是否有任何方式来模拟[NSString stringWithFormat:@“%p”,myVar],从Objective-C,在新的Swift语言?

例如:

let str = "A String"
println(" str value \(str) has address: ?")

当前回答

这当然不是最快或最安全的方法。但这对我很管用。这将允许任何nsobject子类采用此属性。

public extension NSObject {
    public var memoryAddress : String? {
        let str = "\(self.self)".components(separatedBy: ": ")
        guard str.count > 1 else { return nil }
        return str[1].replacingOccurrences(of: ">", with: "")            
    }
}

//usage 
let foo : String! = "hello"
Swift.print(foo.memoryAddress) // prints 0x100f12980

其他回答

就用这个吧:

print(String(format: "%p", object))

斯威夫特5

extension String {
    static func pointer(_ object: AnyObject?) -> String {
        guard let object = object else { return "nil" }
        let opaque: UnsafeMutableRawPointer = Unmanaged.passUnretained(object).toOpaque()
        return String(describing: opaque)
    }
}

用法:

print("FileManager.default: \(String.pointer(FileManager.default))")
// FileManager.default: 0x00007fff5c287698

print("nil: \(String.pointer(nil))")
// nil: nil

我对Swift 3的解决方案

extension MyClass: CustomStringConvertible {
    var description: String {
        return "<\(type(of: self)): 0x\(String(unsafeBitCast(self, to: Int.self), radix: 16, uppercase: false))>"
    }
}

这段代码创建的描述类似于默认描述 < MyClass: 0 x610000223340 >

其他答案都很好,尽管我正在寻找一种方法来获取整数形式的指针地址:

let ptr = unsafeAddressOf(obj)
let nullPtr = UnsafePointer<Void>(bitPattern: 0)

/// This gets the address of pointer
let address = nullPtr.distanceTo(ptr) // This is Int

只是跟进一下。

注意:这是针对引用类型的。

斯威夫特:4/5

print(Unmanaged.passUnretained(someVar).toOpaque())

打印someVar的内存地址。 (感谢@Ying)


斯威夫特3.1:

print(Unmanaged<AnyObject>.passUnretained(someVar as AnyObject).toOpaque())

打印someVar的内存地址。