我如何在Python中制作两个装饰器来完成以下操作?
@make_bold
@make_italic
def say():
return "Hello"
调用say()应返回:
"<b><i>Hello</i></b>"
我如何在Python中制作两个装饰器来完成以下操作?
@make_bold
@make_italic
def say():
return "Hello"
调用say()应返回:
"<b><i>Hello</i></b>"
当前回答
当然,您也可以从decorator函数返回lambdas:
def makebold(f):
return lambda: "<b>" + f() + "</b>"
def makeitalic(f):
return lambda: "<i>" + f() + "</i>"
@makebold
@makeitalic
def say():
return "Hello"
print say()
其他回答
或者,您可以编写一个工厂函数,该函数返回一个装饰器,该装饰器将装饰函数的返回值包装在传递给工厂函数的标记中。例如:
from functools import wraps
def wrap_in_tag(tag):
def factory(func):
@wraps(func)
def decorator():
return '<%(tag)s>%(rv)s</%(tag)s>' % (
{'tag': tag, 'rv': func()})
return decorator
return factory
这使您能够编写:
@wrap_in_tag('b')
@wrap_in_tag('i')
def say():
return 'hello'
or
makebold = wrap_in_tag('b')
makeitalic = wrap_in_tag('i')
@makebold
@makeitalic
def say():
return 'hello'
就我个人而言,我会用不同的方式来编写装饰器:
from functools import wraps
def wrap_in_tag(tag):
def factory(func):
@wraps(func)
def decorator(val):
return func('<%(tag)s>%(val)s</%(tag)s>' %
{'tag': tag, 'val': val})
return decorator
return factory
这将产生:
@wrap_in_tag('b')
@wrap_in_tag('i')
def say(val):
return val
say('hello')
不要忘了decorator语法是一种简写的构造:
say = wrap_in_tag('b')(wrap_in_tag('i')(say)))
用不同数量的参数修饰函数:
def frame_tests(fn):
def wrapper(*args):
print "\nStart: %s" %(fn.__name__)
fn(*args)
print "End: %s\n" %(fn.__name__)
return wrapper
@frame_tests
def test_fn1():
print "This is only a test!"
@frame_tests
def test_fn2(s1):
print "This is only a test! %s" %(s1)
@frame_tests
def test_fn3(s1, s2):
print "This is only a test! %s %s" %(s1, s2)
if __name__ == "__main__":
test_fn1()
test_fn2('OK!')
test_fn3('OK!', 'Just a test!')
结果:
Start: test_fn1
This is only a test!
End: test_fn1
Start: test_fn2
This is only a test! OK!
End: test_fn2
Start: test_fn3
This is only a test! OK! Just a test!
End: test_fn3
说到计数器示例-如上所述,计数器将在使用decorator的所有函数之间共享:
def counter(func):
def wrapped(*args, **kws):
print 'Called #%i' % wrapped.count
wrapped.count += 1
return func(*args, **kws)
wrapped.count = 0
return wrapped
这样,您的装饰器可以重复用于不同的函数(或用于多次装饰同一个函数:func_counter1=counter(func);func_counter2=counter(func)),并且计数器变量将对每个变量保持私有。
查看文档以了解装饰器是如何工作的。以下是您的要求:
from functools import wraps
def makebold(fn):
@wraps(fn)
def wrapper(*args, **kwargs):
return "<b>" + fn(*args, **kwargs) + "</b>"
return wrapper
def makeitalic(fn):
@wraps(fn)
def wrapper(*args, **kwargs):
return "<i>" + fn(*args, **kwargs) + "</i>"
return wrapper
@makebold
@makeitalic
def hello():
return "hello world"
@makebold
@makeitalic
def log(s):
return s
print hello() # returns "<b><i>hello world</i></b>"
print hello.__name__ # with functools.wraps() this returns "hello"
print log('hello') # returns "<b><i>hello</i></b>"
这里是一个链接装饰器的简单示例。注意最后一行-它显示了封面下的情况。
############################################################
#
# decorators
#
############################################################
def bold(fn):
def decorate():
# surround with bold tags before calling original function
return "<b>" + fn() + "</b>"
return decorate
def uk(fn):
def decorate():
# swap month and day
fields = fn().split('/')
date = fields[1] + "/" + fields[0] + "/" + fields[2]
return date
return decorate
import datetime
def getDate():
now = datetime.datetime.now()
return "%d/%d/%d" % (now.day, now.month, now.year)
@bold
def getBoldDate():
return getDate()
@uk
def getUkDate():
return getDate()
@bold
@uk
def getBoldUkDate():
return getDate()
print getDate()
print getBoldDate()
print getUkDate()
print getBoldUkDate()
# what is happening under the covers
print bold(uk(getDate))()
输出如下所示:
17/6/2013
<b>17/6/2013</b>
6/17/2013
<b>6/17/2013</b>
<b>6/17/2013</b>