我有一个大约有2000条记录的CSV文件。
每条记录都有一个字符串和一个类别:
This is the first line,Line1
This is the second line,Line2
This is the third line,Line3
我需要把这个文件读入一个列表，看起来像这样:
data = [('This is the first line', 'Line1'),
('This is the second line', 'Line2'),
('This is the third line', 'Line3')]
如何使用Python将此CSV导入到我需要的列表?
当前回答
您可以使用list()函数将csv阅读器对象转换为列表
import csv
with open('input.csv', newline='') as csv_file:
reader = csv.reader(csv_file, delimiter=',')
rows = list(reader)
print(rows)
其他回答
您可以使用list()函数将csv阅读器对象转换为列表
import csv
with open('input.csv', newline='') as csv_file:
reader = csv.reader(csv_file, delimiter=',')
rows = list(reader)
print(rows)
如果确定输入中没有逗号，而不是分隔类别，则可以逐行读取文件并在，，上进行分割，然后将结果推入List
也就是说，看起来您正在查看一个CSV文件，因此您可以考虑为它使用模块
result = []
for line in text.splitlines():
result.append(tuple(line.split(",")))
一个简单的循环就足够了:
lines = []
with open('test.txt', 'r') as f:
for line in f.readlines():
l,name = line.strip().split(',')
lines.append((l,name))
print lines
使用csv模块:
import csv
with open('file.csv', newline='') as f:
reader = csv.reader(f)
data = list(reader)
print(data)
输出:
[['This is the first line', 'Line1'], ['This is the second line', 'Line2'], ['This is the third line', 'Line3']]
如果你需要元组:
import csv
with open('file.csv', newline='') as f:
reader = csv.reader(f)
data = [tuple(row) for row in reader]
print(data)
输出:
[('This is the first line', 'Line1'), ('This is the second line', 'Line2'), ('This is the third line', 'Line3')]
旧的Python 2答案，同样使用csv模块:
import csv
with open('file.csv', 'rb') as f:
reader = csv.reader(f)
your_list = list(reader)
print your_list
# [['This is the first line', 'Line1'],
# ['This is the second line', 'Line2'],
# ['This is the third line', 'Line3']]
