I've just encountered a bit different but similar situation. Not 100% sure if it'd be a resolution to your case, but I resolved the issue for Django 1.3 by setting a POST parameter 'csrfmiddlewaretoken' with the proper cookie value string which is usually returned within the form of your home HTML by Django's template system with '{% csrf_token %}' tag. I did not try on the older Django, just happened and resolved on Django1.3. My problem was that the first request submitted via Ajax from a form was successfully done but the second attempt from the exact same from failed, resulted in 403 state even though the header 'X-CSRFToken' is correctly placed with the CSRF token value as well as in the case of the first attempt. Hope this helps.

问候,

Hiro

使用Firefox和Firebug。在触发ajax请求时打开“Console”选项卡。使用DEBUG=True，你可以得到django错误页面作为响应，你甚至可以在控制台选项卡中看到ajax响应的渲染html。

然后你就知道误差是什么了。

公认的答案很可能是在转移注意力。Django 1.2.4和1.2.5之间的区别在于AJAX请求需要CSRF令牌。

我在Django 1.3上遇到了这个问题，这是由于CSRF cookie一开始就没有设置造成的。除非必须，否则Django不会设置cookie。因此，在Django 1.2.4上运行的纯ajax或重度ajax站点可能永远不会向客户端发送令牌，然后需要令牌的升级将导致403错误。

理想的解决方法是: http://docs.djangoproject.com/en/dev/ref/contrib/csrf/#page-uses-ajax-without-any-html-form 但是您必须等到1.4版本，除非这只是文档与代码同步

Edit

还要注意的是，Django文档在jQuery 1.5中指出了一个bug，所以确保你使用的是1.5.1或更高版本的Django建议代码: https://docs.djangoproject.com/en/dev/ref/csrf/#ajax

如果你的表单在不使用JS的情况下可以在Django中正确地发布，你应该可以使用ajax逐步增强它，而不需要任何修改或混乱地传递csrf令牌。只需序列化整个表单，它将自动拾取所有表单字段，包括隐藏的csrf字段:

$('#myForm').submit(function(){
    var action = $(this).attr('action');
    var that = $(this);
    $.ajax({
        url: action,
        type: 'POST',
        data: that.serialize()
        ,success: function(data){
            console.log('Success!');
        }
    });
    return false;
});

我已经用Django 1.3+和jQuery 1.5+进行了测试。显然，这适用于任何HTML表单，而不仅仅是Django应用程序。

我有一个解决办法。在我的JS我有两个函数。 首先得到饼干(即。csrftoken):

function getCookie(name) {
let cookieValue = null;
if (document.cookie && document.cookie !== '') {
    const cookies = document.cookie.split(';');
    for (let i = 0; i < cookies.length; i++) {
        const cookie = cookies[i].trim();
        // Does this cookie string begin with the name we want?
        if (cookie.substring(0, name.length + 1) === (name + '=')) {
            cookieValue = decodeURIComponent(cookie.substring(name.length + 1));
            break;
        }
    }
}
return cookieValue;

}

第二个是我的ajax函数。在这种情况下，它是用于登录的，实际上不返回任何东西，只是传递值来设置一个会话:

function LoginAjax() {


    //get scrftoken:
    const csrftoken = getCookie('csrftoken');

    var req = new XMLHttpRequest();
    var userName = document.getElementById("Login-Username");
    var password = document.getElementById("Login-Password");

    req.onreadystatechange = function () {
        if (this.readyState == 4 && this.status == 200) {            
            //read response loggedIn JSON show me if user logged in or not
            var respond = JSON.parse(this.responseText);            
            alert(respond.loggedIn);

        }
    }

    req.open("POST", "login", true);

    //following header set scrftoken to resolve problem
    req.setRequestHeader('X-CSRFToken', csrftoken);

    req.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
    req.send("UserName=" + userName.value + "&Password=" + password.value);
}

One CSRF token is assigned to every session ( i.e. every time you log in). So before you wish to get some data entered by user and send that as ajax call to some function which is protected by csrf_protect decorator, try to find the functions that are being called before you are getting this data from user. E.g. some template must be being rendered on which your user is entering data. That template is being rendered by some function. In this function you can get csrf token as follows: csrf = request.COOKIES['csrftoken'] Now pass this csrf value in context dictionary against which template in question is being rendered. Now in that template write this line: Now in your javascript function, before making ajax request, write this: var csrf = $('#csrf').val() this will pick value of token passed to template and store it in variable csrf. Now while making ajax call, in your post data, pass this value as well : "csrfmiddlewaretoken": csrf

这将工作，即使你没有实现django表单。

实际上，这里的逻辑是:您需要从请求中获得的令牌。 因此，您只需要在登录后立即找出被调用的函数。一旦你有了这个令牌，要么进行另一个ajax调用来获取它，要么将它传递给一些可以通过ajax访问的模板。