在我的makefile中,我有一个变量“NDK_PROJECT_PATH”,我的问题是我如何在编译时将它打印出来?
我读了使文件回显“$PATH”字符串,我尝试了:
@echo $(NDK_PROJECT_PATH)
@echo $(value NDK_PROJECT_PATH)
两者都给了我
"build-local.mk:102: *** missing separator. Stop."
有人知道为什么对我没用吗?
在我的makefile中,我有一个变量“NDK_PROJECT_PATH”,我的问题是我如何在编译时将它打印出来?
我读了使文件回显“$PATH”字符串,我尝试了:
@echo $(NDK_PROJECT_PATH)
@echo $(value NDK_PROJECT_PATH)
两者都给了我
"build-local.mk:102: *** missing separator. Stop."
有人知道为什么对我没用吗?
当前回答
如果您只是想要一些输出,则需要单独使用$(info)。你可以在Makefile的任何地方这样做,它会显示这一行何时被求值:
$(info VAR="$(VAR)")
将输出VAR="<值的VAR>"每当make处理该行。这种行为非常依赖于位置,所以你必须确保$(info)展开发生在所有可以修改$(VAR)的事情已经发生之后!
一个更通用的选项是创建一个特殊的规则来打印变量的值。一般来说,规则是在变量赋值之后执行的,因此这将显示实际使用的值。(尽管规则可以改变变量。)良好的格式将有助于阐明变量的设置,而$(flavor)函数将告诉您某个变量的类型。所以在这个规则中:
print-% : ; $(info $* is a $(flavor $*) variable set to [$($*)]) @true
$* expands to the stem that the % pattern matched in the rule. $($*) expands to the value of the variable whose name is given by by $*. The [ and ] clearly delineate the variable expansion. You could also use " and " or similar. $(flavor $*) tells you what kind of variable it is. NOTE: $(flavor) takes a variable name, and not its expansion. So if you say make print-LDFLAGS, you get $(flavor LDFLAGS), which is what you want. $(info text) provides output. Make prints text on its stdout as a side-effect of the expansion. The expansion of $(info) though is empty. You can think of it like @echo, but importantly it doesn't use the shell, so you don't have to worry about shell quoting rules. @true is there just to provide a command for the rule. Without that, make will also output print-blah is up to date. I feel @true makes it more clear that it's meant to be a no-op.
运行它,你得到
$ make print-LDFLAGS
LDFLAGS is a recursive variable set to [-L/Users/...]
其他回答
如果你使用android make (mka) @echo $(NDK_PROJECT_PATH)将不起作用,并给你错误***丢失分隔符。停止。” 如果你想在android make中打印变量,请使用这个答案
NDK_PROJECT_PATH := some_value
$(warning $(NDK_PROJECT_PATH))
这对我很有用
如果我想查看变量值,我通常会返回一个错误。(除非你想看看价值。它将停止执行。)
@echo $(NDK_PROJECT_PATH = $(NDK_PROJECT_PATH))
@echo $(NDK_PROJECT_PATH)是一个很好的方法。 我不认为错误来自这里。 通常,当您键入错误的意图时,会出现此错误:我认为您在应该有制表符的地方有空格。
来自“Mr. Make post” https://www.cmcrossroads.com/article/printing-value-makefile-variable
在Makefile中添加以下规则:
print-% : ; @echo $* = $($*)
然后,如果你想找出makefile变量的值,只需:
make print-VARIABLE
它会返回:
VARIABLE = the_value_of_the_variable
这可以以通用的方式完成,并且在调试复杂的makefile时非常有用。按照在另一个答案中描述的相同技术,您可以将以下内容插入到任何makefile中:
# if the first command line argument is "print"
ifeq ($(firstword $(MAKECMDGOALS)),print)
# take the rest of the arguments as variable names
VAR_NAMES := $(wordlist 2,$(words $(MAKECMDGOALS)),$(MAKECMDGOALS))
# turn them into do-nothing targets
$(eval $(VAR_NAMES):;@:))
# then print them
.PHONY: print
print:
@$(foreach var,$(VAR_NAMES),\
echo '$(var) = $($(var))';)
endif
然后你可以执行“make print”来转储任何变量的值:
$ make print CXXFLAGS
CXXFLAGS = -g -Wall