我想匹配的只是一个URL的根,而不是一个文本字符串的整个URL。考虑到:

http://www.youtube.com/watch?v=ClkQA2Lb_iE
http://youtu.be/ClkQA2Lb_iE
http://www.example.com/12xy45
http://example.com/random

我想让最后2个实例解析到www.example.com或example.com域。

我听说正则表达式很慢,这将是我在页面上的第二个正则表达式,所以如果有办法做到没有正则表达式,请告诉我。

我正在寻找这个解决方案的JS/jQuery版本。


当前回答

好吧,我知道这是一个老问题,但我做了一个超级高效的url解析器,所以我想我要分享它。

如你所见,这个函数的结构很奇怪,但这是为了提高效率。不使用原型函数,字符串迭代次数不超过一次,处理字符的次数也不超过必要的次数。

function getDomain(url) {
    var dom = "", v, step = 0;
    for(var i=0,l=url.length; i<l; i++) {
        v = url[i]; if(step == 0) {
            //First, skip 0 to 5 characters ending in ':' (ex: 'https://')
            if(i > 5) { i=-1; step=1; } else if(v == ':') { i+=2; step=1; }
        } else if(step == 1) {
            //Skip 0 or 4 characters 'www.'
            //(Note: Doesn't work with www.com, but that domain isn't claimed anyway.)
            if(v == 'w' && url[i+1] == 'w' && url[i+2] == 'w' && url[i+3] == '.') i+=4;
            dom+=url[i]; step=2;
        } else if(step == 2) {
            //Stop at subpages, queries, and hashes.
            if(v == '/' || v == '?' || v == '#') break; dom += v;
        }
    }
    return dom;
}

其他回答

只需使用URL()构造函数:

new URL(url).host

一个不用正则表达式的小技巧:

var tmp        = document.createElement ('a');
;   tmp.href   = "http://www.example.com/12xy45";

// tmp.hostname will now contain 'www.example.com'
// tmp.host will now contain hostname and port 'www.example.com:80'

将上述内容包装在如下函数中,您就拥有了从URI中获取域部分的绝佳方法。

function url_domain(data) {
  var    a      = document.createElement('a');
         a.href = data;
  return a.hostname;
}

解析URL可能很棘手,因为您可以使用端口号和特殊字符。因此,我建议使用parseUri之类的东西来做这个。我怀疑性能不会成为问题,除非您要解析数百个url。

所有url属性,没有依赖,没有JQuery,容易理解

这个解决方案给了你的答案和额外的性质。不需要JQuery或其他依赖,粘贴和走。

使用

getUrlParts("https://news.google.com/news/headlines/technology.html?ned=us&hl=en")

输出

{
  "origin": "https://news.google.com",
  "domain": "news.google.com",
  "subdomain": "news",
  "domainroot": "google.com",
  "domainpath": "news.google.com/news/headlines",
  "tld": ".com",
  "path": "news/headlines/technology.html",
  "query": "ned=us&hl=en",
  "protocol": "https",
  "port": 443,
  "parts": [
    "news",
    "google",
    "com"
  ],
  "segments": [
    "news",
    "headlines",
    "technology.html"
  ],
  "params": [
    {
      "key": "ned",
      "val": "us"
    },
    {
      "key": "hl",
      "val": "en"
    }
  ]
}

代码 代码设计得很容易理解,而不是超级快。每秒可以轻松调用100次,因此它非常适合前端或少量服务器使用,但不适用于高容量吞吐量。

function getUrlParts(fullyQualifiedUrl) {
    var url = {},
        tempProtocol
    var a = document.createElement('a')
    // if doesn't start with something like https:// it's not a url, but try to work around that
    if (fullyQualifiedUrl.indexOf('://') == -1) {
        tempProtocol = 'https://'
        a.href = tempProtocol + fullyQualifiedUrl
    } else
        a.href = fullyQualifiedUrl
    var parts = a.hostname.split('.')
    url.origin = tempProtocol ? "" : a.origin
    url.domain = a.hostname
    url.subdomain = parts[0]
    url.domainroot = ''
    url.domainpath = ''
    url.tld = '.' + parts[parts.length - 1]
    url.path = a.pathname.substring(1)
    url.query = a.search.substr(1)
    url.protocol = tempProtocol ? "" : a.protocol.substr(0, a.protocol.length - 1)
    url.port = tempProtocol ? "" : a.port ? a.port : a.protocol === 'http:' ? 80 : a.protocol === 'https:' ? 443 : a.port
    url.parts = parts
    url.segments = a.pathname === '/' ? [] : a.pathname.split('/').slice(1)
    url.params = url.query === '' ? [] : url.query.split('&')
    for (var j = 0; j < url.params.length; j++) {
        var param = url.params[j];
        var keyval = param.split('=')
        url.params[j] = {
            'key': keyval[0],
            'val': keyval[1]
        }
    }
    // domainroot
    if (parts.length > 2) {
        url.domainroot = parts[parts.length - 2] + '.' + parts[parts.length - 1];
        // check for country code top level domain
        if (parts[parts.length - 1].length == 2 && parts[parts.length - 1].length == 2)
            url.domainroot = parts[parts.length - 3] + '.' + url.domainroot;
    }
    // domainpath (domain+path without filenames) 
    if (url.segments.length > 0) {
        var lastSegment = url.segments[url.segments.length - 1]
        var endsWithFile = lastSegment.indexOf('.') != -1
        if (endsWithFile) {
            var fileSegment = url.path.indexOf(lastSegment)
            var pathNoFile = url.path.substr(0, fileSegment - 1)
            url.domainpath = url.domain
            if (pathNoFile)
                url.domainpath = url.domainpath + '/' + pathNoFile
        } else
            url.domainpath = url.domain + '/' + url.path
    } else
        url.domainpath = url.domain
    return url
}

jquery Oneline

$('<a>').attr('href', document.location.href).prop('hostname');