这是我的webpack.config.js

var webpack = require("webpack");

module.exports = {

  entry: "./entry.js",
  devtool: "source-map",
  output: {
    path: "./dist",
    filename: "bundle.min.js"
  },
  plugins: [
    new webpack.optimize.UglifyJsPlugin({minimize: true})
  ]
};

我用

$ webpack

在dist文件夹里,我只得到

bundle.min.js bundle.min.js.map

我还想看看未压缩的bundle.js


当前回答

我也有同样的问题,必须满足以下所有要求:

缩小版+非缩小版(如问题所示) ES6 跨平台(Windows + Linux)。

我最终解决如下:

webpack.config.js:

const path = require('path');
const MinifyPlugin = require("babel-minify-webpack-plugin");

module.exports = getConfiguration;

function getConfiguration(env) {
    var outFile;
    var plugins = [];
    if (env === 'prod') {
        outFile = 'mylib.dev';
        plugins.push(new MinifyPlugin());
    } else {
        if (env !== 'dev') {
            console.log('Unknown env ' + env + '. Defaults to dev');
        }
        outFile = 'mylib.dev.debug';
    }

    var entry = {};
    entry[outFile] = './src/mylib-entry.js';

    return {
        entry: entry,
        plugins: plugins,
        output: {
            filename: '[name].js',
            path: __dirname
        }
    };
}

package.json:

{
    "name": "mylib.js",
    ...
    "scripts": {
        "build": "npm-run-all webpack-prod webpack-dev",
        "webpack-prod": "npx webpack --env=prod",
        "webpack-dev": "npx webpack --env=dev"
    },
    "devDependencies": {
        ...
        "babel-minify-webpack-plugin": "^0.2.0",
        "npm-run-all": "^4.1.2",
        "webpack": "^3.10.0"
    }
}

然后我可以通过(不要忘记npm install之前):

npm run-script build

其他回答

根据这一行:https://github.com/pingyuanChen/webpack-uglify-js-plugin/blob/master/index.js#L117

应该是这样的:

var webpack = require("webpack");

module.exports = {

  entry: "./entry.js",
  devtool: "source-map",
  output: {
    path: "./dist",
    filename: "bundle.js"
  },
  plugins: [
    new webpack.optimize.UglifyJsPlugin({
     minimize: true,
     compress: false
    })
  ]
};

实际上,通过根据env / argv策略导出不同的配置,您可以拥有多个构建。

webpack.config.js:

const webpack = require("webpack");

module.exports = {
  entry: {
    "bundle": "./entry.js",
    "bundle.min": "./entry.js",
  },
  devtool: "source-map",
  output: {
    path: "./dist",
    filename: "[name].js"
  },
  plugins: [
    new webpack.optimize.UglifyJsPlugin({
      include: /\.min\.js$/,
      minimize: true
    })
  ]
};

从Webpack 4开始,Webpack .optimize. uglifyjsplugin已被弃用,使用它会导致错误:

webpack.optimize.UglifyJsPlugin已被删除,请使用config.optimization.minimize代替

正如手册解释的那样,插件可以用最小化选项代替。自定义配置可以通过指定UglifyJsPlugin实例提供给插件:

const webpack = require("webpack");
const UglifyJsPlugin = require('uglifyjs-webpack-plugin');

module.exports = {
  // ...
  optimization: {
    minimize: true,
    minimizer: [new UglifyJsPlugin({
      include: /\.min\.js$/
    })]
  }
};

这是一个简单的设置。一个更有效的解决方案是同时使用Gulp和Webpack,一次完成同样的事情。

你可以在webpack配置中定义两个入口点,一个用于普通js,另一个用于迷你js。然后你应该输出你的bundle和它的名字,并配置UglifyJS插件来包含min.js文件。请参阅webpack配置示例了解更多细节:

module.exports = {
 entry: {
   'bundle': './src/index.js',
   'bundle.min': './src/index.js',
 },

 output: {
   path: path.resolve(__dirname, 'dist'),
   filename: "[name].js"
 },

 plugins: [
   new webpack.optimize.UglifyJsPlugin({
      include: /\.min\.js$/,
      minimize: true
   })
 ]
};

运行webpack后,你会在dist文件夹中得到bundle.js和bundle.min.js,不需要额外的插件。

你可以为webpack创建两个配置,一个可以减少代码,另一个则不能(只需删除优化)。然后同时运行两个配置$ webpack && webpack——config webpack.config.min.js

你可以使用一个配置文件,并使用一个环境变量有条件地包含UglifyJS插件:

const webpack = require('webpack');
const TerserPlugin = require('terser-webpack-plugin');

const PROD = JSON.parse(process.env.PROD_ENV || '0');

module.exports = {

  entry: './entry.js',
  devtool: 'source-map',
  output: {
    path: './dist',
    filename: PROD ? 'bundle.min.js' : 'bundle.js'
  },
  optimization: {
    minimize: PROD,
    minimizer: [
      new TerserPlugin({ parallel: true })
  ]
};

然后当你想缩小它时,设置这个变量:

$ PROD_ENV=1 webpack

编辑:

正如评论中提到的,通常使用NODE_ENV(按照约定)来说明特定环境是生产环境还是开发环境。要检查它,你也可以设置const PROD = (process.env。NODE_ENV === 'production'),然后正常继续。