我知道这是可行的:

function Foo() {};
Foo.prototype.talk = function () {
    alert('hello~\n');
};

var a = new Foo;
a.talk(); // 'hello~\n'

但如果我想打电话

Foo.talk() // this will not work
Foo.prototype.talk() // this works correctly

我找到了一些制作Foo的方法。谈工作,

Foo。__proto__ = Foo.prototype Foo。talk = Foo.prototype.talk

还有别的办法吗?我不知道这样做是否正确。在JavaScript代码中使用类方法还是静态方法?


当前回答

如果你必须在ES5中编写静态方法,我找到了一个很棒的教程:

//Constructor
var Person = function (name, age){
//private properties
var priv = {};

//Public properties
this.name = name;
this.age = age;

//Public methods
this.sayHi = function(){
    alert('hello');
}
}


// A static method; this method only 
// exists on the class and doesn't exist  
// on child objects
Person.sayName = function() {
   alert("I am a Person object ;)");  
};

看到@https: / / abdulapopoola.com/2013/03/30/static-and-instance-methods-in-javascript/

其他回答

静态方法调用是直接在类上进行的,不能在类的实例上调用。静态方法经常用于 创建效用函数

非常清晰的描述

直接取自mozilla.org

Foo需要绑定到你的类 然后当你创建一个新实例时,你可以调用myNewInstance.foo() 如果你导入你的类,你可以调用一个静态方法

Javascript没有实际的类,而是使用一个原型继承系统,其中对象通过原型链从其他对象“继承”。这最好通过代码本身来解释:

function Foo() {}; // creates a new function object Foo.prototype.talk = function () { console.log('hello~\n'); }; // put a new function (object) on the prototype (object) of the Foo function object var a = new Foo; // When foo is created using the new keyword it automatically has a reference // to the prototype property of the Foo function // We can show this with the following code console.log(Object.getPrototypeOf(a) === Foo.prototype); a.talk(); // 'hello~\n' // When the talk method is invoked it will first look on the object a for the talk method, // when this is not present it will look on the prototype of a (i.e. Foo.prototype) // When you want to call // Foo.talk(); // this will not work because you haven't put the talk() property on the Foo // function object. Rather it is located on the prototype property of Foo. // We could make it work like this: Foo.sayhi = function () { console.log('hello there'); }; Foo.sayhi(); // This works now. However it will not be present on the prototype chain // of objects we create out of Foo

在你的例子中,如果你想要Foo.talk():

function Foo() {};
// But use Foo.talk would be inefficient
Foo.talk = function () {
    alert('hello~\n');
};

Foo.talk(); // 'hello~\n'

但这是一种低效的实现方式,使用原型更好。


另一种方式,My way定义为静态类:

var Foo = new function() {
  this.talk = function () {
    alert('hello~\n');
    };
};

Foo.talk(); // 'hello~\n'

上面的静态类不需要使用原型,因为它只会被构造一次作为静态使用。

https://github.com/yidas/js-design-patterns/tree/master/class

另外,现在可以用类和静态来做

'use strict'

class Foo {
 static talk() {
     console.log('talk')
 };

 speak() {
     console.log('speak')
 };

};

将会给

var a = new Foo();
Foo.talk();  // 'talk'
a.talk();    // err 'is not a function'
a.speak();   // 'speak'
Foo.speak(); // err 'is not a function'

ES6现在支持类和静态关键字,就像一个魅力:

class Foo {
    constructor() {}

    talk() {
        console.log("i am not static");
    }

    static saying() {
        console.log(this.speech);
    }

    static get speech() {
        return "i am static method";
    }

}