我试图使用HttpUrlConnection为我的请求添加头,但方法setRequestProperty()似乎不工作。服务器端没有收到任何带有我头部的请求。

HttpURLConnection hc;
    try {
        String authorization = "";
        URL address = new URL(url);
        hc = (HttpURLConnection) address.openConnection();


        hc.setDoOutput(true);
        hc.setDoInput(true);
        hc.setUseCaches(false);

        if (username != null && password != null) {
            authorization = username + ":" + password;
        }

        if (authorization != null) {
            byte[] encodedBytes;
            encodedBytes = Base64.encode(authorization.getBytes(), 0);
            authorization = "Basic " + encodedBytes;
            hc.setRequestProperty("Authorization", authorization);
        }

当前回答

如果您正在使用Java 8,请使用下面的代码。

URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;

String basicAuth = Base64.getEncoder().encodeToString((username+":"+password).getBytes(StandardCharsets.UTF_8));
httpConn.setRequestProperty ("Authorization", "Basic "+basicAuth);

其他回答

步骤1:获取HttpURLConnection对象

URL url = new URL(urlToConnect);
HttpURLConnection httpUrlConnection = (HttpURLConnection) url.openConnection();

步骤2:使用setRequestProperty方法向HttpURLConnection添加头信息。

Map<String, String> headers = new HashMap<>();

headers.put("X-CSRF-Token", "fetch");
headers.put("content-type", "application/json");

for (String headerKey : headers.keySet()) {
    httpUrlConnection.setRequestProperty(headerKey, headers.get(headerKey));
}

参考链接

最后这对我有用

private String buildBasicAuthorizationString(String username, String password) {

    String credentials = username + ":" + password;
    return "Basic " + new String(Base64.encode(credentials.getBytes(), Base64.NO_WRAP));
}

如果您正在使用Java 8,请使用下面的代码。

URLConnection connection = url.openConnection();
HttpURLConnection httpConn = (HttpURLConnection) connection;

String basicAuth = Base64.getEncoder().encodeToString((username+":"+password).getBytes(StandardCharsets.UTF_8));
httpConn.setRequestProperty ("Authorization", "Basic "+basicAuth);

这对我很管用。 我必须将请求发送给另一只手,并通过POST传输头部“授权”+ jwt和一些参数。另一方面,我们用参数和头组成了jettyRequest。如果我发送以下代码序列:

URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestMethod("POST");
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
// some code add params

然后我只收到一个身体的参数。 如果我发送这个:

URL url = new URL(serviceURL);
HttpURLConnection myURLConnection = (HttpURLConnection)url.openConnection();
myURLConnection.setRequestProperty ("Authorization", jwt); // <---- this place
myURLConnection.setRequestMethod("POST");
// some code add params

然后我收到头授权和参数。

只是因为我在上面的答案中没有看到这一点信息,最初发布的代码片段不能正确工作的原因是因为encodedBytes变量是一个字节[]而不是一个字符串值。如果将字节[]传递给一个新的String(),如下所示,代码段将完美地工作。

encodedBytes = Base64.encode(authorization.getBytes(), 0);
authorization = "Basic " + new String(encodedBytes);