如何从数组中删除对象? 我希望从someArray中删除包含名称Kristian的对象。例如:
someArray = [{name:"Kristian", lines:"2,5,10"},
{name:"John", lines:"1,19,26,96"}];
我想实现:
someArray = [{name:"John", lines:"1,19,26,96"}];
如何从数组中删除对象? 我希望从someArray中删除包含名称Kristian的对象。例如:
someArray = [{name:"Kristian", lines:"2,5,10"},
{name:"John", lines:"1,19,26,96"}];
我想实现:
someArray = [{name:"John", lines:"1,19,26,96"}];
当前回答
你所显示的“数组”是无效的JavaScript语法。花括号{}表示具有属性名/值对的对象,而方括号[]表示数组,就像这样:
someArray = [{name:"Kristian", lines:"2,5,10"}, {name:"John", lines:"1,19,26,96"}];
在这种情况下,您可以使用.splice()方法删除一个项。要删除第一项(索引0),如下所示:
someArray.splice(0,1);
// someArray = [{name:"John", lines:"1,19,26,96"}];
如果你不知道索引,但想通过数组搜索找到名称为“Kristian”的项来删除,你可以这样做:
for (var i =0; i < someArray.length; i++)
if (someArray[i].name === "Kristian") {
someArray.splice(i,1);
break;
}
编辑:我刚刚注意到你的问题被标记为“jQuery”,所以你可以尝试$.grep()方法:
someArray = $.grep(someArray,
function(o,i) { return o.name === "Kristian"; },
true);
其他回答
虽然这可能不适合这种情况,我发现前几天,如果你不需要改变数组的大小,你也可以使用delete关键字从数组中删除一个项目。
var myArray = [1,2,3];
delete myArray[1];
console.log(myArray[1]); //undefined
console.log(myArray.length); //3 - doesn't actually shrink the array down
如果你想删除给定对象的所有出现(基于某些条件),那么使用for循环中的javascript splice方法。
因为删除对象会影响数组长度,所以请确保减少计数器一步,以保持长度检查不变。
var objArr=[{Name:"Alex", Age:62},
{Name:"Robert", Age:18},
{Name:"Prince", Age:28},
{Name:"Cesar", Age:38},
{Name:"Sam", Age:42},
{Name:"David", Age:52}
];
for(var i = 0;i < objArr.length; i ++)
{
if(objArr[i].Age > 20)
{
objArr.splice(i, 1);
i--; //re-adjust the counter.
}
}
上面的代码片段删除了年龄大于20的所有对象。
someArray = jQuery.grep(someArray , function (value) {
return value.name != 'Kristian';
});
你可以使用array.filter()。
如。
someArray = [{name:"Kristian", lines:"2,5,10"},
{name:"John", lines:"1,19,26,96"}];
someArray = someArray.filter(function(returnableObjects){
return returnableObjects.name !== 'Kristian';
});
//someArray will now be = [{name:"John", lines:"1,19,26,96"}];
箭头功能:
someArray = someArray.filter(x => x.name !== 'Kristian')
如果你在数组中的对象上没有任何你知道的属性(或者可能是唯一的),但是你有一个你想要删除的对象的引用,你可以执行下面unregisterObject方法中的操作:
let registeredObjects = []; function registerObject(someObject) { registeredObjects.push(someObject); } function unregisterObject(someObject) { registeredObjects = registeredObjects.filter(obj => obj !== someObject); } let myObject1 = {hidden: "someValue1"}; // Let's pretend we don't know the hidden attribute let myObject2 = {hidden: "someValue2"}; registerObject(myObject1); registerObject(myObject2); console.log(`There are ${registeredObjects.length} objects registered. They are: ${JSON.stringify(registeredObjects)}`); unregisterObject(myObject1); console.log(`There are ${registeredObjects.length} objects registered. They are: ${JSON.stringify(registeredObjects)}`);