我的代码是这样的。 正则表达式可以有很多种形式，下面是我的测试用例 我认为它更具可扩展性。

function extractUrlInfo(url){ let reg = /^((?<protocol>http[s]?):\/\/)?(?<host>((\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])\.(\d{1,2}|1\d\d|2[0-4]\d|25[0-5])|[-a-zA-Z0-9@:%._\+~#=]{1,256}\.[a-zA-Z0-9()]{1,6}\b([-a-zA-Z0-9()@:%_\+.~#?&//=]*)))(\:(?<port>[0-9]|[1-9]\d|[1-9]\d{2}|[1-9]\d{3}|[1-5]\d{4}|6[0-4]\d{3}|65[0-4]\d{2}|655[0-2]\d|6553[0-5]))?$/ return reg.exec(url).groups } var url = "https://192.168.1.1:1234" console.log(extractUrlInfo(url)) var url = "https://stackoverflow.com/questions/8498592/extract-hostname-name-from-string" console.log(extractUrlInfo(url))

一个不用正则表达式的小技巧:

var tmp        = document.createElement ('a');
;   tmp.href   = "http://www.example.com/12xy45";

// tmp.hostname will now contain 'www.example.com'
// tmp.host will now contain hostname and port 'www.example.com:80'

将上述内容包装在如下函数中，您就拥有了从URI中获取域部分的绝佳方法。

function url_domain(data) {
  var    a      = document.createElement('a');
         a.href = data;
  return a.hostname;
}

解析域——一个非常可靠的轻量级库

NPM安装解析域

const { fromUrl, parseDomain } = require("parse-domain");

示例1

parseDomain(fromUrl("http://www.example.com/12xy45"))

{ type: 'LISTED',
  hostname: 'www.example.com',
  labels: [ 'www', 'example', 'com' ],
  icann:
   { subDomains: [ 'www' ],
     domain: 'example',
     topLevelDomains: [ 'com' ] },
  subDomains: [ 'www' ],
  domain: 'example',
  topLevelDomains: [ 'com' ] }

示例2

parseDomain(fromUrl("http://subsub.sub.test.ExAmPlE.coM/12xy45"))

{ type: 'LISTED',
  hostname: 'subsub.sub.test.example.com',
  labels: [ 'subsub', 'sub', 'test', 'example', 'com' ],
  icann:
   { subDomains: [ 'subsub', 'sub', 'test' ],
     domain: 'example',
     topLevelDomains: [ 'com' ] },
  subDomains: [ 'subsub', 'sub', 'test' ],
  domain: 'example',
  topLevelDomains: [ 'com' ] }

Why?

Depending on the use case and volume I strongly recommend against solving this problem yourself using regex or other string manipulation means. The core of this problem is that you need to know all the gtld and cctld suffixes to properly parse url strings into domain and subdomains, these suffixes are regularly updated. This is a solved problem and not one you want to solve yourself (unless you are google or something). Unless you need the hostname or domain name in a pinch don't try and parse your way out of this one.

如果你在这个页面结束，你正在寻找最好的正则表达式的url试试这个:

^(?:https?:)?(?:\/\/)?([^\/\?]+)

https://regex101.com/r/pX5dL9/1

你可以像下面这样使用它，也可以用不区分大小写的方式来匹配HTTPS和HTTP:

const match = str.match(/^(?:https?:)?(?:\/\/)?([^\/\?]+)/i);
const hostname = match && match[1];

它适用于url没有http://，与http，与https，与只是//和不抓取路径和查询路径以及。

祝你好运

只需使用URL()构造函数:

new URL(url).host

我个人对这个解决方案做了很多研究，我能找到的最好的解决方案实际上来自CloudFlare的“浏览器检查”:

function getHostname(){  
            secretDiv = document.createElement('div');
            secretDiv.innerHTML = "<a href='/'>x</a>";
            secretDiv = secretDiv.firstChild.href;
            var HasHTTPS = secretDiv.match(/https?:\/\//)[0];
            secretDiv = secretDiv.substr(HasHTTPS.length);
            secretDiv = secretDiv.substr(0, secretDiv.length - 1);
            return(secretDiv);  
}  

getHostname();

我重写了变量，使它更“人类”可读，但它比预期的工作做得更好。