我正在创建一个实体(房间持久性库)类Food，在那里我想使foodId作为自增量。
@Entity
class Food(var foodName: String, var foodDesc: String, var protein: Double, var carbs: Double, var fat: Double)
{
@PrimaryKey
var foodId: Int = 0
var calories: Double = 0.toDouble()
}
如何设置foodId自增字段?
当前回答
你可以像这样添加@PrimaryKey(autoGenerate = true):
@Entity
data class Food(
var foodName: String,
var foodDesc: String,
var protein: Double,
var carbs: Double,
var fat: Double
){
@PrimaryKey(autoGenerate = true)
var foodId: Int = 0 // or foodId: Int? = null
var calories: Double = 0.toDouble()
}
其他回答
这对我来说很管用:
@Entity(tableName = "note_table")
data class Note(
@ColumnInfo(name="title") var title: String,
@ColumnInfo(name="description") var description: String = "",
@ColumnInfo(name="priority") var priority: Int,
@PrimaryKey(autoGenerate = true) var id: Int = 0//last so that we don't have to pass an ID value or named arguments
)
请注意，id放在最后，以避免在将实体插入Room之前创建实体时必须使用命名参数。一旦它被添加到room，在更新实体时使用id。
你可以像这样添加@PrimaryKey(autoGenerate = true):
@Entity
data class Food(
var foodName: String,
var foodDesc: String,
var protein: Double,
var carbs: Double,
var fat: Double
){
@PrimaryKey(autoGenerate = true)
var foodId: Int = 0 // or foodId: Int? = null
var calories: Double = 0.toDouble()
}
例如，如果你有一个用户实体，你想存储，字段(姓，姓，电子邮件)，你想自动生成id，你这样做。
@Entity(tableName = "users")
data class Users(
@PrimaryKey(autoGenerate = true)
val id: Long,
val firstname: String,
val lastname: String,
val email: String
)
然后，Room将自动生成并自动增加id字段。
用下面的代码注释你的Entity类。
在Java中:
@PrimaryKey(autoGenerate = true)
private int id;
在芬兰湾的科特林:
@PrimaryKey(autoGenerate = true)
var id: Int
然后，Room将自动生成并自动增加id字段。
@Entity(tableName = "user")
data class User(
@PrimaryKey(autoGenerate = true) var id: Int?,
var name: String,
var dob: String,
var address: String,
var gender: String
)
{
constructor():this(null,
"","","","")
}
