我有一个SQL SELECT查询，也使用GROUP BY， 我想统计GROUP BY子句过滤结果集后的所有记录。
有什么方法可以直接用SQL做到这一点吗?例如，如果我有用户表，想要选择不同的城镇和用户总数:
SELECT `town`, COUNT(*)
FROM `user`
GROUP BY `town`;
我想有一个列的所有城镇和另一个与用户的数量在所有行。
一个有3个镇和58个用户的结果的例子是:
| Town | Count |
|---|---|
| Copenhagen | 58 |
| New York | 58 |
| Athens | 58 |
当前回答
在Oracle中，你可以使用分析函数:
select town, count(town), sum(count(town)) over () total_count from user
group by town
你的其他选择是使用子查询:
select town, count(town), (select count(town) from user) as total_count from user
group by town
其他回答
如果你想使用Select All Query With Count选项，试试这个…
select a.*, (Select count(b.name) from table_name as b where Condition) as totCount from table_name as a where where Condition
试试下面的代码:
select ccode, count(empno)
from company_details
group by ccode;
如果你想选择城镇和总用户数量，你可以使用下面的查询:
SELECT Town, (SELECT Count(*) FROM User) `Count` FROM user GROUP BY Town;
你可以使用COUNT(DISTINCT…):
SELECT COUNT(DISTINCT town)
FROM user
我知道这是一个旧的帖子，在SQL Server:
select isnull(town,'TOTAL') Town, count(*) cnt
from user
group by town WITH ROLLUP
Town cnt
Copenhagen 58
NewYork 58
Athens 58
TOTAL 174
