:"AAA", Surname:"ZZZ"},
    {Name: "Name", Surname: "AAA"}
];

…当你这样做时,它会起作用:

People.sort(dynamicSort("Name"));
People.sort(dynamicSort("Surname"));
People.sort(dynamicSort("-Surname"));

事实上,这已经回答了问题。下面的部分是因为许多人联系我,抱怨它不适用于多个参数。

多个参数

您可以使用下面的函数生成具有多个排序参数的排序函数。

function dynamicSortMultiple() {
    /*
     * save the arguments object as it will be overwritten
     * note that arguments object is an array-like object
     * consisting of the names of the properties to sort by
     */
    var props = arguments;
    return function (obj1, obj2) {
        var i = 0, result = 0, numberOfProperties = props.length;
        /* try getting a different result from 0 (equal)
         * as long as we have extra properties to compare
         */
        while(result === 0 && i < numberOfProperties) {
            result = dynamicSort(props[i])(obj1, obj2);
            i++;
        }
        return result;
    }
}

这将使您能够执行以下操作:

People.sort(dynamicSortMultiple("Name", "-Surname"));

子类化数组

对于我们中能够使用ES6的幸运者,ES6允许扩展本机对象:

class MyArray extends Array {
    sortBy(...args) {
        return this.sort(dynamicSortMultiple(...args));
    }
}

这将实现:

MyArray.from(People).sortBy("Name", "-Surname");

简单答案:

objs.sort((a,b)=>a.last_nom.localeCompare(b.last_nom))

细节:

今天非常简单,您可以将字符串与localeCompare进行比较。正如Mozilla Doc所说:

localeCompare()方法返回一个数字,指示引用字符串在排序顺序上位于给定字符串之前、之后或与给定字符串相同。

    //example1:
    console.log("aaa".localeCompare("aab")); //-1
    console.log("aaa".localeCompare("aaa")); //0
    console.log("aab".localeCompare("aaa")); //1

    //example2:
    const a = 'réservé'; // with accents, lowercase
    const b = 'RESERVE'; // no accents, uppercase

    console.log(a.localeCompare(b));
    // expected output: 1
    console.log(a.localeCompare(b, 'en', { sensitivity: 'base' }));
    // expected output: 0

有关详细信息,请参阅Mozilla doclocaleCompare:

我没有看到任何类似于我的实现。此版本基于施瓦茨变换习惯用法。

function sortByAttribute(array, ...attrs) {
  // Generate an array of predicate-objects containing
  // property getter, and descending indicator
  let predicates = attrs.map(pred => {
    let descending = pred.charAt(0) === '-' ? -1 : 1;
    pred = pred.replace(/^-/, '');
    return {
      getter: o => o[pred],
      descend: descending
    };
  });
  // Schwartzian transform idiom implementation. AKA "decorate-sort-undecorate"
  return array.map(item => {
    return {
      src: item,
      compareValues: predicates.map(predicate => predicate.getter(item))
    };
  })
  .sort((o1, o2) => {
    let i = -1, result = 0;
    while (++i < predicates.length) {
      if (o1.compareValues[i] < o2.compareValues[i])
        result = -1;
      if (o1.compareValues[i] > o2.compareValues[i])
        result = 1;
      if (result *= predicates[i].descend)
        break;
    }
    return result;
  })
  .map(item => item.src);
}

下面是如何使用它的示例:

let games = [
  { name: 'Mashraki',          rating: 4.21 },
  { name: 'Hill Climb Racing', rating: 3.88 },
  { name: 'Angry Birds Space', rating: 3.88 },
  { name: 'Badland',           rating: 4.33 }
];

// Sort by one attribute
console.log(sortByAttribute(games, 'name'));
// Sort by mupltiple attributes
console.log(sortByAttribute(games, '-rating', 'name'));