我如何在Python中制作两个装饰器来完成以下操作?

@make_bold
@make_italic
def say():
   return "Hello"

调用say()应返回:

"<b><i>Hello</i></b>"

当前回答

当然,您也可以从decorator函数返回lambdas:

def makebold(f): 
    return lambda: "<b>" + f() + "</b>"
def makeitalic(f): 
    return lambda: "<i>" + f() + "</i>"

@makebold
@makeitalic
def say():
    return "Hello"

print say()

其他回答

做同样事情的另一种方式:

class bol(object):
  def __init__(self, f):
    self.f = f
  def __call__(self):
    return "<b>{}</b>".format(self.f())

class ita(object):
  def __init__(self, f):
    self.f = f
  def __call__(self):
    return "<i>{}</i>".format(self.f())

@bol
@ita
def sayhi():
  return 'hi'

或者,更灵活地说:

class sty(object):
  def __init__(self, tag):
    self.tag = tag
  def __call__(self, f):
    def newf():
      return "<{tag}>{res}</{tag}>".format(res=f(), tag=self.tag)
    return newf

@sty('b')
@sty('i')
def sayhi():
  return 'hi'

这里是一个链接装饰器的简单示例。注意最后一行-它显示了封面下的情况。

############################################################
#
#    decorators
#
############################################################

def bold(fn):
    def decorate():
        # surround with bold tags before calling original function
        return "<b>" + fn() + "</b>"
    return decorate


def uk(fn):
    def decorate():
        # swap month and day
        fields = fn().split('/')
        date = fields[1] + "/" + fields[0] + "/" + fields[2]
        return date
    return decorate

import datetime
def getDate():
    now = datetime.datetime.now()
    return "%d/%d/%d" % (now.day, now.month, now.year)

@bold
def getBoldDate(): 
    return getDate()

@uk
def getUkDate():
    return getDate()

@bold
@uk
def getBoldUkDate():
    return getDate()


print getDate()
print getBoldDate()
print getUkDate()
print getBoldUkDate()
# what is happening under the covers
print bold(uk(getDate))()

输出如下所示:

17/6/2013
<b>17/6/2013</b>
6/17/2013
<b>6/17/2013</b>
<b>6/17/2013</b>

下面有make_bold()和make_italic():

def make_bold(func):
    def core(*args, **kwargs):
        result = func(*args, **kwargs)
        return "<b>" + result + "</b>"
    return core

def make_italic(func):
    def core(*args, **kwargs):
        result = func(*args, **kwargs)
        return "<i>" + result + "</i>"
    return core

您可以使用say()将它们用作装饰器,如下所示:

@make_bold
@make_italic
def say():
   return "Hello"

print(say())

输出:

<b><i>Hello</i></b>

当然,您可以直接使用make_bold()和make_italic()而不使用修饰符,如下所示:

def say():
    return "Hello"
    
f1 = make_italic(say)
f2 = make_bold(f1)
result = f2()
print(result)

简而言之:

def say():
    return "Hello"
    
result = make_bold(make_italic(say))()
print(result)

输出:

<b><i>Hello</i></b>

用于绘制图像的嵌套装饰器的又一示例:

import matplotlib.pylab as plt

def remove_axis(func):
    def inner(img, alpha):
        plt.axis('off')
        func(img, alpha)
    return inner

def plot_gray(func):
    def inner(img, alpha):
        plt.gray()
        func(img, alpha)
    return inner

@remove_axis
@plot_gray
def plot_image(img, alpha):
    plt.imshow(img, alpha=alpha)
    plt.show()

现在,让我们先使用嵌套的装饰器显示一个没有轴标签的彩色图像:

plot_image(plt.imread('lena_color.jpg'), 0.4)

接下来,让我们使用嵌套的装饰器remove_axis和plot_gray显示一个没有轴标签的灰度图像(我们需要cmap='gray',否则默认的颜色映射是viridis,因此除非明确指定,否则默认情况下灰度图像不会以黑白色显示)

plot_image(plt.imread('lena_bw.jpg'), 0.8)

上述函数调用缩减为以下嵌套调用

remove_axis(plot_gray(plot_image))(img, alpha)

当然,您也可以从decorator函数返回lambdas:

def makebold(f): 
    return lambda: "<b>" + f() + "</b>"
def makeitalic(f): 
    return lambda: "<i>" + f() + "</i>"

@makebold
@makeitalic
def say():
    return "Hello"

print say()