如果我有以下对象数组:

[ { id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 2, username: 'ted' } ]

是否有一种方法通过数组循环检查特定的用户名值是否已经存在,如果它不做任何事情,但如果它没有添加一个新对象到数组的用户名(和新ID)?

谢谢!


当前回答

极大地简化了我之前的解决方案,并通过在检查指定ID是否存在之前无需遍历整个数组来提供更好的性能。

这应该是最简单的解决方案(我认为):

const users = [{ id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 3, username: 'ted' }];
const addUser = (username) => {
  const user = users.find((user) => user.username === username);
  if (user) return { ...user, new: false };
  const newUser = {
    id: users.length + 1,
    username,
  };
  users.push(newUser);
  return { ...newUser, new: true };
};

下面是一个活生生的例子:

const users = [{ id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 3, username: 'ted' }]; const addUser = (username) => { const user = users.find((user) => user.username === username); if (user) return { ...user, new: false }; const newUser = { id: users.length + 1, username, }; users.push(newUser); return { ...newUser, new: true }; }; // a little extra scripting here to support the input and button in the example const form = document.querySelector('form'); const input = document.querySelector('input'); const span = document.querySelector('span'); const pre = document.querySelector('pre'); const syncDataWithPre = () => { pre.innerHTML = JSON.stringify(users, null, 2); }; form.onsubmit = (e) => { e.preventDefault(); span.textContent = ''; if (input.value) { const user = addUser(input.value); const { new: isNew, ...userDetails } = user; span.classList[isNew ? 'add' : 'remove']('new'); span.textContent = `User ${isNew ? 'added' : 'already exists'}`; } input.value = ''; syncDataWithPre(); }; syncDataWithPre(); body { font-family: arial, sans-serif; } span { display: block; padding-top: 8px; font-weight: 700; color: #777; } span:empty { display: none; } .new { color: #0a0; } .existing: { color: #777; } <form> <input placeholder="New username" /> <button>Add user</button> </form> <span></span> <pre></pre>

其他回答

Lodash中的xorWith可以用来实现这一点

let objects = [ { id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 2, username: 'ted' } ]
let existingObject = { id: 1, username: 'fred' };
let newObject = { id: 1729, username: 'Ramanujan' }

_.xorWith(objects, [existingObject], _.isEqual)
// returns [ { id: 2, username: 'bill' }, { id: 2, username: 'ted' } ]

_.xorWith(objects, [newObject], _.isEqual)
// returns [ { id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 2, username: 'ted' } ,{ id: 1729, username: 'Ramanujan' } ]

检查现有的用户名相当简单:

var arr = [{ id: 1, username: 'fred' }, 
  { id: 2, username: 'bill'}, 
  { id: 3, username: 'ted' }];

function userExists(username) {
  return arr.some(function(el) {
    return el.username === username;
  }); 
}

console.log(userExists('fred')); // true
console.log(userExists('bred')); // false

但是当你必须向这个数组中添加一个新用户时,要做什么就不那么明显了。最简单的方法-只是推入一个id等于array的新元素。长度+ 1:

function addUser(username) {
  if (userExists(username)) {
    return false; 
  }
  arr.push({ id: arr.length + 1, username: username });
  return true;
}

addUser('fred'); // false
addUser('bred'); // true, user `bred` added

它将保证id的唯一性,但如果将一些元素从数组末尾删除,则会使该数组看起来有点奇怪。

假设我们有一个对象数组,你想检查value of name是否像这样定义,

let persons = [ {"name" : "test1"},{"name": "test2"}];

if(persons.some(person => person.name == 'test1')) {
    ... here your code in case person.name is defined and available
}

这是我在@sagar-gavhane的回答之外所做的

const newUser = {_id: 4, name: 'Adam'}
const users = [{_id: 1, name: 'Fred'}, {_id: 2, name: 'Ted'}, {_id: 3, name:'Bill'}]

const userExists = users.some(user => user.name === newUser.name);
if(userExists) {
    return new Error({error:'User exists'})
}
users.push(newUser)

我假设这里的id是唯一的。Find是一个很棒的数组方法,用于检查数组中是否存在东西:

Const arr = [{id: 1,用户名:'fred'}, {id: 2,用户名:'bill'}, {id: 3,用户名:'ted'}]; 函数add(arr, name) { Const {length} = arr; Const id =长度+ 1; Const found = arr。求(el => el。用户名=== name); 如果(!发现)arr。推送({id,用户名:name}); 返回arr; } console.log(添加(arr“ted”)); console.log(添加(加勒比海盗,“黛西”));