是否有一种通过jQuery(或不使用)检索查询字符串值的无插件方法?
如果是,怎么办?如果没有,是否有插件可以这样做?
是否有一种通过jQuery(或不使用)检索查询字符串值的无插件方法?
如果是,怎么办?如果没有,是否有插件可以这样做?
当前回答
function getUrlVar(key){
var result = new RegExp(key + "=([^&]*)", "i").exec(window.location.search);
return result && unescape(result[1]) || "";
}
https://gist.github.com/1771618
其他回答
function GET() {
var data = [];
for(x = 0; x < arguments.length; ++x)
data.push(location.href.match(new RegExp("/\?".concat(arguments[x],"=","([^\n&]*)")))[1])
return data;
}
example:
data = GET("id","name","foo");
query string : ?id=3&name=jet&foo=b
returns:
data[0] // 3
data[1] // jet
data[2] // b
or
alert(GET("id")[0]) // return 3
tl;博士
一个快速、完整的解决方案,可处理多值键和编码字符。
// using ES5 (200 characters)
var qd = {};
if (location.search) location.search.substr(1).split("&").forEach(function(item) {var s = item.split("="), k = s[0], v = s[1] && decodeURIComponent(s[1]); (qd[k] = qd[k] || []).push(v)})
// using ES6 (23 characters cooler)
var qd = {};
if (location.search) location.search.substr(1).split`&`.forEach(item => {let [k,v] = item.split`=`; v = v && decodeURIComponent(v); (qd[k] = qd[k] || []).push(v)})
// as a function with reduce
function getQueryParams() {
return location.search
? location.search.substr(1).split`&`.reduce((qd, item) => {let [k,v] = item.split`=`; v = v && decodeURIComponent(v); (qd[k] = qd[k] || []).push(v); return qd}, {})
: {}
}
多行:
var qd = {};
if (location.search) location.search.substr(1).split("&").forEach(function(item) {
var s = item.split("="),
k = s[0],
v = s[1] && decodeURIComponent(s[1]); // null-coalescing / short-circuit
//(k in qd) ? qd[k].push(v) : qd[k] = [v]
(qd[k] = qd[k] || []).push(v) // null-coalescing / short-circuit
})
这是什么代码。。。“零合并”,短路评估ES6解构赋值、箭头函数、模板字符串####示例:
"?a=1&b=0&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> qd
a: ["1", "5", "t e x t"]
b: ["0"]
c: ["3"]
d: [undefined]
e: [undefined, "http://w3schools.com/my test.asp?name=ståle&car=saab"]
> qd.a[1] // "5"
> qd["a"][1] // "5"
阅读更多。。。关于Vanilla JavaScript解决方案。
要访问URL的不同部分,请使用位置。(搜索|哈希)
最简单(虚拟)解决方案
var queryDict = {};
location.search.substr(1).split("&").forEach(function(item) {queryDict[item.split("=")[0]] = item.split("=")[1]})
正确处理空钥匙。使用找到的最后一个值覆盖多键。
"?a=1&b=0&c=3&d&e&a=5"
> queryDict
a: "5"
b: "0"
c: "3"
d: undefined
e: undefined
多值键
简单的密钥检查(字典中的项目)?dict.item.push(val):dict.item=[val]
var qd = {};
location.search.substr(1).split("&").forEach(function(item) {(item.split("=")[0] in qd) ? qd[item.split("=")[0]].push(item.split("=")[1]) : qd[item.split("=")[0]] = [item.split("=")[1]]})
现在返回数组。按qd.key[index]或qd[key][index]访问值
> qd
a: ["1", "5"]
b: ["0"]
c: ["3"]
d: [undefined]
e: [undefined]
编码字符?
对第二次或两次拆分使用decodeURIComponent()。
var qd = {};
location.search.substr(1).split("&").forEach(function(item) {var k = item.split("=")[0], v = decodeURIComponent(item.split("=")[1]); (k in qd) ? qd[k].push(v) : qd[k] = [v]})
####示例:
"?a=1&b=0&c=3&d&e&a=5&a=t%20e%20x%20t&e=http%3A%2F%2Fw3schools.com%2Fmy%20test.asp%3Fname%3Dståle%26car%3Dsaab"
> qd
a: ["1", "5", "t e x t"]
b: ["0"]
c: ["3"]
d: ["undefined"] // decodeURIComponent(undefined) returns "undefined" !!!*
e: ["undefined", "http://w3schools.com/my test.asp?name=ståle&car=saab"]
v = v && decodeURIComponent(v);
if (location.search) location.search.substr(1).split("&").forEach(...)
以下代码将创建一个具有两个方法的对象:
isKeyExist:检查是否存在特定参数getValue:获取特定参数的值。
var QSParam = new function() {
var qsParm = {};
var query = window.location.search.substring(1);
var params = query.split('&');
for (var i = 0; i < params.length; i++) {
var pos = params[i].indexOf('=');
if (pos > 0) {
var key = params[i].substring(0, pos);
var val = params[i].substring(pos + 1);
qsParm[key] = val;
}
}
this.isKeyExist = function(query){
if(qsParm[query]){
return true;
}
else{
return false;
}
};
this.getValue = function(query){
if(qsParm[query])
{
return qsParm[query];
}
throw "URL does not contain query "+ query;
}
};
获取查询的一行代码:
var value = location.search.match(new RegExp(key + "=(.*?)($|\&)", "i"))[1];
这是我自己的看法。第一个函数将URL字符串解码为名称/值对的对象:
url_args_decode = function (url) {
var args_enc, el, i, nameval, ret;
ret = {};
// use the DOM to parse the URL via an 'a' element
el = document.createElement("a");
el.href = url;
// strip off initial ? on search and split
args_enc = el.search.substring(1).split('&');
for (i = 0; i < args_enc.length; i++) {
// convert + into space, split on =, and then decode
args_enc[i].replace(/\+/g, ' ');
nameval = args_enc[i].split('=', 2);
ret[decodeURIComponent(nameval[0])]=decodeURIComponent(nameval[1]);
}
return ret;
};
另外,如果您更改了一些参数,可以使用第二个函数将参数数组放回URL字符串中:
url_args_replace = function (url, args) {
var args_enc, el, name;
// use the DOM to parse the URL via an 'a' element
el = document.createElement("a");
el.href = url;
args_enc = [];
// encode args to go into url
for (name in args) {
if (args.hasOwnProperty(name)) {
name = encodeURIComponent(name);
args[name] = encodeURIComponent(args[name]);
args_enc.push(name + '=' + args[name]);
}
}
if (args_enc.length > 0) {
el.search = '?' + args_enc.join('&');
} else {
el.search = '';
}
return el.href;
};