使用纯JavaScript(不是jQuery)，是否有任何方法来检查元素是否包含类?
目前，我正在这样做:
var test = document.getElementById("test");
var testClass = test.className;
switch (testClass) {
例“class1”:
测试。innerHTML = "我有class1";
打破;
例“class2”:
测试。innerHTML = "I have class2";
打破;
例“class3”:
测试。innerHTML = "I have class3";
打破;
“一年级”情况:
测试。innerHTML = "I have class4";
打破;
默认值:
测试。innerHTML = "";
｝
<div id="test" class="class1"></div>
问题是，如果我把HTML改成这个…
<div id="test" class="class1 class5"></div>
.．.不再有一个精确的匹配，所以我得到的默认输出为nothing("")。但我仍然希望输出为I have class1，因为<div>仍然包含。class1类。
这个问题可以通过element.classList.contains()得到很好的回答，但人们的回答过于夸张，并提出了一些大胆的要求，因此我运行了一个基准测试。
记住，每个测试都要进行1000次迭代，所以大多数测试仍然非常快。除非在特定操作中广泛依赖于此，否则不会看到性能差异。
我用各种方法做了一些测试。在我的机器上，(Win 10, 24gb, i7-8700)， classList。Contains表现非常好。className也是。Split(' ')，实际上是相同的。
胜出者是classList.contains()。如果你没有检查classList是否未定义，~(' ' + v.className + ' ')。indexOf(' ' + classToFind + ' ')爬行5-15%
使用元素。contains方法:
element.classList.contains(class);
这适用于所有当前的浏览器，也有支持旧浏览器的腻子。
Alternatively, if you work with older browsers and don't want to use polyfills to fix them, using indexOf is correct, but you have to tweak it a little:
function hasClass(element, className) {
return (' ' + element.className + ' ').indexOf(' ' + className+ ' ') > -1;
}
否则，如果您正在寻找的类是另一个类名的一部分，也会得到true。
DEMO
jQuery使用类似的(如果不是相同的)方法。
应用于本例:
因为这不能和switch语句一起工作，你可以用下面的代码达到同样的效果:
var test = document.getElementById("test"),
classes = ['class1', 'class2', 'class3', 'class4'];
test.innerHTML = "";
for(var i = 0, j = classes.length; i < j; i++) {
if(hasClass(test, classes[i])) {
test.innerHTML = "I have " + classes[i];
break;
}
}
它也更少冗余;)
Felix's trick of adding spaces to flank the className and the string you're searching for is the right approach to determining whether the elements has the class or not.
To have different behaviour according to the class, you may use function references, or functions, within a map:
function fn1(element){ /* code for element with class1 */ }
function fn2(element){ /* code for element with class2 */ }
function fn2(element){ /* code for element with class3 */ }
var fns={'class1': fn1, 'class2': fn2, 'class3': fn3};
for(var i in fns) {
if(hasClass(test, i)) {
fns[i](test);
}
}
for(var i in fns) iterates through the keys within the fns map.
Having no break after fnsi allows the code to be executed whenever there is a match - so that if the element has, f.i., class1 and class2, both fn1 and fn2 will be executed.
The advantage of this approach is that the code to execute for each class is arbitrary, like the one in the switch statement; in your example all the cases performed a similar operation, but tomorrow you may need to do different things for each.
You may simulate the default case by having a status variable telling whether a match was found in the loop or not.
