是否有一种通过jQuery(或不使用)检索查询字符串值的无插件方法?

如果是,怎么办?如果没有,是否有插件可以这样做?


当前回答

tl;博士

一个快速、完整的解决方案,可处理多值键和编码字符。

// using ES5   (200 characters)
var qd = {};
if (location.search) location.search.substr(1).split("&").forEach(function(item) {var s = item.split("="), k = s[0], v = s[1] && decodeURIComponent(s[1]); (qd[k] = qd[k] || []).push(v)})

// using ES6   (23 characters cooler)
var qd = {};
if (location.search) location.search.substr(1).split`&`.forEach(item => {let [k,v] = item.split`=`; v = v && decodeURIComponent(v); (qd[k] = qd[k] || []).push(v)})

// as a function with reduce
function getQueryParams() {
  return location.search
    ? location.search.substr(1).split`&`.reduce((qd, item) => {let [k,v] = item.split`=`; v = v && decodeURIComponent(v); (qd[k] = qd[k] || []).push(v); return qd}, {})
    : {}
}

多行:

var qd = {};
if (location.search) location.search.substr(1).split("&").forEach(function(item) {
    var s = item.split("="),
        k = s[0],
        v = s[1] && decodeURIComponent(s[1]); //  null-coalescing / short-circuit
    //(k in qd) ? qd[k].push(v) : qd[k] = [v]
    (qd[k] = qd[k] || []).push(v) // null-coalescing / short-circuit
})

这是什么代码。。。“零合并”,短路评估ES6解构赋值、箭头函数、模板字符串####示例:

"?a=1&b=0&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> qd
a: ["1", "5", "t e x t"]
b: ["0"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]

> qd.a[1]    // "5"
> qd["a"][1] // "5"


阅读更多。。。关于Vanilla JavaScript解决方案。

要访问URL的不同部分,请使用位置。(搜索|哈希)

最简单(虚拟)解决方案

var queryDict = {};
location.search.substr(1).split("&").forEach(function(item) {queryDict[item.split("=")[0]] = item.split("=")[1]})

正确处理空钥匙。使用找到的最后一个值覆盖多键。

"?a=1&b=0&c=3&d&e&a=5"
> queryDict
a: "5"
b: "0"
c: "3"
d: undefined
e: undefined

多值键

简单的密钥检查(字典中的项目)?dict.item.push(val):dict.item=[val]

var qd = {};
location.search.substr(1).split("&").forEach(function(item) {(item.split("=")[0] in qd) ? qd[item.split("=")[0]].push(item.split("=")[1]) : qd[item.split("=")[0]] = [item.split("=")[1]]})

现在返回数组。按qd.key[index]或qd[key][index]访问值

> qd
a: ["1", "5"]
b: ["0"]
c: ["3"]
d: [undefined]
e: [undefined]

编码字符?

对第二次或两次拆分使用decodeURIComponent()。

var qd = {};
location.search.substr(1).split("&").forEach(function(item) {var k = item.split("=")[0], v = decodeURIComponent(item.split("=")[1]); (k in qd) ? qd[k].push(v) : qd[k] = [v]})

####示例:

"?a=1&b=0&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> qd
a: ["1", "5", "t e x t"]
b: ["0"]
c: ["3"]
d: ["undefined"]  // decodeURIComponent(undefined) returns "undefined" !!!*
e: ["undefined", "http://w3schools.com/my test.asp?name=ståle&car=saab"]


# From comments **\*!!!** Please note, that `decodeURIComponent(undefined)` returns string `"undefined"`. The solution lies in a simple usage of [`&&`][5], which ensures that `decodeURIComponent()` is not called on undefined values. _(See the "complete solution" at the top.)_
v = v && decodeURIComponent(v);

If the querystring is empty (`location.search == ""`), the result is somewhat misleading `qd == {"": undefined}`. It is suggested to check the querystring before launching the parsing function likeso:
if (location.search) location.search.substr(1).split("&").forEach(...)

其他回答

这是我在GitHub上的查询字符串解析代码版本。

它的前缀是jquery.*,但解析函数本身不使用jquery。它非常快,但仍然可以进行一些简单的性能优化。

它还支持URL中的列表和哈希表编码,例如:

arr[]=10&arr[]=20&arr[]=100

or

hash[key1]=hello&hash[key2]=moto&a=How%20are%20you

jQuery.toQueryParams = function(str, separator) {
    separator = separator || '&'
    var obj = {}
    if (str.length == 0)
        return obj
    var c = str.substr(0,1)
    var s = c=='?' || c=='#'  ? str.substr(1) : str; 

    var a = s.split(separator)
    for (var i=0; i<a.length; i++) {
        var p = a[i].indexOf('=')
        if (p < 0) {
            obj[a[i]] = ''
            continue
        }
        var k = decodeURIComponent(a[i].substr(0,p)),
            v = decodeURIComponent(a[i].substr(p+1))

        var bps = k.indexOf('[')
        if (bps < 0) {
            obj[k] = v
            continue;
        } 

        var bpe = k.substr(bps+1).indexOf(']')
        if (bpe < 0) {
            obj[k] = v
            continue;
        }

        var bpv = k.substr(bps+1, bps+bpe-1)
        var k = k.substr(0,bps)
        if (bpv.length <= 0) {
            if (typeof(obj[k]) != 'object') obj[k] = []
            obj[k].push(v)
        } else {
            if (typeof(obj[k]) != 'object') obj[k] = {}
            obj[k][bpv] = v
        }
    }
    return obj;

}

Roshambo jQuery方法没有处理解码URL

http://snipplr.com/view/26662/get-url-parameters-with-jquery--improved/

在return语句中添加时也添加了该功能

return decodeURIComponent(results[1].replace(/\+/g, " ")) || 0;

现在您可以找到更新的要点:

$.urlParam = function(name){
var results = new RegExp('[\\?&]' + name + '=([^&#]*)').exec(window.location.href);
if (!results) { return 0; }
return decodeURIComponent(results[1].replace(/\+/g, " ")) || 0;
}

我认为这是实现这一点的准确和简洁的方法(修改自http://css-tricks.com/snippets/javascript/get-url-variables/):

function getQueryVariable(variable) {

    var query = window.location.search.substring(1),            // Remove the ? from the query string.
        vars = query.split("&");                                // Split all values by ampersand.

    for (var i = 0; i < vars.length; i++) {                     // Loop through them...
        var pair = vars[i].split("=");                          // Split the name from the value.
        if (pair[0] == variable) {                              // Once the requested value is found...
            return ( pair[1] == undefined ) ? null : pair[1];   // Return null if there is no value (no equals sign), otherwise return the value.
        }
    }

    return undefined;                                           // Wasn't found.

}

下面是String原型实现:

String.prototype.getParam = function( str ){
    str = str.replace(/[\[]/,"\\\[").replace(/[\]]/,"\\\]");
    var regex = new RegExp( "[\\?&]*"+str+"=([^&#]*)" );    
    var results = regex.exec( this );
    if( results == null ){
        return "";
    } else {
        return results[1];
    }
}

示例调用:

var status = str.getParam("status")

str可以是查询字符串或url

我使用以下代码(JavaScript)获取通过URL传递的内容:

function getUrlVars() {
            var vars = {};
            var parts = window.location.href.replace(/[?&]+([^=&]+)=([^&]*)/gi, function(m,key,value) {
                vars[key] = value;
            });
            return vars;
        }

然后,要将值分配给变量,只需指定要获取的参数,例如,如果URL是example.com/?I=1&p=2&f=3

您可以执行此操作以获取值:

var getI = getUrlVars()["I"];
var getP = getUrlVars()["p"];
var getF = getUrlVars()["f"];

则值将为:

getI = 1, getP = 2 and getF = 3