检查现有的用户名相当简单:

var arr = [{ id: 1, username: 'fred' }, 
  { id: 2, username: 'bill'}, 
  { id: 3, username: 'ted' }];

function userExists(username) {
  return arr.some(function(el) {
    return el.username === username;
  }); 
}

console.log(userExists('fred')); // true
console.log(userExists('bred')); // false

但是当你必须向这个数组中添加一个新用户时，要做什么就不那么明显了。最简单的方法-只是推入一个id等于array的新元素。长度+ 1:

function addUser(username) {
  if (userExists(username)) {
    return false; 
  }
  arr.push({ id: arr.length + 1, username: username });
  return true;
}

addUser('fred'); // false
addUser('bred'); // true, user `bred` added

它将保证id的唯一性，但如果将一些元素从数组末尾删除，则会使该数组看起来有点奇怪。

极大地简化了我之前的解决方案，并通过在检查指定ID是否存在之前无需遍历整个数组来提供更好的性能。

这应该是最简单的解决方案(我认为):

const users = [{ id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 3, username: 'ted' }];
const addUser = (username) => {
  const user = users.find((user) => user.username === username);
  if (user) return { ...user, new: false };
  const newUser = {
    id: users.length + 1,
    username,
  };
  users.push(newUser);
  return { ...newUser, new: true };
};

下面是一个活生生的例子:

const users = [{ id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 3, username: 'ted' }]; const addUser = (username) => { const user = users.find((user) => user.username === username); if (user) return { ...user, new: false }; const newUser = { id: users.length + 1, username, }; users.push(newUser); return { ...newUser, new: true }; }; // a little extra scripting here to support the input and button in the example const form = document.querySelector('form'); const input = document.querySelector('input'); const span = document.querySelector('span'); const pre = document.querySelector('pre'); const syncDataWithPre = () => { pre.innerHTML = JSON.stringify(users, null, 2); }; form.onsubmit = (e) => { e.preventDefault(); span.textContent = ''; if (input.value) { const user = addUser(input.value); const { new: isNew, ...userDetails } = user; span.classList[isNew ? 'add' : 'remove']('new'); span.textContent = `User ${isNew ? 'added' : 'already exists'}`; } input.value = ''; syncDataWithPre(); }; syncDataWithPre(); body { font-family: arial, sans-serif; } span { display: block; padding-top: 8px; font-weight: 700; color: #777; } span:empty { display: none; } .new { color: #0a0; } .existing: { color: #777; } <form> <input placeholder="New username" /> <button>Add user</button> </form> <span></span> <pre></pre>

function number_present_or_not() {
  var arr = [2, 5, 9, 67, 78, 8, 454, 4, 6, 79, 64, 688];
  var found = 6;
  var found_two;
  for (i = 0; i < arr.length; i++) {
    if (found == arr[i]) {
      found_two = arr[i];
      break;
    }
  }
  if (found_two == found) {
    console.log('number present in the array');
  } else {
    console.log('number not present in the array');
  }
}

这个小片段对我有用。

const arrayOfObject = [{ id: 1, name: 'john' }, {id: 2, name: 'max'}];

const checkUsername = obj => obj.name === 'max';

console.log(arrayOfObject.some(checkUsername))

如果你有一个像['john'，'marsh']这样的元素数组，那么我们可以这样做

const checkUsername = element => element == 'john';
    
console.log(arrayOfObject.some(checkUsername))

下面是一个ES6方法链，使用.map()和.includes():

const arr = [ { id: 1, username: 'fred' }, { id: 2, username: 'bill' }, { id: 2, username: 'ted' } ]

const checkForUser = (newUsername) => {
      arr.map(user => {
        return user.username
      }).includes(newUsername)
    }

if (!checkForUser('fred')){
  // add fred
}

映射现有用户以创建用户名字符串数组。 检查该用户名数组是否包含新用户名 如果不存在，则添加新用户

检查现有的用户名相当简单:

var arr = [{ id: 1, username: 'fred' }, 
  { id: 2, username: 'bill'}, 
  { id: 3, username: 'ted' }];

function userExists(username) {
  return arr.some(function(el) {
    return el.username === username;
  }); 
}

console.log(userExists('fred')); // true
console.log(userExists('bred')); // false

但是当你必须向这个数组中添加一个新用户时，要做什么就不那么明显了。最简单的方法-只是推入一个id等于array的新元素。长度+ 1:

function addUser(username) {
  if (userExists(username)) {
    return false; 
  }
  arr.push({ id: arr.length + 1, username: username });
  return true;
}

addUser('fred'); // false
addUser('bred'); // true, user `bred` added

它将保证id的唯一性，但如果将一些元素从数组末尾删除，则会使该数组看起来有点奇怪。