具有es6箭头功能

let someArray = [
                 {name:"Kristian", lines:"2,5,10"},
                 {name:"John", lines:"1,19,26,96"}
                ];
let arrayToRemove={name:"Kristian", lines:"2,5,10"};
someArray=someArray.filter((e)=>e.name !=arrayToRemove.name && e.lines!= arrayToRemove.lines)

这就是我用的。

Array.prototype.delete = function(pos){
    this[pos] = undefined;
    var len = this.length - 1;
    for(var a = pos;a < this.length - 1;a++){
      this[a] = this[a+1];
    }
    this.pop();
  }

那就像说出来一样简单

var myArray = [1,2,3,4,5,6,7,8,9];
myArray.delete(3);

用任何数字代替3。之后的预期输出应该是:

console.log(myArray); //Expected output 1,2,3,5,6,7,8,9

someArray = jQuery.grep(someArray , function (value) {
        return value.name != 'Kristian';
});

这里有一个映射和拼接的例子

const arrayObject = [ {name: "name1"， value: "value1"}， {name: "name2"， value: "value2"}， {name: "name3"， value: "value3"}， ]; let index = arrayObject.map((item) => item.name).indexOf("name1"); If(索引> -1){ arrayObject。拼接(指数(1); console.log(“结果”,arrayObject); ｝

输出

Result [
  {
    "name": "name2",
    "value": "value2"
  },
  {
    "name": "name3",
    "value": "value3"
  }
]

干净的解决方案是使用Array.filter:

var filtered = someArray.filter(function(el) { return el.Name != "Kristian"; }); 

问题是它不能在IE < 9上工作。然而，你可以包括来自Javascript库(例如:underscore.js)的代码，为任何浏览器实现这一点。

const someArray = [{name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"}];

我们得到对象的索引它的name属性值为"Kristian"

const index = someArray.findIndex(key => key.name === "Kristian");
console.log(index); // 0

通过使用拼接函数我们删除了name属性值为“Kristian”的对象

someArray.splice(index,1);
console.log(someArray); // [{name:"John", lines:"1,19,26,96"}]