这个问题有点混乱。时间戳不是UTC -它们是Unix的东西。日期可能是UTC?假设它是，并且如果你使用的是Python 3.2+，那么simple-date使这个问题变得微不足道:

>>> SimpleDate(date(2011,1,1), tz='utc').timestamp
1293840000.0

如果你有年、月和日，你不需要创建日期:

>>> SimpleDate(2011,1,1, tz='utc').timestamp
1293840000.0

如果日期在其他时区(这很重要，因为我们假设是午夜，没有相关的时间):

>>> SimpleDate(date(2011,1,1), tz='America/New_York').timestamp
1293858000.0

[simple-date背后的想法是将所有python的日期和时间收集到一个一致的类中，这样你就可以进行任何转换。例如，它也会向另一个方向发展:

>>> SimpleDate(1293858000, tz='utc').date
datetime.date(2011, 1, 1)

]

遵循python2.7文档，必须使用calendar.timegm()而不是time.mktime()

>>> d = datetime.date(2011,01,01)
>>> datetime.datetime.utcfromtimestamp(calendar.timegm(d.timetuple()))
datetime.datetime(2011, 1, 1, 0, 0)

Assumption 1: You're attempting to convert a date to a timestamp, however since a date covers a 24 hour period, there isn't a single timestamp that represents that date. I'll assume that you want to represent the timestamp of that date at midnight (00:00:00.000). Assumption 2: The date you present is not associated with a particular time zone, however you want to determine the offset from a particular time zone (UTC). Without knowing the time zone the date is in, it isn't possible to calculate a timestamp for a specific time zone. I'll assume that you want to treat the date as if it is in the local system time zone.

首先，您可以使用timetuple()成员将日期实例转换为表示各种时间组件的元组:

dtt = d.timetuple() # time.struct_time(tm_year=2011, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=5, tm_yday=1, tm_isdst=-1)

然后你可以使用time.mktime将其转换为时间戳:

ts = time.mktime(dtt) # 1293868800.0

您可以通过使用epoch时间本身(1970-01-01)测试来验证此方法，在这种情况下，函数应该返回该日期本地时区的时区偏移量:

d = datetime.date(1970,1,1)
dtt = d.timetuple() # time.struct_time(tm_year=1970, tm_mon=1, tm_mday=1, tm_hour=0, tm_min=0, tm_sec=0, tm_wday=3, tm_yday=1, tm_isdst=-1)
ts = time.mktime(dtt) # 28800.0

28800.0是8小时，这对太平洋时区(我所在的时区)来说是正确的。

一个完整的时间字符串包含:

日期 时间 utcoffset [+HHMM或-HHMM]

例如:

0000 == UNIX时间戳:3600

$ python3
>>> from datetime import datetime
>>> from calendar import timegm
>>> tm = '1970-01-01 06:00:00 +0500'
>>> fmt = '%Y-%m-%d %H:%M:%S %z'
>>> timegm(datetime.strptime(tm, fmt).utctimetuple())
3600

注意:

UNIX时间戳是一个浮点数，以UTC标准从epoch开始的秒数表示。

编辑:

$ python3
>>> from datetime import datetime, timezone, timedelta
>>> from calendar import timegm
>>> dt = datetime(1970, 1, 1, 6, 0)
>>> tz = timezone(timedelta(hours=5))
>>> timegm(dt.replace(tzinfo=tz).utctimetuple())
3600

仅适用于unix系统:

>>> import datetime
>>> d = datetime.date(2011, 1, 1)
>>> d.strftime("%s")  # <-- THIS IS THE CODE YOU WANT
'1293832800'

注1:dizzyf注意到这适用于本地化的时区。不要在生产中使用。

注2:Jakub narerbbski指出，这忽略了时区信息，即使是偏移感知datetime (Python 2.7测试)。

使用箭头包:

>>> import arrow
>>> arrow.get(2010, 12, 31).timestamp
1293753600
>>> time.gmtime(1293753600)
time.struct_time(tm_year=2010, tm_mon=12, tm_mday=31, 
    tm_hour=0, tm_min=0, tm_sec=0, 
    tm_wday=4, tm_yday=365, tm_isdst=0)