我想匹配的只是一个URL的根，而不是一个文本字符串的整个URL。考虑到:
http://www.youtube.com/watch?v=ClkQA2Lb_iE
http://youtu.be/ClkQA2Lb_iE
http://www.example.com/12xy45
http://example.com/random
我想让最后2个实例解析到www.example.com或example.com域。
我听说正则表达式很慢，这将是我在页面上的第二个正则表达式，所以如果有办法做到没有正则表达式，请告诉我。
我正在寻找这个解决方案的JS/jQuery版本。
当前回答
解析域——一个非常可靠的轻量级库
NPM安装解析域
const { fromUrl, parseDomain } = require("parse-domain");
示例1
parseDomain(fromUrl("http://www.example.com/12xy45"))
{ type: 'LISTED',
hostname: 'www.example.com',
labels: [ 'www', 'example', 'com' ],
icann:
{ subDomains: [ 'www' ],
domain: 'example',
topLevelDomains: [ 'com' ] },
subDomains: [ 'www' ],
domain: 'example',
topLevelDomains: [ 'com' ] }
示例2
parseDomain(fromUrl("http://subsub.sub.test.ExAmPlE.coM/12xy45"))
{ type: 'LISTED',
hostname: 'subsub.sub.test.example.com',
labels: [ 'subsub', 'sub', 'test', 'example', 'com' ],
icann:
{ subDomains: [ 'subsub', 'sub', 'test' ],
domain: 'example',
topLevelDomains: [ 'com' ] },
subDomains: [ 'subsub', 'sub', 'test' ],
domain: 'example',
topLevelDomains: [ 'com' ] }
Why?
Depending on the use case and volume I strongly recommend against solving this problem yourself using regex or other string manipulation means. The core of this problem is that you need to know all the gtld and cctld suffixes to properly parse url strings into domain and subdomains, these suffixes are regularly updated. This is a solved problem and not one you want to solve yourself (unless you are google or something). Unless you need the hostname or domain name in a pinch don't try and parse your way out of this one.
其他回答
我的代码是这样的。 正则表达式可以有很多种形式，下面是我的测试用例 我认为它更具可扩展性。
function extractUrlInfo(url){ let reg = /^((?<protocol>http[s]?):\/\/)?(?<host>((\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])|[-a-zA-Z0-9@:%._\+~#=]{1,256}\.[a-zA-Z0-9()]{1,6}\b([-a-zA-Z0-9()@:%_\+.~#?&//=]*)))(\:(?<port>[0-9]|[1-9]\d|[1-9]\d{2}|[1-9]\d{3}|[1-5]\d{4}|6[0-4]\d{3}|65[0-4]\d{2}|655[0-2]\d|6553[0-5]))?$/ return reg.exec(url).groups } var url = "https://192.168.1.1:1234" console.log(extractUrlInfo(url)) var url = "https://stackoverflow.com/questions/8498592/extract-hostname-name-from-string" console.log(extractUrlInfo(url))
import URL from 'url';
const pathname = URL.parse(url).path;
console.log(url.replace(pathname, ''));
这样就兼顾了协议。
String.prototype.trim = function(){return his.replace(/^\s+|\s+$/g,"");}
function getHost(url){
if("undefined"==typeof(url)||null==url) return "";
url = url.trim(); if(""==url) return "";
var _host,_arr;
if(-1<url.indexOf("://")){
_arr = url.split('://');
if(-1<_arr[0].indexOf("/")||-1<_arr[0].indexOf(".")||-1<_arr[0].indexOf("\?")||-1<_arr[0].indexOf("\&")){
_arr[0] = _arr[0].trim();
if(0==_arr[0].indexOf("//")) _host = _arr[0].split("//")[1].split("/")[0].trim().split("\?")[0].split("\&")[0];
else return "";
}
else{
_arr[1] = _arr[1].trim();
_host = _arr[1].split("/")[0].trim().split("\?")[0].split("\&")[0];
}
}
else{
if(0==url.indexOf("//")) _host = url.split("//")[1].split("/")[0].trim().split("\?")[0].split("\&")[0];
else return "";
}
return _host;
}
function getHostname(url){
if("undefined"==typeof(url)||null==url) return "";
url = url.trim(); if(""==url) return "";
return getHost(url).split(':')[0];
}
function getDomain(url){
if("undefined"==typeof(url)||null==url) return "";
url = url.trim(); if(""==url) return "";
return getHostname(url).replace(/([a-zA-Z0-9]+.)/,"");
}
解析URL可能很棘手，因为您可以使用端口号和特殊字符。因此，我建议使用parseUri之类的东西来做这个。我怀疑性能不会成为问题，除非您要解析数百个url。
不需要解析字符串，只需将URL作为参数传递给URL构造函数:
const url = 'http://www.youtube.com/watch?v=ClkQA2Lb_iE';
const { hostname } = new URL(url);
console.assert(hostname === 'www.youtube.com');
