具有es6箭头功能

let someArray = [
                 {name:"Kristian", lines:"2,5,10"},
                 {name:"John", lines:"1,19,26,96"}
                ];
let arrayToRemove={name:"Kristian", lines:"2,5,10"};
someArray=someArray.filter((e)=>e.name !=arrayToRemove.name && e.lines!= arrayToRemove.lines)

性能

今天2021.01.27我在Chrome v88, Safari v13.1.2和Firefox v84上对所选解决方案的MacOs HighSierra 10.13.6进行测试。

结果

对于所有浏览器:

当元素不存在时，最快/最快的解决方案:A和B 快速/最快的大数组解决方案:C 当元素存在时，大数组的快速/最快解决方案:H 对于小数组来说是非常缓慢的解:F和G 对于大数组:D, E和F，非常缓慢的解决方案

细节

我执行4个测试用例:

小数组(10个元素)和元素存在-你可以在这里运行它 小数组(10个元素)和元素不存在-你可以在这里运行它 大数组(百万元素)和元素存在-你可以在这里运行它 大数组(百万元素)和元素不存在-你可以在这里运行它

下面的代码片段展示了解决方案之间的差异 一个 B C D E F G H 我

function A(arr, name) { let idx = arr.findIndex(o => o.name==name); if(idx>=0) arr.splice(idx, 1); return arr; } function B(arr, name) { let idx = arr.findIndex(o => o.name==name); return idx<0 ? arr : arr.slice(0,idx).concat(arr.slice(idx+1,arr.length)); } function C(arr, name) { let idx = arr.findIndex(o => o.name==name); delete arr[idx]; return arr; } function D(arr, name) { return arr.filter(el => el.name != name); } function E(arr, name) { let result = []; arr.forEach(o => o.name==name || result.push(o)); return result; } function F(arr, name) { return _.reject(arr, el => el.name == name); } function G(arr, name) { let o = arr.find(o => o.name==name); return _.without(arr,o); } function H(arr, name) { $.each(arr, function(i){ if(arr[i].name === 'Kristian') { arr.splice(i,1); return false; } }); return arr; } function I(arr, name) { return $.grep(arr,o => o.name!=name); } // Test let test1 = [ {name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"}, ]; let test2 = [ {name:"John3", lines:"1,19,26,96"}, {name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"}, {name:"Joh2", lines:"1,19,26,96"}, ]; let test3 = [ {name:"John3", lines:"1,19,26,96"}, {name:"John", lines:"1,19,26,96"}, {name:"Joh2", lines:"1,19,26,96"}, ]; console.log(` Test1: original array from question Test2: array with more data Test3: array without element which we want to delete `); [A,B,C,D,E,F,G,H,I].forEach(f=> console.log(` Test1 ${f.name}: ${JSON.stringify(f([...test1],"Kristian"))} Test2 ${f.name}: ${JSON.stringify(f([...test2],"Kristian"))} Test3 ${f.name}: ${JSON.stringify(f([...test3],"Kristian"))} `)); <script src="https://code.jquery.com/jquery-3.5.1.min.js" integrity="sha256-9/aliU8dGd2tb6OSsuzixeV4y/faTqgFtohetphbbj0=" crossorigin="anonymous"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.20/lodash.min.js" integrity="sha512-90vH1Z83AJY9DmlWa8WkjkV79yfS2n2Oxhsi2dZbIv0nC4E6m5AbH8Nh156kkM7JePmqD6tcZsfad1ueoaovww==" crossorigin="anonymous"> </script> This shippet only presents functions used in performance tests - it not perform tests itself!

这里是chrome的示例结果

只从数组中返回属性名不是“Kristian”的对象

var noKristianArray = $.grep(someArray, function (el) { return el.name!= "Kristian"; });

演示:

var someArray = [ {名称:“克里斯蒂安”,行:“2、5、10”}, {名称:“约翰”,行:“1,19日,26日96”}, {名称:“克里斯蒂安”,行:" 58160 "}, {名称:“费利克斯”,行:“96”1,19日,26日} ]; var noKristianArray = $。grep(someArray, function (el){返回el.name!= "克里斯蒂安”;})； console.log (noKristianArray); < script src = " https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js " > < /脚本>

这个答案

for (var i =0; i < someArray.length; i++)
   if (someArray[i].name === "Kristian") {
      someArray.splice(i,1);
   }

对于满足条件的多个记录不工作。如果您有两个这样的连续记录，则只删除第一个记录，跳过另一个记录。你必须使用:

for (var i = someArray.length - 1; i>= 0; i--)
   ...

代替。

这个概念使用剑道网格

var grid = $("#addNewAllergies").data("kendoGrid");

var selectedItem = SelectedCheckBoxList;

for (var i = 0; i < selectedItem.length; i++) {
    if(selectedItem[i].boolKendoValue==true)
    {
        selectedItem.length= 0;
    }
}

这是一个对我有用的函数:

function removeFromArray(array, value) {
    var idx = array.indexOf(value);
    if (idx !== -1) {
        array.splice(idx, 1);
    }
    return array;
}