实际情况是shell将“*test.c”展开为一个文件列表。尝试转义星号为:

find . -name \*test.c

当我试图找到多个文件名时，我遇到了这个问题，我不能组合成一个正则表达式，正如@Chris J的回答所描述的那样，下面是对我有用的方法

find . -name one.pdf -o -name two.txt -o -name anotherone.jpg

-o或-or是逻辑或。更多信息请参见Gnu.org上的查找文件。

我在CygWin上运行这个。

实际情况是shell将“*test.c”展开为一个文件列表。尝试转义星号为:

find . -name \*test.c

看来这个问题已经有答案了。我只是想分享对我有用的东西。我在(和名字)之间漏了一个空格。因此，选择一个文件排除其中一些的正确方法如下所示;

find . -name 'my-file-*' -type f -not \( -name 'my-file-1.2.0.jar' -or -name 'my-file.jar' \) 

你可以试试这个:

cat $(file $( find . -readable) | grep ASCII | tr ":" " " | awk '{print $1}')

这样，您就可以用ASCII找到所有可读的文件，并使用cat读取它们

如果你想指定他的权重和不可执行的:

cat $(file $( find . -readable ! -executable -size 1033c) | grep ASCII | tr ":" " " | awk '{print $1}')

从查找手册:

NON-BUGS         

   Operator precedence surprises
   The command find . -name afile -o -name bfile -print will never print
   afile because this is actually equivalent to find . -name afile -o \(
   -name bfile -a -print \).  Remember that the precedence of -a is
   higher than that of -o and when there is no operator specified
   between tests, -a is assumed.

   “paths must precede expression” error message
   $ find . -name *.c -print
   find: paths must precede expression
   Usage: find [-H] [-L] [-P] [-Olevel] [-D ... [path...] [expression]

   This happens because *.c has been expanded by the shell resulting in
   find actually receiving a command line like this:
   find . -name frcode.c locate.c word_io.c -print
   That command is of course not going to work.  Instead of doing things
   this way, you should enclose the pattern in quotes or escape the
   wildcard:
   $ find . -name '*.c' -print
   $ find . -name \*.c -print